# Equilibrium 1994A Teddy Ku. 1994 A MgF 2(s) Mg 2+ (aq) + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+

## Presentation on theme: "Equilibrium 1994A Teddy Ku. 1994 A MgF 2(s) Mg 2+ (aq) + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+"— Presentation transcript:

Equilibrium 1994A Teddy Ku

1994 A MgF 2(s) Mg 2+ (aq) + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+ is 1.21x10 3 molar. The equilibrium is represented by the equation above. a)Write the expression for the solubility-product constant, K sp, and calculate its value at 18 degrees Celsius.  K sp = [Mg 2+ ] [F - ] 2  [F - ] = 2(1.21x10 -3 )  K sp = (1.21x10 -3 )(2.42x10 -3 ) 2 = 7.09x10 -9

1994 A MgF 2 (s) Mg 2+ (aq) + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+ is 1.21x10 3 molar. The equilibrium is represented by the equation above. b)Calculate the equilibrium concentration of Mg 2+ in 1.000 liter of saturated MgF 2 solution at 18 degrees Celsius to which.100 mole of solid KF has been added. The KF dissolves completely. Assume the volume change is negligible. MgF 2 (s) Mg 2+ (aq) + 2F - (aq) Initial (M) Change (M) Equilibrium (M) 0 1.21x10 -3 0 -x-x 0 1.21x10 -3 - x 2.42x10 -3 +.100 -2x 2.42x10 -3 +.100 - 2x K c = [Mg 2+ ] [F-] 2 = (1.21x10 -3 - x)(2.42x10 -3 +.100 - 2x) 2 = 7.09x10 -9 Solve for x on calculator X= 1.20929x10 -3 [Mg 2+ ] = 1.21x10 -3 + x = 2.42x10 -3

1994 A MgF 2 (s) Mg 2+ + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+ is 1.21x10 3 molar. The equilibrium is represented by the equation above. c)Predict whether a precipitate of MgF 2 will form when 100.0 milliliters of a 3.00x10 -3 molar Mg(NO 3 ) 2 solution is mixed with 200.0 milliliters of a 2.00x10 -3 molar NaF solution at 18 degrees Celsius. Calculations to support your prediction must be shown. Set up the equilibrium law and calculate (did in a) –Ksp=7.09x10 9 Calculate ion product –(3.00x10 -3 )(2.00x10 -3 ) 2 =1.2x10 -8 Compare ion product with K sp –If the ion product > Ksp, the solution is supersaturated, and precipitate will form. –If the ion product is < or = to the Ksp, no precipitate will form. –1.2x10 -8 < 7.09x10 9 No precipitate

1994 A MgF 2 (s) Mg 2+ + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg2+ is 1.21x10 3 molar. The equilibrium is represented by the equation above. d)At 27 degrees the concentration of Mg 2+ in a saturated solution of MgF 2 is 1.17x10 -3 molar. Is the dissolving of MgF 2 in water an endothermic or an exothermic process? Give an explanation to support your conclusion Equilibrium shifts to the left when temperature increases –Heat must be a product Exothermic if heat is a product

Download ppt "Equilibrium 1994A Teddy Ku. 1994 A MgF 2(s) Mg 2+ (aq) + 2F - (aq) In a saturated solution of MgF 2 at 18 degrees Celsius, the concentration of Mg 2+"

Similar presentations