Presentation on theme: "Environmental Challenges – Pulp & Paper Industry"— Presentation transcript:
1Environmental Challenges – Pulp & Paper Industry Program for North American Mobility in Higher Education Introducing Process Integration for Environmental Control in Engineering CurriculaModule 4: Tier IIIEnvironmental Challenges – Pulp & Paper IndustryCreated at:École Polytechnique de Montréal &Texas A&M University, 2003
2LEGEND Go to the web site Go to next subject More information on the same subjectLook for the answer to the question
4Tier III: Statement of Intent The purpose of this is to provide students with an open-ended problem which assimilates the concepts of minimum impact manufacturing including process integration and LCA .
5Problem Statement for Q-1 & 2 You are an environmental engineer in a pulp and paper mill. The head office wants to enhance its competiveness by putting together a technology roadmap with the ultimate goal to be a minimum impact manufacturing mill.Some information about the mill is given at the following page.
6Mill DescriptionConventional pulping technology, ECF bleaching, drying, activated sludge plantDebarking: dryLime kiln: normalLime kiln fuel: heavy fuel oilLime kiln flue gas: high eff. ESPBark boiler (HW bark):Total efficiency 0.87Fluidized bed boilerElectric power generation from excess heat in mill condensation turbineSince no information is available concerning the effluent treatment plant, its efficiency will be consider constant. As a consequence of that, from a relative point of view, the effluent ion loads can be considered proportional to the ones before the effluent treatment.
7Question 1A few months ago the company ordered a partial LCA study in order to have an idea about its life cycle environmental impacts. As a first step, your boss had asked you to look at this study as well as at the mill simulation and give him your recommendations for environmental improvement. To do this look at unit process contribution to each impacts and perform sensibility analysis. Do not use any normalization or weighting. Without doing calculations, you can also use cost arguments. Also determine, by mass balances by how much fresh water can be theoretically reduced (by recycle).System boundaries are defined in the LCA study and the main hypothesis are presented next pages.
8Functional UnitAll LCA results are presented relative to the functional unit. The functional unit has been defined as follow:The production of 1 admt of pulp.
9Chemical ProductionChemical production as been included into the system boundaries. Chemicals are considered to be transported an average distance of 100 km using 40 ton diesel trucks and empty trucks return to the supplier. For calculation purpose a weight of 1/10 of the transported chemicals has been assumed for the return of the truck.No data was available for talc manufacturing. Therefore it has been excluded from the system boundaries. However, its transportation has been considered.
10Birch Growth and Harvesting Birch growth and harvesting as been included in the boundaries. The wood is transported an average of 100 km. The same assumptions as for chemicals apply.
11Others By product have been located. A credit has been considered for the generated energy (but only on the energy).Pulp is transported an average distance of 200 km to the customer (same assumptions as chemicals).Industrial landfill is located 5 km from the mill. 16 ton diesel trucks are used to transport the solid wastes, the return of the trucks is considered negligible.
12Necessary documentsLCA Base CaseProcess Simulation
13Question 2Your boss is convinced that most of the competitive advantages that can be gained with environmental improvements are related with fresh water reduction.In this case, recycling the effluent water is the most obvious way to reduce fresh water consumption, but this can result in the build-up of non-process elements and so reduce process performance.For this reason, he has also mandated a consulting company to perform a water pinch study subject to process constraints.
14Question 2 (Cont’d)The consultant has first evaluated possibility of direct recycle because it does not implicate major capital costs. Major results are presented in the following table.Water Consumption23% reductionLiquid EffluentReduction of ion content of 2.3%Gas EffluentCl, K: 0.2% increaseNa: 6.8% increaseEnergy produced5% reduction (need more energy to pump)Dust13.4% increaseSolid wastesNeglictible difference
15Question 2 (Cont’d)Using the LCA model, discuss if this represents a real environmental improvement. To compare results, normalize against the base case.A panel of experts has determined that the importance of each impact category can be described by the weights in the following tables. Resources and emissions are weighted separatly.What is the influence of the weights on the final decision.
17Solution – Q1The process simulation does not give a lot of insights on the environmental impacts of the process. However it is obvious that the bleaching plant consumes a lot on fresh water and rejects a lot in the environment. The following is the solution for potential water reduction
18Solution – Q1 (Cont’d)Water balances can be summarized by this picture.The total fresh water consumption is =34.79 ton/ton of dry pulp.Only liquid water can be “directly” recycle: = ton/ton of dry pulp.For mass conservation reasons, only the min of fresh water or liquid effluent can be recycle ie ton.So the minimum water consumption is =6.56 ton (ie a reduction of 81%).
