Download presentation

Presentation is loading. Please wait.

Published byZane Baulch Modified over 3 years ago

1
Computer Architecture Vector Architectures Ola Flygt Växjö University http://w3.msi.vxu.se/users/ofl/ Ola.Flygt@msi.vxu.se +46 470 70 86 49

2
Outline Introduction Basic priciples Sd Examples Cray xcx CH01

3
Scalar processing 4n clock cycles required to process n elements! Timeop 0a0a0 4a1a1 8a2a2 …… 4nanan

4
Pipelining 4n/(4+n) clock cycles required to process n elements! Timeop 0 op 1 op 2 op 3 0a0a0 1a1a1 a0a0 2a2a2 a1a1 a0a0 3a3a3 a2a2 a1a1 a0a0 4a4a4 a3a3 a2a2 a1a1 …………… nanan a n-1 a n-2 a n-3

5
Pipeline Basic Principle Stream of objects Number of objects = stream length n Operation can be subdivided into sequence of steps Number of steps = pipeline length p Advantage Speedup = pn/(p+n) Stream length >> pipeline length Speedup approx.p Speedup is limited by pipeline length!

6
Vector Operations Operations on vectors of data (floating point numbers) Vector-vector V1 <-V2 + V3 (component-wise sum) V1 <-- V2 Vector-scalar V1 <-c * V2 Vector-memory V <-A (vector load) A <-V (vector store) Vector reduction c <-min(V) c <-sum(V) c <-V1 * V2 (dot product)

7
Vector Operations, cont. Gather/scatter V1,V2 <-GATHER(A) load all non-zero elements of A into V1 and their indices into V2 A <-SCATTER(V1,V2) store elements of V1 into A at indices denoted by V2 and fill rest with zeros Mask V1 <-MASK(V2,V3) store elements of V2 into V1 for which corresponding position in V3 is non-zero

8
Example, Scalar Loop approx. 6n clock cycles to execute loop. Fortran loop: DO I=1,N A(I) = A(I)+B(I) ENDDO Scalar assembly code: R0 <- N R1 <- I JMP J L: R2 <- A(R1) R3 <- B(R1) R2 <- R2+R3 A(R1) <- R2 R1 <- R1+1 J: JLE R1, R0, L

9
Example, Vector Loop 4n clock cycles, because no loop iteration overhead (ignoring speedup by pipelining) Fortran loop: DO I=1,N A(I) = A(I)+B(I) ENDDO Vectorized assembly code: V1 <- A V2 <- B V3 <- V1+V2 A <- V2

10
Chaining Overlapping of vector instructions (see Hwang, Figure 8.18) Hence: c+n ticks (for small c) Speedup approx.6 (c=16, n=128, s=(6*128)/(16+128)=5.33) The longer the vector chain, the better the speedup! A <-B*C+D chaining degree 5 Vectorization speedups between 5 and 25

11
Vector Programming How to generate vectorized code? 1. Assembly programming. 2. Vectorized Libraries. 3. High-level vector statements. 4. Vectorizing compiler.

12
Vectorized Libraries Predefined vector operations (partially implemented in assembly language) VECLIB, LINPACK, EISPACK, MINPACK C = SSUM(100, A(1,2), 1, B(3,1), N) 100...vector length A(1,2)...vector address A 1...vector stride A B(3,1)...vector address B N...vector stride B Addition of matrix column to matrix row.

13
High-Level Vector Statements e.g. Fortran 90 INTEGER A(100), B(100), C(100), S A(1:100) = S*B(1:100)+C(1:100) * Vector-vector operations. * Vector-scalar operations. * Vector reduction. *... Easy transformation into vector code.

14
Vectorizing Compiler 1. Fortran 77 DO Loop * DO I=1, N D(I) = A(I)*B+C(I) ENDDO 2. Vectorization * D(1:N) = A(1:N)*B+C(1:N) 3. Strip mining * DO I=1, N/128 D(I:I+127) = A(I:I+127)*B + C(I:I+127) ENDDO IF ((N.MOD.128).NEQ.0) A((N/128)*128+1:N) =... ENDIF 4. Code generation * V0 <- V0*B... Related techniques for parallelizing compiler!

15
Vectorization In which cases can loop be vectorized? DO I = 1, N-1 A(I) = A(I+1)*B(I) ENDDO | V A(1:128) = A(2:129)*B(1:128) A(129:256) = A(130:257)*B(129:256).... Vectorization preserves semantics.

16
Loop Vectorization s semantics always preserved? DO I = 2, N A(I) = A(I-1)*B(I) ENDDO | V A(2:129) = A(1:128)*B(2:129) A(130:257) = A(129:256)*B(130:257).... Vectorization has changed semantics!

17
Vectorization Inhibitors Vectorization must be conservative; when in doubt, loop must not be vectorized. Vectorization is inhibited by Function calls Input/output operations GOTOs into or out of loop Recurrences (References to vector elements modified in previous iterations)

18
Components of a vectorizing supercomputer

19
The DS for floating-point precision

20
The DS for integer precision

21
How vectorization works Un-vectorized computation

22
How vectorization works vectorized computation

23
How vectorization speeds up computation

24
Speed improvements Non-pipelined computation

25
Speed improvements pipelined computation

26
Increasing the granularity of a pipeline Repetition governed by slowest component

27
Increasing the granularity of a pipeline Granularity increased to improve repetition

28
Parallel computation of floating point and integer results

29
Mixed functional and data parallelism

30
The DS for parallel computational functionality

31
Performance of four generations of Cray systems

32
Communication between CPUs and memory

33
The increasing complexity in Cray systems

34
Integration density

35
Convex C4/XA system

36
The configuration of the crossbar switch

37
The processor configuration

Similar presentations

OK

CSCE 212 Quiz 9a – 4/1/11 For the following questions, assume the clock cycle times given above and the following set of instructions: lw $5, -16($5) sw.

CSCE 212 Quiz 9a – 4/1/11 For the following questions, assume the clock cycle times given above and the following set of instructions: lw $5, -16($5) sw.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google