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Phasing Goal is to calculate phases using isomorphous and anomalous differences from PCMBS and GdCl 3 derivatives --MIRAS. How many phasing triangles will.

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Presentation on theme: "Phasing Goal is to calculate phases using isomorphous and anomalous differences from PCMBS and GdCl 3 derivatives --MIRAS. How many phasing triangles will."— Presentation transcript:

1 Phasing Goal is to calculate phases using isomorphous and anomalous differences from PCMBS and GdCl 3 derivatives --MIRAS. How many phasing triangles will we have for each structure factor? For example. F PH = F P +F H for isomorphous differences For example. F PH * = F P + F H * for anomalous differences -h-k-l hkl -h-k-l

2 4 Phase relationships PCMBS F PH = F P +F H for isomorphous differences PCMBS F PH * = F P + F H * for anomalous differences -h-k-l hkl -h-k-l GdCl 3 F PH = F P +F H for isomorphous differences GdCl 3 F PH * = F P + F H * for anomalous differences -h-k-l hkl -h-k-l

3 Real axis Imaginary axis Harker construction for SIR phases. F P –native measurement F H (hkl) calculated from heavy atom position. F PH (hkl)–measured from derivative. Point to these on graph. FHFH |F p | |F PH | PCMBS F PH = F P +F H for isomorphous differences SIR Phasing Ambiguity

4 Real axis Imaginary axis F H ( hkl ) F H (-h-k-l)* F p (hkl) We will calculate SIRAS phases using the PCMBS Hg site. F P –native measurement F H (hkl) and F H (-h-k-l) calculated from heavy atom position. F PH (hkl) and F PH (-h-k-l) –measured from derivative. Point to these on graph. Isomorphous differences Anomalous differences PCMBS F PH * = F P + F H * for anomalous differences -h-k-l hkl -h-k-l Harker Construction for SIRAS phasing (Single Isomorphous Replacement with Anomalous Scattering)

5 Real axis Imaginary axis Anomalous Deriv 1 F p (hkl) Isomorphous Deriv 1 Isomorphous Deriv 2 GdCl 3 F PH = F P +F H for isomorphous differences Harker Construction for MIRAS phasing (Multiple Isomorphous Replacement with Anomalous Scattering)

6 Real axis Imaginary axis Anomalous Deriv 1 Isomorphous Deriv 1 Isomorphous Deriv 2 F p (hkl) Anomalous Deriv 2 GdCl 3 F PH * = F P + F H * for anomalous differences -h-k-l hkl -h-k-l Harker Construction for MIRAS phasing (Multiple Isomorphous Replacement with Anomalous Scattering)

7 Barriers to combining phase information from 2 derivatives 1)Initial Phasing with PCMBS 1)Calculate phases using coordinates you determined. 2)Refine heavy atom coordinates 2)Find Gd site using Cross Difference Fourier map. 1)Easier than Patterson methods. 2)Want to combine PCMBS and Gd to make MIRAS phases. 3)Determine handedness (P or P ?) 1)Repeat calculation above, but in P )Compare map features with P map to determine handedness. 4)Combine PCMBS and Gd sites (use correct hand of space group) for improved phases. 5)Density modification (solvent flattening & histogram matching) 1)Improves Phases 6)View electron density map

8  Remember, because the position of Hg was determined using a Patterson map there is an ambiguity in handedness.  The Patterson map has an additional center of symmetry not present in the real crystal. Therefore, both the site x,y,z and -x,-y,-z are equally consistent with Patterson peaks.  Handedness can be resolved by calculating both electron density maps and choosing the map which contains structural features of real proteins (L- amino acids, right handed a-helices).  If anomalous data is included, then one map will appear significantly better than the other. Center of inversion ambiguity Patterson map

9 Use a Cross difference Fourier to resolve the handedness ambiguity With newly calculated protein phases,  P, a protein electron density map could be calculated. The amplitudes would be |F P |, the phases would be  P.  x  =1/V*  |F P |e -2  i(hx+ky+lz-  P ) Answer: If we replace the coefficients with |F PH2 -F P |, the result is an electron density map corresponding to this structural feature.

10  x  =1/V*  |F PH2 -F P |e -2  i(hx-  P ) What is the second heavy atom, Alex. When the difference F PH2 -F P is taken, the protein component is removed and we are left with only the contribution from the second heavy atom. This cross difference Fourier will help us in two ways: 1)It will resolve the handedness ambiguity by producing a very high peak when phases are calculated in the correct hand, but only noise when phases are calculated in the incorrect hand. 2)It will allow us to find the position of the second heavy atom and combine this data set into our phasing. Thus improving our phases.

11 Phasing Procedures 1)Calculate phases for site x,y,z of PCMBS and run cross difference Fourier to find the Gd site. Note the height of the peak and Gd coordinates. 2)Negate x,y,z of PCMBS and invert the space group from P to P Calculate a second set of phases and run a second cross difference Fourier to find the Gd site. Compare the height of the peak with step 1. 3)Chose the handedness which produces the highest peak for Gd. Use the corresponding hand of space group and PCMBS, and Gd coordinates to make a combined set of phases.

12 Lack of closure  =(F H +F P )-(F PH ) F H -calculated from atom position F PH -observed F P -observed Why is it not zero?  is the discrepancy between the heavy atom model and the actual data.

13 Phasing power |F H |/  = phasing power. The bigger the better. Phasing power >1.5 excellent Phasing power =1.0 good Phasing power = 0.5 unusable  =(F H +F P )-(F PH )

14 R cullis  /|F PH |-|F P |= R cullis. Kind of like an R factor for your heavy atom model. |F PH |-|F P | is like an observed FH, and e is the discrepancy between the heavy atom model and the actual data. R cullis <1 is useful. <0.6 great!  =(F H +F P )-(F PH )

15 Figure of Merit Phase probability distribution How far away is the center of mass from the center of the circle?

16 Density modification A) Solvent flattening. Calculate an electron density map. If  solvent If  >threshold -> protein Build a mask Set density value in solvent region to a constant (low). Transform flattened map to structure factors Combine modified phases with original phases. Iterate Histogram matching

17 Density modification B) Histogram matching. Calculate an electron density map. Calculate the electron density distribution. It’s a histogram. How many grid points on map have an electron density falling between 0.2 and 0.3 etc? Compare this histogram with ideal protein electron density map. Modify electron density to resemble an ideal distribution. Number of times a particular electron density value is observed. Electron density value

18 HOMEWORK


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