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Round all masses to the 10ths place

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Step One: two atoms of iron and three of oxygen Step Two: Fe = 55.8 amu and O = 16.0 amu Step Three: (2 x 55.8) + (3 x 16.0) Step Four: 111.6 + 48.0 = 159.6 amu (grams) for one mole

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Step One: one atom of potassium, one of chlorine, and four of oxygen. Step Two: K = 39.1 amu, Cl = 35.5 amu, O = 16.0 amu Step Three: (1 x 39.1) + (1 x 35.5) + (4 x 16.0) Step Four: 39.1 + 35.5 + 64.0 = 138.6 amu (grams) for one mole

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Step One: two atoms of nitrogen, eight of hydrogen and one of sulfur Step Two: N = 14.0 amu, H = 1.0 amu, S = 32.1 amu Step Three: (2 x 14.0) + (8 x 1.0) + (1 x 32.1) Step Four: 28 + 8.0 + 32.1 = 68.1 amu (grams) for one mole

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Calculate the molar mass of Al(NO 3 ) 3 Al(1 x 27.0) + N(3 x 14.0) + O(9 x 16.0) = 213.0 amu (grams) is the mass of one mole of aluminum nitrate.

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1. AlCl 3 2. Ba(SCN) 2 3. LiH 4. Ba(BrO 3 ) 2 5. AlBr 3 6. HCl

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1. 133.5 g/mol 2. 253.5 g/mol 3. 7.9 g/mol 4. 393.1 g/mol 5. 266.7 g/mol 6. 36.5 g/mol

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Round all final answers to 3 sig figs

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KMnO 4 = 158.0 g / mole of KMnO 4 Now let’s solve it 25.0 g x 1 mole = 0.158191804 moles 158.0 g 0.158 moles

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H 2 O 2 = 34.0 g / mole Now, let’s solve it 17.0 g x 1 mol H 2 O 2 = 0.5 moles 34.0 g 0.500 moles

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Calculate the moles present in: 1) 2.00 grams of H 2 O 2) 75.57 grams of KBr 3) 100. grams of KClO 4 4) 8.76 grams of NaOH 5) 0.750 grams of Na 2 CO 3 Remember to round answers to 3 sig figs

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1)0.111 moles 2)0.635 moles 3) 0.722 moles 4)0.219 moles 5)0.00708 moles

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Round all answers to 3 sig figs

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H 2 O 2 molar mass = 34.0 grams/mole 0.700 moles x 34.0 grams = 23.8 g 1 mole 23.8 grams

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KClO 3 molecular mass = 122.6 g/mole 2.50 moles x 122.6 g = 306.5 grams 1 mole 307 grams

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Calculate the grams present in: 1) 0.200 moles of H 2 S 2) 0.100 moles of KI 3) 1.500 moles of KClO 4) 0.750 moles of NaOH 5) 3.40 x 10 -5 moles of Na 2 CO 3 Remember to round answer to 3 sig figs

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1)6.82 grams 2)16.6 grams 3)136 grams 4)30.0 grams 5)0.00360 grams

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6.02 x 10 23 particles = 1 mole Particles can mean atoms or molecules

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One mole of donuts contains 6.02 x 10 23 donuts One mole of H 2 O contains 6.02 x 10 23 molecules One mole of nails contains 6.02 x 10 23 nails One mole of Fe contains 6.02 x 10 23 atoms

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One mole of dogs contains 6.02 x 10 23 dogs One mole of electrons contains 6.02 x 10 23 electrons One mole of Chemistry students contains 6.02 x 10 23 poor, suffering (I mean happy, joyful) high school students

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0.450 mole Fe x 6.02 x 10 23 atoms 1 mole = 2.709x10 23 atoms Final, rounded answer: 2.71x10 23 atoms

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0.200 mole x 6.02 x 10 23 atoms 1 mole = 1.204x10 23 atoms Final, rounded answer: 1.20x10 23 atoms

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1) Calculate the number of molecules in 1.058 mole of H 2 O 2) Calculate the number of atoms in 0.750 mole of Fe Remember to round to 3 sig figs

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1)6.37x10 23 molecules 2)4.52x10 23 atoms

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Grams to particles OR particles to grams Grams to atoms OR atoms to grams If MOLE is not stated, it’s a two step problem ROUND ALL ANSWERS TO 3 SIG FIGS

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0.450 g x 1 mole Fe x 6.02x10 23 atoms = 55.8 g 1 mole 4.8548387x10 21 atoms Final answer = 4.85x10 21 atoms

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H 2 O molecular mass = 18.0 g 0.200 g x 1 mole H 2 O x 6.02x10 23 molecules 18.0 g 1 mole 6.6888888889x10 21 molecules Final answer = 6.69x10 21 molecules

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1) Calculate the number of molecules in 1.058 gram of H 2 O 2) Calculate the number of atoms in 0.750 gram of Fe Remember to round answer to 3 sig figs

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1)3.54x10 22 molecules 2)8.10x10 21 atoms

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