Presentation is loading. Please wait.

Presentation is loading. Please wait.

COP-5725 PRACTICE EXERCISES Chapter 5: Queries, Triggers, Constraints (up to, but not including aggregation) M. Amanda Crick.

Similar presentations


Presentation on theme: "COP-5725 PRACTICE EXERCISES Chapter 5: Queries, Triggers, Constraints (up to, but not including aggregation) M. Amanda Crick."— Presentation transcript:

1 COP-5725 PRACTICE EXERCISES Chapter 5: Queries, Triggers, Constraints (up to, but not including aggregation) M. Amanda Crick

2 Exercise 5.2 Problem  Consider the following schema  Suppliers(sid: integer, sname: string, address: string)  Parts(pid: integer, pname: string, color: string)  Catalog(sid: integer, pid: integer, cost: real)  The Catalog relation lists the prices charged for parts by Suppliers. Write the following queries in SQL:

3 Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) 1. Find the pnames of parts for which there is some supplier.

4 Exercise 5.2 Solution for (1) SELECT DISTINCT P.pname FROM Parts P, Catalog C WHERE P.pid = C.pid

5 Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) 4. Find the pnames of parts supplied by Acme Widget Suppliers and no one else.

6 Exercise 5.2 Solution for (4) SELECT P.pname FROM Parts P, Catalog C, Suppliers S WHERE P.pid = C.pid AND C.sid = S.sid AND S.sname = ‘Acme Widget Suppliers’ AND NOT EXISTS ( SELECT * FROM Catalog C1, Suppliers S1 WHERE P.pid = C1.pid AND C1.sid = S1.sid AND S1.sname <> ‘Acme Widget Suppliers’ )

7 Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) 6. For each part, find the sname of the supplier who charges the most for that part.

8 Exercise 5.2 Solution for (6) SELECT P.pid, S.sname FROM Parts P, Suppliers S, Catalog C WHERE C.pid = P.pid AND C.sid = S.sid AND C.cost >= ALL (SELECT C1.cost) FROM Catalog C1 WHERE C1.pid = P.pid)

9 Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) 8. Find the sids of suppliers who supply a red part and a green part.

10 Exercise 5.2 Solution for (8) SELECT DISTINCT C.sid FROM Catalog C, Parts P WHERE C.pid = P.pid AND P.color = ‘Red’ INTERSECT SELECT DISTINCT C1.sid FROM Catalog C1, Parts P1 WHERE C1.pid = P1.pid AND P1.color = ‘Green’

11 Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) 9. Find the sids of suppliers who supply a red part or a green part.

12 Exercise 5.2 Solution for (9) SELECT DISTINCT C.sid FROM Catalog C, Parts P WHERE C.pid = P.pid AND P.color = ‘Red’ UNION SELECT DISTINCT C1.sid FROM Catalog C1, Parts P1 WHERE C1.pid = P1.pid AND P1.color = ‘Green’

13 Exercise 5.4 Problem  Consider the following relational schema. An employee can work in more than one department; the pct_time field of the Works relation shows the percentage of time that a given employee works in a given department.  Emp(eid: integer, ename: string, age: integer, salary: real)  Works(eid: integer, did: integer, pct_time: integer)  Dept(did: integer, dname: string, budget: real, managerid: integer)  Write the following queries in SQL:

14 Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) 1. Print the names and ages of each employee who works in both the Hardware department and the Software department.

15 Exercise 5.4 Solution for (1) SELECT E.ename, E.age FROM Emp E, Works W1, Works W2, Dept D1, Dept D2 WHERE E.eid = W1.eid AND W1.did = D1.did AND D1.dname = ‘Hardware’ AND E.eid = W2.eid AND W2.did = D2.did AND D2.dname = ‘Software’

16 Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) 3. Print the name of each employee whose salary exceeds the budget of all of the departments that he or she works in.

17 Exercise 5.4 Solution for (3) SELECT E.ename FROM Emp E WHERE E.salary > ALL (SELECT D.budget FROM Dept D, Works W WHERE E.eid = W.eid AND D.did = W.did)

18 Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) 5. Find the enames of managers who manage the departments with the largest budgets.

19 Exercise 5.4 Solution for (5) SELECT E.ename FROM Emp E WHERE E.eid IN (SELECT D.managerid FROM Dept D WHERE D.budget >= ALL (SELECT D2.budget FROM Dept D2))

20 Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) 8. Find the enames of managers who manage the departments with the largest budgets.

21 Exercise 5.4 Solution for (8) SELECT M.ename FROM Emp M WHERE M.sid IN (SELECT M2.sid FROM Emp M2, Dept D WHERE M2.sid = D.managerid AND D.budget < EXCEPT SELECT M3.sid FROM Emp M3, Dept D2 WHERE M3.sid = D2.managerid AND D2.budget <= )

22 This is the end of the lecture! I hope you enjoyed it.


Download ppt "COP-5725 PRACTICE EXERCISES Chapter 5: Queries, Triggers, Constraints (up to, but not including aggregation) M. Amanda Crick."

Similar presentations


Ads by Google