Presentation on theme: "Problem of the Day 1) I am thinking of four numbers such that"— Presentation transcript:
1Problem of the Day 1) I am thinking of four numbers such that The sum of all the four numbers is 31.Only one of number is odd.The highest number minus the lowest number is 7.If you subtract the middle two numbers, it equals two.There are no duplicate numbers.What four numbers i am thinking of ?
2Fundamental Theorem of Algebra Objective: To be able to use the Fundamental Theorem of Algebra to find polynomial equations.TS: Demonstrating understanding of conceptsWarm up:T or F: A cubic function has at least one real root.T or F: A polynomial function can have no complex solutions.T or F: A polynomial function could have only one imaginary solution.T or F: A polynomial could have root 2 as its only irrational solution.
3Linear Factorization Theorem The Fundamental Theorem of AlgebraIf f(x) is a polynomial of degree n, where n > 0, then f has at least one zero in the complex number system.Linear Factorization TheoremIf f(x) is a polynomial of degree n where n > 0, f has precisely n linear factorsf(x) = an(x – c1)(x – c2)∙∙∙(x – cn)where c1, c2, …, cn are complex numbers.
5Find the quartic polynomial with zeros -√2 and i, which passes through (1, 6)
6Factoring Polynomials so they are irreducable over the rationals, reals and complex zeros. Factor each:a) x4 – x2 – 20x4 – 3x3 – x2 – 12x – 20(Hint: x2 + 4 is a factor)
7You Try:1) If -1 – 3i is a zero of x3 + 4x2 + 14x + 20, find the other zerosFactor the following: x4 + 6x2 – 27a) Irreducible over the rationals:b) Irreducible over the reals:c) Irreducible over the complex: