# NameEnrollment noRoll no PATEL KRUPALI13084010604006 SHAH JENNY13084010605661 NAYAK KHUSHBU13084010602578 GAMIT ZANKHANA13084010601549 Guided by - Mr.

## Presentation on theme: "NameEnrollment noRoll no PATEL KRUPALI13084010604006 SHAH JENNY13084010605661 NAYAK KHUSHBU13084010602578 GAMIT ZANKHANA13084010601549 Guided by - Mr."— Presentation transcript:

NameEnrollment noRoll no PATEL KRUPALI13084010604006 SHAH JENNY13084010605661 NAYAK KHUSHBU13084010602578 GAMIT ZANKHANA13084010601549 Guided by - Mr. Shivang Dabhi -Miss Ankita Upadhyay

Area INTRODUCTION The term “area” in the context of surveying refers to the area of the tract of land projected upon the horizontal plane and not to the actual area of the land surface. Area may be expressed in the following units : 1 : Square meters 2 : Hectares (1 hectare =10000 m 2 =2471 acres) 3 : Square feet 4 : Acres (1 acre =4840 sq. yd. =43,560 sq. ft.) 5 : Square kilometer (km 2 ) = (1 km 2 =10 6 m 2 )

Computation of Area Graphical MethodInstrumental method From Field notes Entire area Boundary area Frotted planm plo Mid oridnate rule Trapezoidal rule Simpson rule Avg. oridnate rule

COMPUTATION OF AREA FROM FIELD NOTES: In this method, chain line is run approximately in the centre of the area to be calculated. With the help of the cross-staff or optical square,

Area of fig 1 can be calculated as A=A1+A2+A3+A4+A5 A1=1/2(58-25)*10=165 m2 A2=1/2(25*10)=125 m2 A3=1/2(16*12)=96 m2 A4=1/2(12+9)*(50-16)=357 m2 A5=1/2(58-50)*9=36 m2 Total area of field A=779 m2

. Computation of area from a plotted plan The area may be calculated in the following two ways. Case-1: considering the entire area: The entire area is divided into regions of a convenient shape and calculated as follows: (1) by dividing the area into triangles. (2) by dividing the area into squares. (3) by drawing parallel lines and converting them to rectangles.

Triangle area =1/2*base*altitude Area=sum of areas of triangles Each square represents unit area 1 cm2 or 1 m2 Area=nos. of square *unit area

Area =Σ Length of rectangle ×Constant depth

Case 2 : Middle area +boundary Area : In this method, a large square or rectangle is formed within the area in the plan. The ordinates are drawn at regular intervals from the side of the square to the curved boundary. Total area A=Middle Area A1+boundary area A2 Middle area can be subdivided into simple geometrical shapes, such as triangle rectangle, squares, trapezoids etc and Area of these figures are determined from the dimensions obtained from the plan.

Boundary area is calculated according to one of the following rules: 1 The mid-ordinate rule 2 The average ordinate rule 3 The trapezoidal rule 4 Simpson rule The mid ordinate Rule : Let O1,O2,O3,….,On=Ordinate At equal intervals. l=length of base line d=common distance between ordinates h1,h2,….,hn=mid-ordinates Area of plot=h1*d+h2*d+…+hn*d =d(h1+h2+….+hn) i.e. Area =common distance*sum of mid-ordinates

(2) The Average-Ordinate Rule : Lets O1,O2,…..,On=Ordinate or offsets at regular intervals L=Length of base line n= Number of divisions n+=number of ordinates Area =O1+O2+….+On/n+1*l =sum of ordinates/no. of ordinates *length of base line

3: The Trapezoidal Rule : While applying the trapezoidal rule, boundaries between the ends of the ordinates are assumed to be the straight. Thus, the area enclosed between the base line and the irregular boundary line are considered as trapezoids.

Let O1,O2,….On = Ordinates at equal intervals d=Common distance 1 st Area =O1+O2/2*d 2 nd Area =O2+O3/2*d 3 rd Area = O3+O4/2*d last area = On-+On/2*d Total area =[O 1 +2O 2 +2O 3 +2O 4 +2On-1 +On]*d/2 [O 1 +O n +2(O 2 +O 3 +….+ O n-1 )]*d/2 Common distance/2 [(1 st ordinate +last ordinate)+2 (sum of other ordinates)

4: Simpson Rule In this rule the boundaries between the ends of ordinates are assumed to form an arc of the parabola. Hence Simpson rule is sometimes called the parabola rule. Let O1,O2,O3=Three consecutive ordinates d=Common distance between the ordinates Area AF2DC = area of trapezium AFDC+ Area of * segment F2DEF Here, Area of trapezium =O1+O2/2*2d

Area of segment =2/3*area of parallelogram F13D = 2/3 *E2*2d =2/3 *{O2-O1+O2/2}*2d So, the area between the first two divisions, ∆1=O1+O3/2*2d+2/3{O2-O1+O3/2}*2d =d/3(O1+4O2+O3) Similarly, the area between next two divisions ∆2= d/3(O3+4O4+O5) and so on. Total area =d/3 (O1+4O2+2O3+4O4+……+On) =d/3 [o1+on+4(o2+o4+…)+2(o3+o5+…)] =common distance/3[(1 st ordinate + last ordinate) + 4(sum of even ordinates) + 2 (sum of remaining odd ordinates)]

TRAPEZOIDAL RULE V/S SIMPSON RULE 1. The boundary between the ordinates is considered to be straight 2. There is no limitation. It can be applied for any no. of ordinates. 3. It gives an approximate result. 1.The boundary between the ordinates is considered to be an arc of a parabola. 2. This rule can be applied when the no. of ordinates must be odd. 3. It gives a more accurate result than the trapezoidal rule…

PLANIMETER A=M(FR – IR +/- 10N + C )

Download ppt "NameEnrollment noRoll no PATEL KRUPALI13084010604006 SHAH JENNY13084010605661 NAYAK KHUSHBU13084010602578 GAMIT ZANKHANA13084010601549 Guided by - Mr."

Similar presentations