1. OutLine of Tutorial 5 Summary of Load/Store instructions Exercises reading memory in Simulator Exercises writing code

2. Summary of Load/Store instructions Format Opcode regA, displacement(regB) displacement is less than 16 bit Code like “ldq regA, label” won’t be executed in the Simulator, it needs to be replaced by following code ldiq regA, label; ldq regA, (regA) vitual memory = displacement + value of regB

3. Summary of Load/Store instructions Load instructions in Simulator ldbu: filling remaining bytes in register with 0 ldwu: filling remaining bytes in register with 0 Memory address has to be multiple of 2 ldl filling remaining bytes in register with signed bit Memory address has to be multiple of 4 ldq Memory address has to be multiple of 8 lda Load the memory address rather than the value

4. Summary of Load/Store instructions Store instruction in Simulator stb: stw: Memory address has to be multiple of 2 stl Memory address has to be multiple of 4 stq Memory address has to be multiple of 8

5. Get answer using Simulator, Exercise 1 data{ value0:asciiz"ab"; value1:byte 0x12; value2: long 0x3456; value3:quad 0x87654321; } ldiq$t0, value0; ldq$t1, ($t0); ldwu$t2, 4($t0); lda$t3, 3($t0); ldbu$t2, ($t3); ldl$t3, 8($t0); ldl$t4, 6($t0); ldq$t5, 4($t0); Show the contents of memory and the labels With above memory allocated, indicate how the contents of registers are changed by following instructions, and which instructions can’t be executed following code is in example 5

6. Continue exercise 1 stq$t1, ($t0); stb$t2, 1($t0); stw$t3, 2($t0); stl$t3, 8($t0); ldiq$t0, value2; stq$t3, ($t0); stl$t3, 2($t0); Continue with above exercise, indicate how the contents of registers are changed by following instructions, and which instructions can’t be executed

7. Get answer using Simulator, Exercise 2 data{ align quad; value0:asciiz"ab"; alignword; value1:byte 0x12; alignlong; value2: word 0x3456; value3:long0x7890; } ldiq$t0, value0; ldq$t1, ($t0); ldwu$t2, 4($t0); lda$t3, 3($t0); ldbu$t2, ($t3); ldl$t3, 8($t0); ldl$t4, 6($t0); ldq$t5, 4($t0); Show the contents of memory and the labels With above memory allocated, indicate how the contents of registers are changed by following instructions, and which instructions can’t be executed following code is in example 6

8. Continue exercise 2 stq$t1, ($t0); stb$t2, 1($t0); stw$t3, 2($t0); stl$t3, 8($t0); ldiq$t0, value2; stq$t3, ($t0); stl$t3, 2($t0); Continue with above exercise, indicate how the contents of registers are changed by following instructions, and which instructions can’t be executed

9. Exercise 3: add code to example 7 (1) Write code to load value0,value1,value2,value3 to register t1,t2,t3,t4 (2) Write code to store values in register t1,t2,t3,t4 in memory label value0,value1,value2,value3