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CHARLES The neon gas inside a dry cleaner’s window sign is at a temperature of 114 oC and fills a space that totals L. If this same sample of gas was transferred to a different sign with twice the volume, while maintaining the same pressure, what would the neon’s new temperature be?

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**V1 = V2 T2 = T1V2 T1 T2 V1 . T2 = (387 K) (1.3 L) . T2 = 774 K CHARLES**

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Avogadro If a weather balloon containing 121 moles of helium gas has a volume of kL at 20OC and atm, how many moles of helium gas are in a 25.0 L birthday balloon at a temperature of 293K and a pressure of 798 mmHg?

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**V1 = V2 n2 = n1V2 n1 n2 V1 . n2 = (121 mol) (25.0 L) . n2 = 1.12 mol**

Avogadro

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Gay-Lussac Assuming a constant volume, a balloon with an internal pressure of atm at 298 K would be what temperature at a pressure of atm?

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**P1 = P2 T2 = T1P2 T1 T2 P1 . T2 = (298 K) (0.646 atm) . T2 = 195K**

Gay-Lussac

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Combined Shortly after beginning to blow a bubble gum bubble, a child’s 14.3 mL bubble contains moles of air at 98oF and 1.11 atm. At the moment just before it popped, the child had added an additional moles of air, and the final temperature and pressure were 97.3oF and 758 torr respectively. What was the volume of the bubble right before it popped?

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P1V1 = P2V2 V2 = P1V1n2T2 n1T n2T n1T1P2 . V2 = (1.11atm)(14.3mL)( mol)(309K) . ( mol)(310K)(0.997atm) V2 = 133 mL Combined

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Boyle In a thermonuclear device,the pressure of the 0.50 L of gas within the bomb casing reaches 4.0x106atm. When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. What is the volume of the gas after the explosion?

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**P1V1 = P2V2 V2 = P1V1 . V2 = (4.0 x 106 atm)(0.50 L) .**

V2 = 2.0 x 106 L Boyle

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January 31, 2008 Go over homework Charles’s Law Avogadro’s Law Homework -- Page 480 -- 11, 13, 14bc, 15bc, 17, 19, 20.

January 31, 2008 Go over homework Charles’s Law Avogadro’s Law Homework -- Page 480 -- 11, 13, 14bc, 15bc, 17, 19, 20.

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