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**Volume & Surface Area of Solids www.mathsrevision.com Revision of Area**

Revision of Volume and Surface Area Volume of a Prism Volume of a Cylinder Volume of a Pyramid Curved Area of a Cylinder Volume of a Sphere Exam Type Questions

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**Starter Questions a2 – 3b2 = 57 Q1. True or false**

Q2. Write down the probability of picking out a number greater than 20 in the national lottery. Q3. If a = -3 and b = -4 does a2 – 3b2 = 57 Q4. Calculate Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Revision of Areas www.mathsrevision.com Any Type of Triangle**

Level 4 Any Type of Triangle Rhombus and kite Parallelogram Trapezium Circle

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**Compiled by Mr. Lafferty Maths Dept.**

Area Level 4 Learning Intention Success Criteria We are revising area of basic shapes. Know formulae. Use formulae correctly. Show working and appropriate units. 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Area Example : Find the area of the V – shape kite.**

Level 4 Example : Find the area of the V – shape kite. 4cm 7cm Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Composite Areas We can use our knowledge of the basic areas**

Level 4 We can use our knowledge of the basic areas to work out more complicated shapes. Example : Find the area of the arrow. 5cm 3cm 6cm 4cm Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Composite Areas 8cm www.mathsrevision.com 11cm 10cm**

Level 4 Example : Find the area of the shaded area. 8cm 11cm 4cm 10cm Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Created by Mr. Lafferty Maths Dept.**

Composite Areas The Circle Level 4 Example : Find the area of the shape Area = rectangle + semicircle 20cm 5 cm 11-Apr-17 Created by Mr. Lafferty Maths Dept.

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**Area Now try TJ 4+ Ex 16.1 Ch16 (page 121) www.mathsrevision.com**

Level 4 Now try TJ 4+ Ex 16.1 Ch16 (page 121) Tuesday, 11 April 2017 Created by Mr.

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**Q4. Rearrange into the form y =**

Starter Questions Q1. Find the area of the triangle. 10cm 3cm 4cm Q2. Expand out and simplify 2w2 – 3(2w – 5) Q3. True or false Q4. Rearrange into the form y = 2y – 3x + 7 = 0 Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Compiled by Mr. Lafferty Maths Dept.**

Volume & Surface Area Level 4 Learning Intention Success Criteria We are revising volume and surface area of a cuboid. Know formulae. Use formulae correctly. Show working and appropriate units. 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Compiled by Mr. Lafferty Maths Dept.**

Volume of a cuboid 3cm 4cm 6cm Level 4 18 cubes fit the base. = 1 centimetre cube = 1 cm³ 4 layers of 18 cubes = 4 x 18 = 72 centimetre cubes = 72 cm³ 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Compiled by Mr. Lafferty Maths Dept.**

A short cut ! 3cm 4cm 6cm Level 4 height Area of rectangle breadth length Volume = 6 x 3 x 4 = 72 cm³ Volume = length x breadth x height 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Compiled by Mr. Lafferty Maths Dept.**

Example Working Volume = l x b x h Level 4 Heilander’s Porridge Oats V = 18 x 5 x 27 V = cm³ 27cm 5 cm 18 cm 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Compiled by Mr. Lafferty Maths Dept.**

Example Working Volume = l x b x h Level 4 V = 2 x 2 x 2 V = 8 cm³ 2cm 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Compiled by Mr. Lafferty Maths Dept.**

Example Find the volume of the composite shape. Level 4 VT = V1 + V2 7 cm 3 cm 5 cm VT = 10 cm 9 cm 8 cm VT = 825 cm3 V1 = l x b x h = 3 x 5 x 7 V2 = l x b x h = 105 cm³ = 8 x 10 x 9 = 720 cm³ 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Find the length the cuboid**

Example Find the length the cuboid This just an equation. We know how to solve them ! Level 4 4 cm Volume = L x B x H V=200cm3 200 = L x 5 x 4 5 cm 200 = 20L 10 cm L 20L = 200 L = 10 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Compiled by Mr. Lafferty Maths Dept.**

Example Liquid Volume Working Volume = l x b x h Level 4 V = 100 x 30 x 50 V = cm³ 50 cm = ml = 150 litres 30 cm 100 cm How much water can this fish tank hold in litres? 1cm3 = 1 ml 1000 ml = 1 litre So the fish tank can hold 150 litres of water. 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Face Edges and Vertices**

