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ISENTROPIC EFFICIENCY CALCULATIONS for POSITIVE-DISPLACEMENT ROTARY-LOBE BLOWERS Roger E. Blanton, P.E. District Sales Manager Kaeser Compressors, Inc.

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Presentation on theme: "ISENTROPIC EFFICIENCY CALCULATIONS for POSITIVE-DISPLACEMENT ROTARY-LOBE BLOWERS Roger E. Blanton, P.E. District Sales Manager Kaeser Compressors, Inc."— Presentation transcript:

1 ISENTROPIC EFFICIENCY CALCULATIONS for POSITIVE-DISPLACEMENT ROTARY-LOBE BLOWERS Roger E. Blanton, P.E. District Sales Manager Kaeser Compressors, Inc.

2 EFFICIENCY  All air and gas compressors are less than 100% efficient

3 EFFICIENCY P1 V1 T1 Position 1 P2 V2 T2 Position 2 P2 > P1 V2 < V1 T2 > T1

4 EFFICIENCY  Entropy is a measure of the energy loss

5 COMPRESSION MODEL  Constant entropy (isentropic) process is ideal  No heat loss and perfectly reversible

6 ISENTROPIC COMPRESSION  Follows this relationship, P2 /P1 = (v1/ v2) k » Pv k = a constant where: v = specific volume [ft 3 /lb] P1, P2 = initial and final pressure [Pabs] k = Cp/Cv = specific heat ratio = 1.4 for air

7 COMPRESSOR WORK  For continuous isentropic compression of a gas obeying the previous relationship, work per unit mass (ft·lb/lb) is Wis = vdP = P1 * v1 * [k / (k-1)] * [(P2 / P1) ((k-1) / k) – 1] BHF = Big Hairy Formula !!!

8 POWER  hp is = W is * m / 60 / 550 where m is mass flow rate in lb/min

9 EFFICIENCY  Isentropic efficiency of a compressor is the ratio of the ideal isentropic work to the actual work required  is = W is / W act = hp is / hp act

10 EXAMPLE CALCULATION  Brand K model 2000 rpm  P1 = 14.7 psia  P2 = 10 psig (24.7 psia)  T1 = 68° F  ρ1 (density) = lb/ft 3  K = 1.4 (air)  BHP = 13.2 (from performance table)  CFM = 222 (from performance table)  m = 222 * = lb/min

11 EXAMPLE CALCULATION (cont’d)  v1 = 1/ ρ1 = 1 / = ft 3 /lb  k / (k-1) = 1.4 / (1.4 – 1) = 1.4 / 0.4 = 3.5  P2 / P1 = 24.7 / 14.7 = 1.68  (k-1) / k) = (1.4 -1) / 1.4 = 0.4 / 1.4 =  (P2 / P1) ((k-1) / k) = = 1.16

12 EXAMPLE CALCULATION (cont’d) Back to the Big Hairy Formula Wis = P1 * v1 * [k / (k-1)] * [(P2 / P1) ((k-1) / k) – 1] Wis = 14.7 * * 3.5 * [ ] * 144 = 15,801 ft·lb/lb

13 EXAMPLE CALCULATION (cont’d)  hp is = W is * m / 60 / 550  hp is = * / 60 / 550 = 8 hp

14 EXAMPLE CALCULATION (cont’d)   is = hp is / hp act   is = 8 / 13.2 = 61% efficient

15 CONCLUSION  Repeat this procedure for different blowers at the same pressure

16 CONCLUSION  Perform this calculation on blowers bid for a project to evaluate efficiency  Look at blower efficiency, not just price when making a decision

17 CONCLUSION  Perform a Life Cycle Cost (LCC) analysis  Typically a 20 year project horizon is considered  Include installation, estimated maintenance, and operating costs  Discount the expenses to net present value (NPV) for comparison

18 CONCLUSION  Operating cost greatly outweighs first cost  Blower efficiency is important for customer satisfaction


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