Download presentation

Presentation is loading. Please wait.

1
**5.1 Inverse & Joint Variation**

p.303 What is direct variation? What is inverse variation? What is joint variation?

2
**Just a reminder… Direct Variation Use y=kx.**

Means “y varies directly with x.” k is called the constant of variation.

3
**New stuff! Inverse Variation “y varies inversely with x.”**

k is the constant of variation.

4
**Hint: Solve the equation for y and take notice of the relationship.**

Ex: tell whether x & y show direct variation, inverse variation, or neither. xy=4.8 y=x+4 Inverse Variation Hint: Solve the equation for y and take notice of the relationship. Neither Direct Variation

5
**Ex: The variables x & y vary inversely, and y=8 when x=3.**

Write an equation that relates x & y. k=24 Find y when x= -4. y= -6

6
**The inverse variation equation is y = When x = 2, y = 2 = 6. ANSWER**

The variables x and y vary inversely. Use the given values to write an equation relating x and y. Then find y when x = 2. 4. x = 4, y = 3 y = a x Write general equation for inverse variation. 4 3 = a Substitute 3 for y and 4 for x. 12 = a Solve for a. 12 x The inverse variation equation is y = When x = 2, y = 2 = 6. ANSWER

7
MP3 Players The number of songs that can be stored on an MP3 player varies inversely with the average size of a song. A certain MP3 player can store 2500 songs when the average size of a song is 4 megabytes (MB). Write a model that gives the number n of songs that will fit on the MP3 player as a function of the average song size s (in megabytes).

8
**• Make a table showing the number of songs that will**

• Make a table showing the number of songs that will fit on the MP3 player if the average size of a song is 2MB, 2.5MB, 3MB, and 5MB as shown below. What happens to the number of songs as the average song size increases?

9
**Write an inverse variation model. a n = s a 2500 = 4 10,000 = a**

STEP 1 Write an inverse variation model. a n = s Write general equation for inverse variation. a 2500 = 4 Substitute 2500 for n and 4 for s. 10,000 = a Solve for a. A model is n = s 10,000 ANSWER STEP 2 Make a table of values. From the table, you can see that the number of songs that will fit on the MP3 player decreases as the average song size increases. ANSWER

10
The table compares the area A (in square millimeters) of a computer chip with the number c of chips that can be obtained from a silicon wafer. Computer Chips • Write a model that gives c as a function of A. • Predict the number of chips per wafer when the area of a chip is 81 square millimeters.

11
SOLUTION STEP 1 Calculate the product A c for each data pair in the table. 58(448) = 25,984 62(424) = 26,288 66(392) = 25,872 70(376) = 26,320 Each product is approximately equal to 26,000. So, the data show inverse variation. A model relating A and c is: A c = 26,000 , or c = A 26,000 STEP 2 Make a prediction. The number of chips per wafer for a chip with an area of 81 square millimeters is 81 26,000 321 c =

12
Joint Variation When a quantity varies directly as the product of 2 or more other quantities. For example: if z varies jointly with x & y, then z=kxy. Ex: if y varies inversely with the square of x, then y=k/x2. Ex: if z varies directly with y and inversely with x, then z=ky/x.

13
**Examples: Write an equation.**

y varies directly with x and inversely with z2. y varies inversely with x3. y varies directly with x2 and inversely with z. z varies jointly with x2 and y. y varies inversely with x and z.

14
**Write a general joint variation equation. z = axy**

The variable z varies jointly with x and y. Also, z = –75 when x = 3 and y = –5. Write an equation that relates x, y, and z. Then find z when x = 2 and y = 6. SOLUTION STEP 1 Write a general joint variation equation. z = axy Use the given values of z, x, and y to find the constant of variation a. STEP 2 –75 = a(3)(–5) Substitute 75 for z, 3 for x, and 25 for y. –75 = –15a Simplify. 5 = a Solve for a.

15
STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = 5xy STEP 4 Calculate z when x = 2 and y = 6 using substitution. z = 5xy = 5(2)(6) = 60

16
**Write an equation for the given relationship.**

y = a x a. y varies inversely with x. b. z varies jointly with x, y, and r. z = axyr c. y varies inversely with the square of x. y = a x2 d. z varies directly with y and inversely with x. z = ay x e. x varies jointly with t and r and inversely with s. x = atr s

17
**Write a general joint variation equation. z = axy**

x = 4, y = –3, z =24 SOLUTION STEP 1 Write a general joint variation equation. z = axy Use the given values of z, x, and y to find the constant of variation a. STEP 2 24 = a(4)(– 3) Substitute 24 for z, 4 for x, and –3 for y. 24 = –12a Simplify. = a – 2 Solve for a.

18
STEP 3 Rewrite the joint variation equation with the value of a from Step 2. z = – 2 xy STEP 4 Calculate z when x = – 2 and y = 5 using substitution. z = – 2 xy = – 2 (– 2)(5) = 20 z = – 2 xy ; 20 ANSWER

19
**What is direct variation?**

y varies directly with x (y = kx) What is inverse variation? y varies inversely with x (y = k/x) What is joint variation? A quantity varies directly as the product of two or more other quantities ( y = kxy)

20
Assignment p. 307 3-33 every third problem,

Similar presentations

Presentation is loading. Please wait....

OK

Vocabulary direct variation constant of variation

Vocabulary direct variation constant of variation

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on metro rail in india Ppt on healthy diet india Ppt on reproductive system of human body Ppt on diode characteristics graph Free download ppt on probability for class 9 Ppt on javascript events onload Ppt on rain water harvesting download Ppt on central government of india Ppt on vitamin b12 deficiency Basic map reading ppt on ipad