19Solution – Q1 (Cont’d)The following graph show the contribution of each process unit to resource consumption.
20Solution – Q1 (Cont’d)The last figure show that the manufacturing activities consumes a lot of resources: water, virgin fiber and other natural resources.It also shows that chemical production is particularly energy-consuming.From a first look, reducing chemical and water consumption will result in a significant environmental benefit.
21Solution – Q1 (Cont’d)The following graph show the contribution of each process unit to emission-related environmental impacts.
22Solution – Q1 (Cont’d) From this graph it is possible to note that: Manufacturing activities are a large contributor to acidification, eutrophication, winter smog and solid wastes;Chemical production is a large contributor to all impact categories but more specifically eutrophication, heavy metals and summer smog.Transportation seems also to be a large contributor to several impact categories: global warming, carcinogenic substances and summer smog.Global warming is due to almost all unit processes.
23Solution – Q1 (Cont’d)Even if it is impossible to talk about the relative importance of each impacts since no weighting has been performed, it is clear from the last two graphs that manufacturing activities, including chemical consumption must be targeted in order to reduce the overall environmental impacts. Transport is also a significant contributor.The following results show how much a 5% reduction in transportation and chemical consumption will affect the environmental impacts. Manufacturing is more difficult to assess but the impact of an increase of 5% of the yield (from 50% to 52.5%) is also presented. It as been assumed that an increased yield will only impact the quantity of wood required and not the chemical consumption in order to keep both effect separate.
24Solution – Q1 (Cont’d)It is important to note that here only easily manipulable variable have been modified in order to determine which changes will influence the more the environmental impacts.The most important results are the following:A 5% increase in the yield will result in a:5.64% reduction in fresh water consumption;4.70% reduction in virgin fiber consumption;4.39% reduction in natural resources consumption.A 5% reduction in transportation will result in a:4.86% reduction in energy consumption;4.26 reduction in carcinogenic substances.A 5% reduction in chemical will not affect significantly the environmental impacts.
25Solution – Q1 (Cont’d)As an environmental engineer, you will propose the followings:Increase the process performance, which will also reduce costs.Since reducing transportation distance is not easily realizable, you suggest to find a mode of transportation less pollutant.Even if a reduction of chemical consumption will necessarily reduce the cost, it is not an environmental priority.The mass balances have shown that there is a lot of potential for fresh water reduction.
27Solution - Q2 (Cont’d)The last graph shows the LCA results (resources) for the direct water recycle option. The results have been normalized against the reference case. From this graph, it is possible to say that:Raw water consumption from the manufacturing process unit has been reduced to 70% of the reference case.Energy consumption by the manufacturing has been increase by 5%.Everything else is constant.
29Solution - Q2 (Cont’d)The preceding graph shows a reduction in the following impact categories:Acidification from the manufacturing process unit.It also shows an increase in:Winter smog from the manufacturing process unit.All the remaining impact categories are almost constant.
30Solution - Q2 (Cont’d) The aggregated indicators are: Resources: 0.76Emissions: 1.00From this it is possible to conclude that the direct water recycle solution has a positive impact on the resource impact categories (almost 25% improvement) and almost no impact on the emissions.
31Weight of the raw water consumption Solution - Q2 (Cont’d)A lot of importance has been given to the raw water consumption. A sensitivity analysis on the weights has been conducted. First, weight of raw water has been decreased while maintaining the other relative weights constant.The results are presented in the table. It can be seen than even if the raw water importance passes from 83% to 10%. There is still an environmental benefit.Weight of the raw water consumptionAggregated Indicator0.830.760.500.850.300.910.100.97
32Solution - Q2 (Cont’d) Weight of the Energy Aggregated Indicator 0.08 The impact category the most influenced by the direct recycle other than raw water is the energy.By increasing the weight of energy while maintaining the other ratios constant we obtain the results presented in the table.The conclusion of the 2 tables is that the environmental improvement is robust to the weights.Weight of the EnergyAggregated Indicator0.080.760.160.780.320.820.640.900.830.96
33Weight of the Acidification Solution - Q2 (Cont’d)The same strategy has been applied to the emission impact categories. Sensitivity analysis have been conducted on the acidification and winter smog weights.Acidification has been reduced so the sensitivity analysis try to determine if more weight on this impact category will reduce significantly the aggregated indicator.The table shows that even if acidification weight passes from 1% to 80% this will results in only 2% improvement.Weight of the AcidificationAggregated Indicator0.011.000.100.200.400.990.800.98
34Weight of the Winter Smog Solution - Q2 (Cont’d)Winter smog has been increased so the sensitivity analysis try to determine if more weight on this impact category will increase significantly the aggregated indicator.The table shows that even if winter smog weight passes from 7% to 80% this will results in only 1% degradation.The 2 previous tables show that the emissions indicator is robust to the weights.Weight of the Winter SmogAggregated Indicator0.071.000.140.280.560.801.01
35Solution - Q2 (Cont’d) Overall conclusion: Direct water recycle results in a positive resource saving (24%) without compromising the other impact categories.Furthermore, it is a low cost solution.In consequence, its implementation is highly recommended.
