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Published byStephan Purinton Modified about 1 year ago

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1 3. Process Flow Measures Three Sequential Operations; One Oven Operation AOperation BOperation C You Oven Friend 15 Time (minutes) Capacity (per hour) 205 =60/15 = 4 =60/20 = 3 =60/5 = 12 Throughput Time 15+20+5 = 40 Process Capacity = 3 You also need to subtract 40 minutes from your overall available time because it takes you 40 minutes to produce the first unit. Therefore id you have 4×60 minutes. It will take 40 minutes to produce 1, and then in the remaining time which is 240-40 = 200 you will produce 1 unit per 20 minuts, i.e. 3 units per hour. And a total capacity of 1+1+3*3= 11 per 4 hours

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2 3. Process Flow Measures Two Ovens Operation AOperation BOperation C You Oven Friend 15 Time (minutes) Capacity (per hour) 205 =60/15 = 4 = 2×60/20 = 6 =60/5 = 12 Throughput Time 15+20+5 = 40 Process Capacity = 4

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3 3. Process Flow Measures Two Ovens Plus Cross Functional Workers Operation AOperation BOperation C Human Oven Human 15 Time (minutes) 205 Resource Human Oven Time 5+1520 Capacity 2*60/20 =6120/20 =6

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4 3. Process Flow Measures Flow Time; Parallel Tasks A B C D 2 2 4 1 TT = 2+2+4+1 = 9 A B C D 2 2 4 1 TT = 2+(max(2,4))+1 = 7 M1H1 H2M2 H1 H2 M2 M1 Capacity M1 =30, H1=30, H2=15, M2=60

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5 3. Process Flow Measures Christine, Roommate, Mixer, and Oven ResourceChristine RoomateMixerOven Time84610 Capacity60/8 =7.560/4=1560/6=1060/10 = 6

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6 3. Process Flow Measures Two Ovens ResourceChristine RoomateMixerOven Time84610 Capacity60/8 =7.560/4=1560/6=10120/10 =12

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7 3. Process Flow Measures Cross Functional Workers ResourceHuman MixerOven Time8+4610 Capacity120/12 =1060/6=10120/10 =12

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8 3. Process Flow Measures Parallel Operations A B C D 2 2 4 1 TT = 2+(max(2,4))+1 = 7 H H M2 M1 Capacity A =30, B=30, C=15, D=60

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9 3. Process Flow Measures Partitioning the Task to do it In Paralell A B C1 D 2 2 3 1 TT = 2+(max(3,3))+1 = 6 H H M2 M1 Capacity A =30, B=20, C=20, D=60 C2 1 H

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