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Operator Overloading

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C++ 2 Outline General technique Overloading of the assignment operator Overloading the increment and decrement operators

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C++ 3 General Technique In the case of our MyVector class, if v1 and v2 are two vectors, then the sum of them can be printed out with the following statement: v1.Sum(v2).Display(); But we would like to do this, by using the form: cout << v1 + v2; Thus, we have to overload the << and + operators.

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C++ 4 General Rules There is no way to define new operators, just the existing ones can be overloaded. There are some operators which cannot be overloaded, like the scope operator (::), and the member selection operator (.). There is no possibility to change the nature of an operator (binary or unary, and associativity).

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C++ 5 How to Overload an Operator? Define a special member function (or friend function). The name of the function is composed of the operator keyword, and the respective operator.

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C++ 6 The Class Declaration class MyVector { private: int *elem; int dim; public: MyVector(int *e, int d); MyVector(const MyVector & v); ~MyVector(); void SquareVect(); MyVector operator +(MyVector & v); ostream& Display(ostream & s) const; };

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C++ 7 The + Operator MyVector MyVector::operator +(MyVector & v) { if (dim != v.dim) throw "Different size"; int* x = new int[dim];

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C++ 8 The + Operator for(int i = 0; i < dim; i++) x[i] = elem[i] + v.elem[i]; MyVector t(x, dim); delete [] x; return t; }

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C++ 9 The Display Member Function ostream & MyVector::Display(ostream & s) const { for(int i = 0; i < dim; i++) s << elem[i] << '\t'; return s << endl; }

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C++ 10 The Inserter Operator ostream& operator << (ostream & s, const MyVector & v) { return v.Display(s); }

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C++ 11 The main Function int main() { int x[]={1, 2, 3, 4, 5}; MyVector v1(x, 5); int y[]={2, 4, 6, 8, 10}; MyVector v2(y, 5); cout << v1+v2; }

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C++ 12 Overloading of the Assignment Operator By default a member-wise assignment is defined. Generally this gives good results if there are no pointer data members. In other case we should overload the assignment operator.

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C++ 13 Example 1 (No Assignment Operator Needed) #include using namespace std; class Fraction { int numerator; int denominator; public: Fraction(int a = 0, int b = 1); Fraction operator *(Fraction& r); ostream& Display(ostream &s); };

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C++ 14 Constructor Fraction::Fraction(int a, int b) { numerator = a; denominator = b; }

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C++ 15 The * operator Fraction Fraction::operator *(Fraction& r) { return Fraction(numerator * r.numerator, denominator * r.denominator); }

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C++ 16 The Display Member Function ostream& Fraction::Display(ostream &s) { return s << numerator << " / " << denominator; }

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C++ 17 The << operator ostream& operator <<(ostream& s, Fraction & t) { return t.Display(s); }

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C++ 18 The main Function int main() { Fraction x(3, 5); Fraction y(2, 7); Fraction z; z = x * y;// OK. No error cout << z;// Result: 6 / 36 }

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C++ 19 Example 2 MyVector has a data member (elem), which is a pointer, thus we must overload the assignment operator. In other case, the assignment v2 = v1; leads to a running-time error.

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C++ 20 The Error in Visual C++

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C++ 21 The MyVector Class class MyVector { private: int *elem; int dim; public: MyVector(int *e, int d); MyVector(const MyVector & v); ~MyVector(); void SquareVect(); MyVector operator +(MyVector & v); MyVector& operator =(const MyVector& v); ostream& Display(ostream & s) const; };

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C++ 22 The Assignment Operator MyVector& MyVector::operator =(const MyVector& v) { if (this != &v) { delete[] elem; dim = v.dim; elem = new int[dim]; for(int i = 0; i < dim; i++) elem[i] = v.elem[i]; } return *this; }

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C++ 23 The main Function int main() { int x[]={1, 2, 3, 4, 5}; MyVector v1(x, 5); int y[]={2, 4, 6, 8, 10}; MyVector v2(y, 5); cout << v1+v2; v2 = v1; cout << v2; }

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C++ 24 Output

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C++ 25 Other Assignment Operators All op= operators can be overloaded, where op is a binary arithmetical or bitwise operator. By default these operators are not overloaded. If op is already overloaded, then we can use it, and the current object can be accessed in the form: *this.

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C++ 26 The MyVector Class class MyVector { private: int *elem; int dim; public: MyVector(int *e, int d); MyVector(const MyVector & v);

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C++ 27 The MyVector Class ~MyVector(); void SquareVect(); MyVector operator +(const MyVector & v); MyVector& operator =(const MyVector& v); MyVector& operator +=(const MyVector& v); ostream& Display(ostream & s) const; };

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C++ 28 The += operator MyVector& MyVector::operator +=(const MyVector& v) { return *this = *this + v; } Because the formal parameter v is declared as const we must have the same in case of the + operator.

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C++ 29 If there is no const If this is not the case, then we can define the += operator in the following form: MyVector& MyVector::operator +=(const MyVector& v) { return *this = *this + const_cast (v); }

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C++ 30 The main Function int main() { int x[]={1, 2, 3, 4, 5}; MyVector v1(x, 5); int y[]={2, 4, 6, 8, 10}; MyVector v2(y, 5); v2 += v1; cout << v2; }

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C++ 31 The Copy Constructor and the Assignment Operator MyVector v2(v1);// copy constructor MyVector v2 = v1;// copy constructor MyVector v2; // default constructor v2 = v1; // assignment operator

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C++ 32 Overloading the Increment and Decrement Operators pre increment post increment pre decrement post decrement

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C++ 33 Example #include using namespace std; class Fraction { int numerator; int denominator; public:

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C++ 34 Example Fraction(int a = 0, int b = 1); Fraction operator *(Fraction& r); Fraction& operator ++(); // pre increment Fraction operator ++( int ); // post increment ostream& Display(ostream &s); };

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C++ 35 Constructor Fraction::Fraction(int a, int b) { numerator = a; denominator = b; }

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C++ 36 Pre Increment Operator Fraction& Fraction::operator ++() { numerator += denominator; return *this; }

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C++ 37 Post Increment Operator Fraction Fraction::operator ++( int ) { Fraction t(numerator, denominator); numerator += denominator; return t; }

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C++ 38 The main Function int main() { Fraction x(3, 4); Fraction y(3, 4); Fraction z; z = x++; cout << "z = " << z << endl; cout << "x = " << x << endl; z = ++y; cout << "z = " << z << endl; cout << "y = " << y << endl; }

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C++ 39 Output z = 3 / 4 x = 7 / 4 z = 7 / 4 y = 7 / 4

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