36Problem Statement – Q3-7Consider the following Kraft pulp mill depicted belowwashpulpwaterchipsDEDEDscreeningBrown Stock WashingTo papermakingDigesterFlueRecovery BoilerGasconcentratorcond.cond.SBLweaksmeltESPblack liquorMultiple Effect Evaporatorssaltcakedust recyclewhite liquorwashwaterlimefluegasmudweak white liquordissolvingwashtankmudlime kilnwaterdregswhite liquorfiltermuddregsclarifierwasherwasher& filtergreen liquor clarifiercausticizergritsslaker
37Problem Definition Chips = 6000 tons (wet basis) Moisture = 50% = 0.5*6000 t = 3000 tPulp Yield = 50 % of Dry = 0.5 * 3000 tConsistency (CY) = 0.12Dilution Factor (DF)= 2Wash Water for Pulp = [(1-CY)/CY] +DFIon Content of Process Water:Cl = 3.7; K = 1.1; Na = 3.6 (values in ppm)
38Problem DefinitionGiven this Kraft pulping process, it is desired to develop cost-effective strategies for the reduction of water discharge from the mill. It should be noted that any water reduction objectives will entail the use of recycle; consequently, various species will build up in the process, leading to operation problems.
39Problem DefinitionTo alleviate the detrimental effect of build-up, comprehensive mass integration strategies are required to provide answers to the following questions:What are the rigorous targets for reduction in water usage and discharge?Which streams need to be recycled? To which units?Should these streams be mixed or segregated?What interception devices should be added to the process? To remove what load?What new research needs to be developed to attain the optimum solutions?Q3 – 7 will address some of these questions
40Question 3What are the rigorous targets in water discharge and reduction?
41Species Tracking Model Before one can begin to tackle the water targeting problem, it is crucial to develop a species tracking model of the system with the right balance in details.A too-simplified model will not adequately describe the process nor will it capture critical aspects of the process.A too-detailed model cannot be readily incorporated into the process integration and optimization framework and will negatively impact the effectiveness of the optimization computations.
42Species Tracking Model In order to develop the species tracking module, we will make use of path diagram equations, perform degrees of freedom analysis, and use the mixer splitter models. These topics were covered in Module II, though they are included here as a quick referencePath Diagram EquationDegrees of FreedomMixer-Splitter Model
43Mathematical Modeling The modeling techniques covered in module II allow one to describe unit performance without requiring detailed models while still capitalizing on nominal plant data and knowledge about the process. With this information, one can begin to make choices for the selected model and streams/species.Consider the following unit:
45Mathematical Modeling W and P refer to the loads of water and a pollutant, respectively.Suppose that the load of the water were to change as a result of process improvement (e.g. mass integration). The load of the pollutant will be affected as well; thus, it will be necessary to determine the new load of the pollutant.Furthermore, suppose that there exists a proportional relationship between the pollutant loads in streams 2 and 3 (much more so than between streams 1 & 3, 1 & 4, etc).
46Mathematical Modeling With this knowledge, the ratio model can be used to relate the pollutant loads in streams 2 and 3:P3new = (P3old/ P2old) * P2newThe pollutant load in stream 4 can then be determined by a simple component material balance:P4new = P1new + P1new + P3new
47Nominal Balance ModelBy using these modeling techniques, path equations can be developed for tracking water and targeted NPE’s throughout the process, resulting in a mathematical model for the nominal case study. The nominal case study can then be revised to reflect the impact of mass integration on the process.
