Presentation on theme: "Computer Engineering II"— Presentation transcript:
1Computer Engineering II 4th year, Communications EngineeringWinter 2014Dr. Tamer Samy GaafarDept. of Computer & Systems Engineering
2Course Web Page http://www.tsgaafar.faculty.zu.edu.eg
3AnnouncementsEng. Mohamed Atef will take the last 50 minutes of today’s class to cover the material required for Lab1.Lab/Assignment Groups are posted or not?.Lab1 is now posted.Before your lab day, get prepared by reading the posted material very well so that you don’t waste much of your lab time trying to figure out what is going on.Today’s lecture and lab presentation are posted.
6Typical 16 Mb DRAM (4M x 4)Logically, 4 square arrays of 2048 x 2048 elements.Each horizontal line connects to the Select terminal of each cell in its row.Each vertical line connects to the Data in/Sense terminal of each cell in its column.Reduces number of address pinsMultiplex row address and column address11 pins to address (211=2048)Adding one more pin doubles range of values so x4 capacity
7RefreshingRefresh circuit included on chip.Disable chip.Count through rows.Data is read out and written back into the same location each cell is refreshed.Takes time.Slows down apparent performance.
8Chip Packaging 16-Mbit DRAM, 4M x 4. 8-Mbit EPROM chip, 1M x 8. One-word-per-chip package.Address: A0-A19, Data: D0-D7Vcc; power, Vss: ground, CE: chip enable, Vpp: programming voltage.16-Mbit DRAM, 4M x 4.Updatable data pins in/out.WE: Write EnableOE: Output EnableNC: No Connect even # of pins
9Module Organization256 k byte memoryAvailable: 256 k x 1-bit chips
10Module Organization (2) 1 M byte memoryAvailable: 256 k x 1-bit chips
11Semiconductor memory is subject to errors. Hard Failure Error CorrectionSemiconductor memory is subject to errors.Hard FailurePermanent physical defect.Memory cells cannot store data: stuck at 0 or 1, or switching.Caused by harsh environments, manufacturing defects, or wear.Soft ErrorRandom, non-destructive event that alters contents of one or more memory cells.No permanent damage to memory.Caused by power supply problems or alpha particles.Detected/corrected using Hamming error correcting code.
13Hamming Error-Correcting Code Data bits: 1110AB1111DiscrepanciesCParity bitsChosen so that total number of 1s in each circle is even.By checking the parity bits, discrepancies are found error can be easily found and corrected.
14How many check bits to use? The comparison logic receives as input two K-bit values.A bit-by-bit comparison is done by taking the XOR of the two inputs syndrome word.Each bit of the syndrome word is 0 if there was a match in that position, otherwise, it is 1.Syndrome word is K bits wide range 0 : 2K -1.The value 0 indicates no error 2K -1 are left to indicate which bit was in error.2K -1 ≥ M + K
15Hamming Code2K - 1 ≥ M + K 2K ≥ 9+K K = 41111Data bits12111098765432111?11?11?1??1111=Bit position 4Bit position 8Bit position 1Bit position 2Bit position 8: 0Bit position 2: 1Bit position 1: 1Bit position 4: 1
161 1 ? 1 1 1 ? 1 ? 1 ? Hamming Code (2) Assume error in bit 9. 12111098765432111?111?1?1?Assume error in bit 9.Recompute the check bits.Bit 1 = 0 (error).Bit 2 = 1.Bit 4 = 1.Bit 8 = 1 (error).Error is in bit position = = 9 flip it (correction).