Don’t forget the faces edges and corners we can’t see at the back Face Edges and Vertices Level 4 The shape below is called a cuboid. It is made up of FACES, EDGES and VERTICES. Edges are where the two faces meet (lines) Faces are the sides of a shape (surface area) Vertices where lines meet (corners) 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Face Edges and Vertices**

Calculate the number of faces edges and vertices for a cuboid. Face Edges and Vertices Level 4 6 faces 12 edges Front and back are the same 8 vertices Top and bottom are the same Right and left are the same 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Face Edges and Vertices**

Calculate the number of faces edges and vertices for a cube. Face Edges and Vertices Level 4 6 faces 12 edges Faces are squares 8 vertices 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Find the surface area of the cuboid**

Example Find the surface area of the cuboid Working Level 4 Front Area = l x b = 5 x 4 =20cm2 Top Area = l x b = 5 x 3 =15cm2 4cm Side Area = l x b = 3 x 4 =12cm2 3cm 5cm Total Area = = 94cm2 Front and back are the same Top and bottom are the same Right and left are the same 11-Apr-17 Compiled by Mr. Lafferty Maths Dept.

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**Now try TJ 4+ Ex 16.2 Ch16 (page 122) Volume & Surface Area**

Level 4 Now try TJ 4+ Ex 16.2 Ch16 (page 122) Tuesday, 11 April 2017 Created by Mr.

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**Starter Questions Q1. True or false 2(x – 6) - 2(x + 6) = 0**

Q2. Does x 20 = Explain your answer Q3. Factorise 2y2 + 3y +2 Q4. Calculate Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Volume of Prisms www.mathsrevision.com Learning Intention**

Level 4 Learning Intention Success Criteria We are learning how to calculating volume of any prism given area. 1. Calculate the volume for various prisms. 2. Solution must include appropriate units and working.

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**Volume of Prisms www.mathsrevision.com**

Level 4 Definition : A prism is a solid shape with uniform cross-section Hexagonal Prism Cylinder (circular Prism) Triangular Prism Pentagonal Prism Volume = Area of Cross section x length

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**Volume of Prisms www.mathsrevision.com**

Level 4 Definition : A prism is a solid shape with uniform cross-section Hexagonal Prism Cylinder (circular Prism) Triangular Prism Pentagonal Prism Volume = Area of Cross section x length

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**Volume of Solids www.mathsrevision.com**

Definition : A prism is a solid shape with uniform cross-section Q. Find the volume the triangular prism. Triangular Prism Volume = Area x length = 20 x 10 = 200 cm3 10cm 20cm2

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**Volume of Prisms Now try TJ 4+ Ex 16.3 Ch16 (page 124)**

Level 4 Now try TJ 4+ Ex 16.3 Ch16 (page 124) Tuesday, 11 April 2017 Created by Mr.

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**Starter Questions Q1. Find the area of the parallelogram Q2. Factorise**

7 7 Q2. Factorise 4x + 40 Q3. A can of beans is reduce by 15% to 25p. Find the price before the reduction. Q4. The speed of light is metres per sec. True or false in scientific notation 3 x 108. Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Volume of a Cylinder www.mathsrevision.com Learning Intention**

Level 4 Learning Intention Success Criteria We are learning how to derive the formula for the volume of a cylinder and apply it to solve problems. To know formula. Apply formula correctly. Work backwards using formula.

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**Volume of a Cylinder Volume = Area x height = πr2 = πr2h**

Level 4 The volume of a cylinder can be thought as being a pile of circles laid on top of each other. Volume = Area x height h = πr2 x h Cylinder (circular Prism) = πr2h

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**Volume of a Cylinder V = πr2h = π(5)2x10 = 250π cm3 = 784.5 cm3**

Example : Find the volume of the cylinder below. 5cm Cylinder (circular Prism) 10cm V = πr2h = π(5)2x10 = 250π cm3 = cm3

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**Volume of a Cylinder Now try TJ 4+ Ex 16.4 Ch16 (page 125)**

Level 4 Now try TJ 4+ Ex 16.4 Ch16 (page 125) Tuesday, 11 April 2017 Created by Mr.

