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**COP-5725 Practice Exercises**

Chapter 5: Queries, Triggers, Constraints (up to, but not including aggregation) M. Amanda Crick

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**Exercise 5.2 Problem Consider the following schema**

Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) The Catalog relation lists the prices charged for parts by Suppliers. Write the following queries in SQL:

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Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) Find the pnames of parts for which there is some supplier.

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**Exercise 5.2 Solution for (1) SELECT DISTINCT P.pname**

FROM Parts P, Catalog C WHERE P.pid = C.pid

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Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) Find the pnames of parts supplied by Acme Widget Suppliers and no one else.

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**Exercise 5.2 Solution for (4) SELECT P.pname**

FROM Parts P, Catalog C, Suppliers S WHERE P.pid = C.pid AND C.sid = S.sid AND S.sname = ‘Acme Widget Suppliers’ AND NOT EXISTS ( SELECT * FROM Catalog C1, Suppliers S1 WHERE P.pid = C1.pid AND C1.sid = S1.sid AND S1.sname <> ‘Acme Widget Suppliers’ )

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Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) For each part, find the sname of the supplier who charges the most for that part.

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**Exercise 5.2 Solution for (6) SELECT P.pid, S.sname**

FROM Parts P, Suppliers S, Catalog C WHERE C.pid = P.pid AND C.sid = S.sid AND C.cost >= ALL (SELECT C1.cost) FROM Catalog C1 WHERE C1.pid = P.pid)

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Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) Find the sids of suppliers who supply a red part and a green part.

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**Exercise 5.2 Solution for (8) SELECT DISTINCT C.sid**

FROM Catalog C, Parts P WHERE C.pid = P.pid AND P.color = ‘Red’ INTERSECT SELECT DISTINCT C1.sid FROM Catalog C1, Parts P1 WHERE C1.pid = P1.pid AND P1.color = ‘Green’

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Exercise 5.2 Problem Suppliers(sid: integer, sname: string, address: string) Parts(pid: integer, pname: string, color: string) Catalog(sid: integer, pid: integer, cost: real) Find the sids of suppliers who supply a red part or a green part.

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**Exercise 5.2 Solution for (9) SELECT DISTINCT C.sid**

FROM Catalog C, Parts P WHERE C.pid = P.pid AND P.color = ‘Red’ UNION SELECT DISTINCT C1.sid FROM Catalog C1, Parts P1 WHERE C1.pid = P1.pid AND P1.color = ‘Green’

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Exercise 5.4 Problem Consider the following relational schema. An employee can work in more than one department; the pct_time field of the Works relation shows the percentage of time that a given employee works in a given department. Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) Write the following queries in SQL:

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Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) Print the names and ages of each employee who works in both the Hardware department and the Software department.

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**Exercise 5.4 Solution for (1) SELECT E.ename, E.age**

FROM Emp E, Works W1, Works W2, Dept D1, Dept D2 WHERE E.eid = W1.eid AND W1.did = D1.did AND D1.dname = ‘Hardware’ AND E.eid = W2.eid AND W2.did = D2.did AND D2.dname = ‘Software’

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Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) Print the name of each employee whose salary exceeds the budget of all of the departments that he or she works in.

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**Exercise 5.4 Solution for (3) SELECT E.ename FROM Emp E**

WHERE E.salary > ALL (SELECT D.budget FROM Dept D, Works W WHERE E.eid = W.eid AND D.did = W.did)

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Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) Find the enames of managers who manage the departments with the largest budgets.

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**Exercise 5.4 Solution for (5) SELECT E.ename FROM Emp E**

WHERE E.eid IN (SELECT D.managerid FROM Dept D WHERE D.budget >= ALL (SELECT D2.budget FROM Dept D2))

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Exercise 5.4 Problem Emp(eid: integer, ename: string, age: integer, salary: real) Works(eid: integer, did: integer, pct_time: integer) Dept(did: integer, dname: string, budget: real, managerid: integer) Find the enames of managers who manage the departments with the largest budgets.

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**Exercise 5.4 Solution for (8) SELECT M.ename FROM Emp M**

WHERE M.sid IN (SELECT M2.sid FROM Emp M2, Dept D WHERE M2.sid = D.managerid AND D.budget < EXCEPT SELECT M3.sid FROM Emp M3, Dept D2 WHERE M3.sid = D2.managerid AND D2.budget <= )

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**This is the end of the lecture!**

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