Download presentation

Presentation is loading. Please wait.

Published byJanae Dearth Modified about 1 year ago

1
3 February 2004K. A. Connor RPI ECSE Department 1 Smith Chart Supplemental Information Fields and Waves I ECSE 2100

2
3 February 2004K. A. Connor RPI ECSE Department 2 Smith Chart Impedances, voltages, currents, etc. all repeat every half wavelength The magnitude of the reflection coefficient, the standing wave ratio (SWR) do not change, so they characterize the voltage & current patterns on the line If the load impedance is normalized by the characteristic impedance of the line, the voltages, currents, impedances, etc. all still have the same properties, but the results can be generalized to any line with the same normalized impedances

3
3 February 2004K. A. Connor RPI ECSE Department 3 Smith Chart The Smith Chart is a clever tool for analyzing transmission lines The outside of the chart shows location on the line in wavelengths The combination of intersecting circles inside the chart allow us to locate the normalized impedance and then to find the impedance anywhere on the line

4
3 February 2004K. A. Connor RPI ECSE Department 4 Smith Chart Real Impedance Axis Imaginary Impedance Axis

5
3 February 2004K. A. Connor RPI ECSE Department 5 Smith Chart Constant Imaginary Impedance Lines Constant Real Impedance Circles Impedance Z=R+jX =100+j50 Normalized z=2+j for Z o =50

6
3 February 2004K. A. Connor RPI ECSE Department 6 Smith Chart Impedance divided by line impedance (50 Ohms) Z1 = j50 Z2 = 75 -j100 Z3 = j200 Z4 = 150 Z5 = infinity (an open circuit) Z6 = 0 (a short circuit) Z7 = 50 Z8 = 184 -j900 Then, normalize and plot. The points are plotted as follows: z1 = 2 + j z2 = 1.5 -j2 z3 = j4 z4 = 3 z5 = infinity z6 = 0 z7 = 1 z8 = j18S

7
3 February 2004K. A. Connor RPI ECSE Department 7 Smith Chart Thus, the first step in analyzing a transmission line is to locate the normalized load impedance on the chart Next, a circle is drawn that represents the reflection coefficient or SWR. The center of the circle is the center of the chart. The circle passes through the normalized load impedance Any point on the line is found on this circle. Rotate clockwise to move toward the generator (away from the load) The distance moved on the line is indicated on the outside of the chart in wavelengths

8
3 February 2004K. A. Connor RPI ECSE Department 8 Toward Generator Away From Generator Constant Reflection Coefficient Circle Scale in Wavelengths Full Circle is One Half Wavelength Since Everything Repeats

9
3 February 2004K. A. Connor RPI ECSE Department 9 Smith Chart References ic.com/appnotes.cfm/appnote_number/742/http://www.maxim- ic.com/appnotes.cfm/appnote_number/742/ e%2004.pdfhttp://www.ece.uvic.ca/~whoefer/elec454/Lectur e%2004.pdf TENT_ID=2482 to download applethttp://www.educatorscorner.com/index.cgi?CON TENT_ID=2482 Two examples from this page are shown in the following slideshttp://www.amanogawa.com/index.html

10
3 February 2004K. A. Connor RPI ECSE Department 10 Smith Chart Example First, locate the normalized impedance on the chart for Z L = 50 + j100 Then draw the circle through the point The circle gives us the reflection coefficient (the radius of the circle) which can be read from the scale at the bottom of most charts Also note that exactly opposite to the normalized load is its admittance. Thus, the chart can also be used to find the admittance. We use this fact in stub matching

11
3 February 2004K. A. Connor RPI ECSE Department 11

12
3 February 2004K. A. Connor RPI ECSE Department 12 Note – the cursor is at the load location

13
3 February 2004K. A. Connor RPI ECSE Department 13 Single Stub Matching (as in Homework) Load of j100 Ohms on 50 Ohm Transmission Line The frequency is 1 GHz = 1x10 9 Hz Want to place an open circuit stub somewhere on the line to match the load to the line, at least as well as possible. The steps are well described at First the line and load are specified. Then the step by step procedure is followed to locate the open circuit stub to match the line to the load

14
3 February 2004K. A. Connor RPI ECSE Department 14

15
3 February 2004K. A. Connor RPI ECSE Department 15

16
3 February 2004K. A. Connor RPI ECSE Department 16

17
3 February 2004K. A. Connor RPI ECSE Department 17

18
3 February 2004K. A. Connor RPI ECSE Department 18

19
3 February 2004K. A. Connor RPI ECSE Department 19

20
3 February 2004K. A. Connor RPI ECSE Department 20

21
3 February 2004K. A. Connor RPI ECSE Department 21 Smith Chart Now the line is matched to the left of the stub because the normalized impedance and admittance are equal to 1 Note that the point on the Smith Chart where the line is matched is in the center (normalized z=1) where also the reflection coefficient circle has zero radius or the reflection coefficient is zero. Thus, the goal with the matching problem is to add an impedance so that the total impedance is the characteristic impedance

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google