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Round all masses to the 10ths place

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Step One: two atoms of iron and three of oxygen Step Two: Fe = 55.8 amu and O = 16.0 amu Step Three: (2 x 55.8) + (3 x 16.0) Step Four: = amu (grams) for one mole

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Step One: one atom of potassium, one of chlorine, and four of oxygen. Step Two: K = 39.1 amu, Cl = 35.5 amu, O = 16.0 amu Step Three: (1 x 39.1) + (1 x 35.5) + (4 x 16.0) Step Four: = amu (grams) for one mole

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Step One: two atoms of nitrogen, eight of hydrogen and one of sulfur Step Two: N = 14.0 amu, H = 1.0 amu, S = 32.1 amu Step Three: (2 x 14.0) + (8 x 1.0) + (1 x 32.1) Step Four: = 68.1 amu (grams) for one mole

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Calculate the molar mass of Al(NO 3 ) 3 Al(1 x 27.0) + N(3 x 14.0) + O(9 x 16.0) = amu (grams) is the mass of one mole of aluminum nitrate.

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1. AlCl 3 2. Ba(SCN) 2 3. LiH 4. Ba(BrO 3 ) 2 5. AlBr 3 6. HCl

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g/mol g/mol g/mol g/mol g/mol g/mol

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Round all final answers to 3 sig figs

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KMnO 4 = g / mole of KMnO 4 Now let’s solve it 25.0 g x 1 mole = moles g moles

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H 2 O 2 = 34.0 g / mole Now, let’s solve it 17.0 g x 1 mol H 2 O 2 = 0.5 moles 34.0 g moles

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Calculate the moles present in: 1) 2.00 grams of H 2 O 2) grams of KBr 3) 100. grams of KClO 4 4) 8.76 grams of NaOH 5) grams of Na 2 CO 3 Remember to round answers to 3 sig figs

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1)0.111 moles 2)0.635 moles 3) moles 4)0.219 moles 5) moles

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Round all answers to 3 sig figs

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H 2 O 2 molar mass = 34.0 grams/mole moles x 34.0 grams = 23.8 g 1 mole 23.8 grams

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KClO 3 molecular mass = g/mole 2.50 moles x g = grams 1 mole 307 grams

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Calculate the grams present in: 1) moles of H 2 S 2) moles of KI 3) moles of KClO 4) moles of NaOH 5) 3.40 x moles of Na 2 CO 3 Remember to round answer to 3 sig figs

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1)6.82 grams 2)16.6 grams 3)136 grams 4)30.0 grams 5) grams

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6.02 x particles = 1 mole Particles can mean atoms or molecules

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One mole of donuts contains 6.02 x donuts One mole of H 2 O contains 6.02 x molecules One mole of nails contains 6.02 x nails One mole of Fe contains 6.02 x atoms

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One mole of dogs contains 6.02 x dogs One mole of electrons contains 6.02 x electrons One mole of Chemistry students contains 6.02 x poor, suffering (I mean happy, joyful) high school students

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mole Fe x 6.02 x atoms 1 mole = 2.709x10 23 atoms Final, rounded answer: 2.71x10 23 atoms

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mole x 6.02 x atoms 1 mole = 1.204x10 23 atoms Final, rounded answer: 1.20x10 23 atoms

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1) Calculate the number of molecules in mole of H 2 O 2) Calculate the number of atoms in mole of Fe Remember to round to 3 sig figs

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1)6.37x10 23 molecules 2)4.52x10 23 atoms

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Grams to particles OR particles to grams Grams to atoms OR atoms to grams If MOLE is not stated, it’s a two step problem ROUND ALL ANSWERS TO 3 SIG FIGS

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g x 1 mole Fe x 6.02x10 23 atoms = 55.8 g 1 mole x10 21 atoms Final answer = 4.85x10 21 atoms

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H 2 O molecular mass = 18.0 g g x 1 mole H 2 O x 6.02x10 23 molecules 18.0 g 1 mole x10 21 molecules Final answer = 6.69x10 21 molecules

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1) Calculate the number of molecules in gram of H 2 O 2) Calculate the number of atoms in gram of Fe Remember to round answer to 3 sig figs

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1)3.54x10 22 molecules 2)8.10x10 21 atoms

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