Download presentation

Presentation is loading. Please wait.

Published byCheyanne Garrick Modified about 1 year ago

1
Symmetry and the DTFT If we know a few things about the symmetry properties of the DTFT, it can make life simpler. First, for a real-valued sequence x(n), the amplitude spectrum (magnitude of the DTFT) is an EVEN function of . To show this first show that,

2
Symmetry and the DTFT But we’ve assumed that x(n) is a real sequence, so and the relationship is proven

3
Symmetry and the DTFT The amplitude spectrum is If is replaced by – , th amplitude spectrum is unchanged. X(e j ) = X(e -j ), so the amplitude spectrum is an even function of .

4
Symmetry and the DTFT The phase function is For this to be an odd function of , the imaginary part must be odd and the real part must be even. By euler’s formula,

5
Symmetry and the DTFT Since cos( n) = cos(- n), Re(X(e j )) is an even function of . Likewise, since sin( n) = -sin(- n), Im(X(e j )) is an even function of . Therefore, it is shown that the phase function is an odd function of :

6
Symmetry and the DTFT Suppose x(n) has even symmetry about the origin: Then Which means that X(e j ) is a real-valued function

7
Periodicity and the DTFT The DTFT is a periodic function of , with period = 2 So the frequency response function and all other DTFT’s are periodic. One period of a DTFT completely describes the function for all values of so it Is usually plotted only for the interval [- ]

8
Periodicity and the DTFT If x(n) is a real-valued sequence, the amplitude spectrum is an even function of , AND periodic. Therefore, it is completely described by the interval [0, ]. Since the phase function is an odd function, it is also completely described by the interval [0, ]. Since the phase function is an odd function, it is also completely described by the interval [0, ].

9
DTFT of a Sinusoid Suppose x(n) is the complex exponential, e j n This delta function is the Dirac (continuous time) delta function, so it has the sifting property. Taking the inverse DTFT,

10
DTFT of a Sinusoid So the complex exponential sequenc looks like this in the frequency domain:

11
DTFT of a Sinusoid If x(n) is a sinusoid:

12
DTFT of a Sinusoid So the DTFT of a sinusoid is a pair of impulses int the frequency domain, at the positive and negative frequency of the sinusoid, then repeated every 2 radians per sample

13
The DTFT and the Fourier Transform Suppose we have a continuous time signal x a (t), and its Fourier transform: We sample x a (t) at a sampling frequency f s, creating a discrete time signal (a sequence): This sequence has a spectrum (DTFT):

14
The DTFT and the Fourier Transform I will state the following relationship now, without proof. The proof comes later: In other words, whatever the continuous time spectrum is, the spectrum of the discrete time signal obtained by sampling has the same shape, but it is periodic in frequency with period = f s

15
The DTFT and the Fourier Transform If the continuous time signal has this spectrum X a (f) f Then the discrete time signal (sequence) has this spectrum: X(e j2 f ) f 0fsfs 2f s -2f s -f s 0fsfs 2f s -2f s -f s

16
The DTFT and the Fourier Transform X a (f) f 0fsfs 2f s -2f s -f s If the continuous time signal is bandlimited (has no significant spectral content above some frequency f=B), Then the sequence obtained by sampling the continuous time signal looks like this in the frequency domain: B-B

17
The DTFT and the Fourier Transform X(e j2 f ) f 0fsfs 2f s -2f s -f s B-B As long as f s > 2B, no problem. But if f s < 2B, it looks like this: X(e j2 f ) f 0fsfs 2f s -2f s -f s B-B -3f s -4f s 3f s 4f s

18
The DTFT and the Fourier Transform Note that the spectral replicas created by sampling overlap X(e j2 f ) f 0fsfs 2f s -2f s -f s B-B -3f s -4f s 3f s 4f s This is called aliasing To avoid aliasing, the minimum sample frequency is given by the Nyquist criterion:

19
The DTFT and the Fourier Transform And the minimum sampling frequency is called the Nyquist frequency or Nyquist rate. If the Nyquist criterion is met, the original continuous time signal x a (t) can be completely recovered from the sequence x(n) by an ideal digital to analog converter.

20
The DTFT and the Fourier Transform To make sure the Nyquist criterion is met, the signal should pass through an antialiasing filter before it is sampled by the analog to digital converter (ADC): Antiasing FilterADCx a (t)x(n) The antialising filter must be designed to cut off any spectral content above ½ the sampling frequency.

Similar presentations

© 2016 SlidePlayer.com Inc.

All rights reserved.

Ads by Google