Presentation on theme: "Genetic Algorithms (Evolutionary Computing) Genetic Algorithms are used to try to “evolve” the solution to a problem Generate prototype solutions called."— Presentation transcript:
Genetic Algorithms (Evolutionary Computing) Genetic Algorithms are used to try to “evolve” the solution to a problem Generate prototype solutions called chromosomes (individuals) Backpack problem as example: http://home.ksp.or.jp/csd/english/ga/gatrial/Ch9_A2_4.h tml All individuals form the population Generate new individuals by reproduction Use a fitness function to evaluate individuals Survival of the fittest: population has a fixed size Individuals with higher fitness is more likely to reproduce
Reproduction Methods Mutation Alter a single gene in the chromosome randomly to create a new chromosome Example Cross-over Pick a random location within chromosome New chromosome receives first set of genes from parent 1, second set from parent 2 Example Inversion Reverse the chromsome
Interpretation Genetic algorithms try to solve a hill climbing problem Method is parallelizable The trick is in how you represent the chromosome Tries to avoid local maxima by keeping many chromsomes at a time
Another Example: Traveling Sales Rep Problem How to represent a chromosome? What effects does this have on crossover and mutation?
TSP Chromosome: Ordering of city numbers (1 9 2 4 6 5 7 8 3) What can go wrong with crossover? To fix, use order crossover technique Take two chromosomes, and take two random locations to cut p1 = (1 9 2 | 4 6 5 7 | 8 3) p2 = (4 5 9 | 1 8 7 6 | 2 3) Goal: preserve as much as possible of the orderings in the chromosomes
Order Crossover p1 = (1 9 2 | 4 6 5 7 | 8 3) p2 = (4 5 9 | 1 8 7 6 | 2 3) New p1 will look like: c1 = (x x x | 4 6 5 7 | x x) To fill in c1, first produce ordered list of cities from p2, starting after cut, eliminating cities in c1 2 3 9 1 8 Drop them into c1 in order c1 = (2 3 9 4 6 5 7 1 8) Do similarly in reverse to obtain c2 = (3 9 2 1 8 7 6 4 5)
Mutation & Inversion What can go wrong with mutation? What is wrong with inversion?
Mutation & Inversion Redefine mutation as picking two random spots in path, and swapping p1 = (1 9 2 4 6 5 7 8 3) c1 = (1 9 8 4 6 5 7 2 3) Redefine inversion as picking a random middle section and reversing: p1 = (1 9 2 | 4 6 5 7 8 | 3) c1 = (1 9 2 | 8 7 5 6 4 | 3) Another example: http://home.online.no/~bergar/mazega.htm
Reinforcement Learning Game playing: So far, we have told the agent the value of a given board position. How can an agent learn which board positions are important? Play a whole bunch of games, and receive reward at end (+ or -) How do you determine utility of states that aren’t ending states?
The setup: Possible game states Terminal states have reward Mission: Estimate utility of all possible game states
Passive Learning Agent learns by “watching” Fixed probability of moving from one state to another
Technique #1: Naive Updating Also known as Least Mean Squares (LMS) approach Starting at home, obtain sequence of states to terminal state Utility of terminal state = reward loop back over all other states utility for state i = running average of all rewards seen for state i
Naive Updating Analysis Minimizes mean square error with respect to seen data Works, but converges slowly Must play lots of games Ignores that utility of a state should depend on successor
Technique #2: Adaptive Dynamic Programming Utility of a state depends entirely on the successor state If a state has one successor, utility should be the same If a state has multiple successors, utility should be expected value of successors
Finding the utilities To find all utilities, just solve equations This is done via dynamic programming “Gold standard” – this gets you the right values instantly, no convergence or iteration Completely intractable for large problems: For a real game, it means finding actual utilities of all states Assumes that you know M ij
Technique 3: Temporal Difference Learning Want utility to depend on successors, but want to solve iteratively Whenever you observe a transition from i to j: = learning rate difference between successive states = temporal difference Converges faster than Naive updating
Passive Learning in Unknown Environment Unknown environment = transition probabilities unknown Only affects technique 2, Adaptive Dynamic Programming Iteratively: Estimate transition probabilities based on what you’ve seen Solve dynamic programming problem with best estimates so far
Active Learning in an Unknown Environment Probability of going from one state to another now depends on action ADP equations are now:
Exploration: where should agent go to learn utilities? Suppose you’re trying to learn optimal blackjack strategies Do you follow best utility, in order to win? Do you move around at random, hoping to learn more (and losing lots in the process)? Following best utility all the time can get you stuck at an imperfect solution Following random moves can lose a lot
Where should agent go to learn utilities? f(u,n) = exploration function depends on utility of move, and number of times that agent has tried it One possibility: Try a move a bunch of times, then eventually settle
Generalization in Reinforcement Learning Maintaining utilities for all seen states in a real game is intractable. Instead, treat it as a supervised learning problem Training set consists of (state, utility) pairs Learn to predict utility from state This is a regression problem, not a classification problem Can use neural network with multiple outputs
Other applications Applies to any situation where something is to learn from reinforcement Possible examples: Toy robot dogs Petz That darn paperclip “The only winning move is not to play”
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