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**Starter Questions -(a2) + b2 = 5 Q1. Factorise**

Q2. Write down the probability of picking out a number less than 30 in the national lottery. Q3. True or false if a = -1 and b = -2 -(a2) + b2 = 5 Q4. Explain why Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Volume of a Pyramid www.mathsrevision.com Learning Intention**

Level 4 Learning Intention Success Criteria We are learning how to use the formula for the volume of ANY pyramid and apply it to solve problems. To know formula. Apply formula correctly. Work backwards using formula.

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**Volume of a Pyramid www.mathsrevision.com**

Level 4 cone The volume of any pyramid can be calculated using the formula A = Area of base h = height

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**Volume of Pyramid www.mathsrevision.com**

Level 4 Q. Find the volume the pyramid. 12m 100m2

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**Volume of a Cone www.mathsrevision.com h r**

Level 4 h r If the above cone has radius 15cm and height of 10 cm. Calculate it’s volume.

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**Volume of a Pyramid Now try TJ 4+ Ex 16.5 Ch16 (page 127)**

Level 4 Now try TJ 4+ Ex 16.5 Ch16 (page 127) Tuesday, 11 April 2017 Created by Mr.

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**Starter Questions Q1. Expand out and simplify 3(x – 2) - ( - 3x + 4)**

Q2. Factorise 2x2 – 16x Q3. True or false Q4. By rearranging in y = , find the gradient and where the straight line crosses the x-axis y + 4x - 3 = 0 Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Surface Area of a Cylinder www.mathsrevision.com Learning Intention**

Level 4 Learning Intention Success Criteria We are learning how to calculate the surface area of a cylinder by using basic areas. To know how to split up a cylinder. 2. Calculate the surface area of a cylinder.

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**Surface Area of a Cylinder 2πr h Total Surface Area = 2πr2 + 2πrh**

Level 4 The surface area of a cylinder is made up of 2 basic shapes can you name them. Cylinder (circular Prism) 2πr Curved Area =2πrh Top Area =πr2 Roll out curve side h Bottom Area =πr2 Total Surface Area = 2πr2 + 2πrh

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**Surface Area of a Cylinder = 2π(3)2 + 2π x 3 x 10 = 18π + 60π**

Level 4 Example : Find the surface area of the cylinder below: 3cm Surface Area = 2πr2 + 2πrh 10cm = 2π(3)2 + 2π x 3 x 10 = 18π + 60π Cylinder (circular Prism) = 245 cm2

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**Surface Area of a Cylinder D = 25 25 D = π www.mathsrevision.com**

Diameter = 2r Example : A net of a cylinder is given below. Find the diameter of the tin and the total surface area. D = 25 25 π 9cm 25cm D = = 7.96 cm Surface Area = 2πr2 + 2πrh = 2π(3.98) 2 + 2π(3.98)x9 = = cm2

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**Now try TJ 4+ Ex 16.6 Ch16 (page 129) Surface Area of a Cylinder**

Level 4 Now try TJ 4+ Ex 16.6 Ch16 (page 129) Tuesday, 11 April 2017 Created by Mr.

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**Starter Questions Q1. Find the area of the triangle. 10cm**

Q2. Factorise 4x2 – 64x 6cm Q3. Calculate Q4. Rearrange equation in y = y – 2x + 5 = 0 Tuesday, 11 April 2017 Created by Mr.Lafferty

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**Volume of Solids www.mathsrevision.com Learning Intention**

Level 4 Learning Intention Success Criteria We are learning how to use the sphere formula and use it to solve real-life problems. To know the volume formula for a sphere. Work out volumes for spheres. Answer to contain appropriate units and working.

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**Volume of a Sphere www.mathsrevision.com D = diameter r**

Level 4 D = diameter r D Q. If the above sphere has radius 10cm. Calculate it’s volume.

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**Volume of a sphere Q. Find the volume the composite shape.**

Level 4 Q. Find the volume the composite shape. Volume = Cylinder + half a sphere ½ sphere Cylinder r 2m h = 6m

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**Now try TJ 4+ Ex 16.7 Ch16 (page 130) Volume of a sphere**

Level 4 Now try TJ 4+ Ex 16.7 Ch16 (page 130) Tuesday, 11 April 2017 Created by Mr.

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