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The neon gas inside a dry cleaner’s window sign is at a temperature of 114 o C and fills a space that totals 0.65 L. If this same sample of gas was transferred.

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Presentation on theme: "The neon gas inside a dry cleaner’s window sign is at a temperature of 114 o C and fills a space that totals 0.65 L. If this same sample of gas was transferred."— Presentation transcript:

1 The neon gas inside a dry cleaner’s window sign is at a temperature of 114 o C and fills a space that totals 0.65 L. If this same sample of gas was transferred to a different sign with twice the volume, while maintaining the same pressure, what would the neon’s new temperature be? CHARLES

2 V1 = V2 T2 = T1V2 T1 T2 V1. T2 = (387 K) (1.3 L). (0.65 L) T2 = 774 K CHARLES

3 If a weather balloon containing 121 moles of helium gas has a volume of kL at 20 O C and 1.05 atm, how many moles of helium gas are in a 25.0 L birthday balloon at a temperature of 293K and a pressure of 798 mmHg? Avogadro

4 V1 = V2 n2 = n1V2 n1 n2 V1. n2 = (121 mol) (25.0 L). (2710 L) n2 = 1.12 mol Avogadro

5 Assuming a constant volume, a balloon with an internal pressure of atm at 298 K would be what temperature at a pressure of atm? Gay-Lussac

6 P1 = P2 T2 = T1P2 T1 T2 P1. T2 = (298 K) (0.646 atm). (0.987atm) T2 = 195K Gay-Lussac

7 Shortly after beginning to blow a bubble gum bubble, a child’s 14.3 mL bubble contains moles of air at 98 o F and 1.11 atm. At the moment just before it popped, the child had added an additional moles of air, and the final temperature and pressure were 97.3 o F and 758 torr respectively. What was the volume of the bubble right before it popped? Combined

8 P1V1 = P2V2 V2 = P1V1n2T2 n1T1 n2T2 n1T1P2. V2 = (1.11atm)(14.3mL)( mol)(309K). ( mol)(310K)(0.997atm) V2 = 133 mL Combined

9 In a thermonuclear device,the pressure of the 0.50 L of gas within the bomb casing reaches 4.0x10 6 atm. When the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. What is the volume of the gas after the explosion? Boyle

10 P1V1 = P2V2V2 = P1V1. P2 V2 = (4.0 x 10 6 atm)(0.50 L). (1.00 atm) V2 = 2.0 x 10 6 L Boyle


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