Presentation is loading. Please wait.

Presentation is loading. Please wait.

Check Beam Shear. Bending moment design Short direction 245 166 2.5m.

Similar presentations


Presentation on theme: "Check Beam Shear. Bending moment design Short direction 245 166 2.5m."— Presentation transcript:

1 Check Beam Shear

2 Bending moment design Short direction m

3 Central band of short direction = 0.83 As = 0.83 (10.1)=8.6cm 2 Central band ratio =

4

5 Footing Design Part II Combined footing

6 Example 1 Design a combined footing As shown

7 Dimension calculation The base dimension to get uniform distributed load x2=6.2m x1=0.2m 800 kN 1200 kN x 2000kN A 800(0.2)+1200(6.2)=2000(x) x = 3.8m 2x =7.6 m 800 kN 1200 kN Try thickness =80cm

8 Area required

9 Check for punching Shear d = 730 mm A 1.13m 0.765

10 B

11 Draw S.F.D & B.M.D Stress under footing = 190 *1.8 = 342 kN/m

12 Check for beam shear b = 1800mm, d = 730mm

13 Bending moment Long direction

14 Bending moment Short direction Under Column A

15 Under Column B Shrinkage Reinforcement in short direction

16

17 Footing Design Part III Combined footing, strip footing, & Mat foundation

18 Example 2 Design a combined footing As shown

19 Dimension calculation The base dimension to get uniform distributed load x1=0.2m x2=4.2 m 1200 kN 750 kN x 1950kN A 750(4.2)+1200(0.2)=1950 (x) x = 1.75m

20 Area required

21 Check for punching Shear h= 750mm d = 732 mm A B1=4m B2=1m

22 B

23 Draw S.F.D & B.M.D

24 M max Empirical S.F.D & B.M.D m Convert trapezoidal load to rectangle Clear distance between column B in moment design = ave. width = 2.5m

25 Check for beam shear d = 665mm Y=1.5m 1m 4m x b

26 Bending moment Long direction Top Bottom

27 Bending moment Short direction Under Column A

28 Under Column B Shrinkage Reinforcement in short direction

29 Reinforcement details

30 Example 3 (Strip footing) Design a combined footing As shown

31 Dimension calculation The base dimension to get uniform distributed load Assume L1=0.6 x1=5.2m 800 kN 1280 kN x 3040kN A 800(0.6)+1280(5.1)+960(10.6)= 3040 (x) x = 5.65m, 2(x)=11.3m L2= (10.6)= kN x2=10.7m L2

32

33 Check for punching Shear h = 700 mm d=630mm B Example You can check other columns

34 Draw S.F.D & B.M.DStress under footing = 195 *1.8 = 351 kN/m

35 Check for beam shear b = 1800mm, d = 630mm

36 Bending moment Long direction Design Short direction as example 1 (lecture 11)

37 Reinforcement details

38 Mat Foundation

39

40 Check for punching Shear

41 Modified load General Example, Ref. 2

42 General reinforcement details


Download ppt "Check Beam Shear. Bending moment design Short direction 245 166 2.5m."

Similar presentations


Ads by Google