48Nominal Balance ModelFor this case study, the nominal balance model will be developed with the purpose of tracking water and three nonprocess elements, chloride, potassium, and sodium. These ions were selected because they are among the most important species that cause buildup problems and limit the extent of mass integration
49Nominal Balance ModelUsing process knowledge, nominal plant data, modeling techniques, initial assumptions, etc., one can begin to develop the nominal balance model unit by unit.The overall result for the nominal balance model will be provided at this time. However, the full development of the nominal balance is provided at the end of this module for the reader’s understanding.Nominal Balance
51Back to Question 3What are the rigorous targets in water discharge and reduction?The objective here is to minimize the amount of fresh water used in the process and the amount of wastewater discharged from the system.
52Solution – Q3Beginning with the nominal balance model (figure ), the first step is to identify all possible sources of water entering, leaving or being consumed in the process in order to obtain the overall water balance for the process, as depicted in next figure
53OVERALL WATER BALANCE OVERALL Water Balance Screening = 1450 MEE = 8901Chips = 3000OVERALLWater BalanceStripper = 1024Washer = 13995ESP = 1202Screening = 1450Washer/Filter dregs = 4Lime Kiln = 423Washers/Filters = 5762Slaker grits = 8Bleach Plant = 30990Slaker = 32Water consumedBy reaction = 168BP water = 30990Pulp leaving Bleach Plant = 10995Total Water In =55197 – 168 = tpdTotal Water Out = tpd
54Solution – Q3Next, all streams that use fresh water and all streams that contain potentially recyclable water are identified.There are four fresh water streams (S2, S6, S24 and S34) giving a total fresh water use of 52,197tpd.There are also four potentially recyclable streams, S8, S10, S12 and S37 giving a total of 42,365 tpd.The overall water balance diagram has been modified to reflect this information (see figure )
55FRESH AND RECYCLABLE WATER BALANCE Screening = 1450MEE = 8901Water BalanceWasher = 13995Stripper = 1024Screening = 1450Washers/Filters = 5762Bleach Plant = 30990Water consumedBy reaction = 168BP water = 30990Total Fresh Water in = tpdTotal recyclable water out = tpd
56Minimum water consumption = Solution – Q3If the recyclable water can be intercepted and cleaned up to the point where it is acceptable for use in place of fresh water and if self-recycle is allowed, then one can determine the target for fresh water usage:Minimum water consumption =52197 – = 9832 tpd
57Solution – Q3By adding up the flowrates of the water streams leaving the process except the recyclable streams (S8, s10, s12, s37) and water in the produced pulp, we get a target for wastewater discharge of 1,669 tpd
58OVERALL WATER TARGETING FOR CASE STUDY WastewaterChipsW1 = 3000Target = 1669tpdW2 = 13995Water Consumed168Fresh WaterW6 = 1450Target = 9832Water going out with pulp10995tpdW24 = 5762WtoBP= 30990Target for minimum water consumption = 52,197 – 42,365 = 9,832 tons per day
59Solution – Q3 Therefore, the rigorous targets are: Minimum Fresh water target = 9832 tpd Wastewater target = 1669 tpd
60Limitations on Self-Recycle Previously, it was permitted to consider recycling the effluent back to the same unit. However, self-recycle may sometimes be forbidden due to numerous reasons such as:To prevent the build-up of impurities in a flow loopTo avoid dynamic instabilities that may arise due to the high interconnectivity between the input and outputTo enhance process reliability by disengaging the dependence of the input from the output.
61Limitations on Self-Recycle If self-recycle is not allowed, then it is possible that the targets identified earlier may not be reached even if interception technologies are used to clean up the recyclable water streams. As a result, new targets will need to be determined, which leads to the next question:
62Question 4aIn the case of no self-recycle with one interceptor, which streams can be intercepted?
63Solution Q4a There are four recyclable streams for consideration: W8 – MEEW10 – ConcentratorW12 – ScreenW37 – Bleach plant effluentIn the development of the nominal balance model, it was assumed that there were no ions in the water leaving the MEE and Concentrator (i.e. it has the same quality as demineralized water); therefore, the only interception candidates are the screen and bleach plant effluents.
64Question 4bChoosing the bleach plant effluent for interception and assuming that the quality of the screen effluent is acceptable for direct recycle to the pulping process, what are the new water targets (remember, no self-recycle)?
65Solution Q4bThe flow of the intercepted bleach plant effluent, along with the screen effluent is more than enough to replace all of the fresh water used in the pulping process. Therefore, the fresh water target for the pulping process is zero.For the bleach plant, only water meeting dimineralized quality can be used. Thus, the effluents from the multiple effect evaporator and the concentrators can be used, replacing a total of 9925 tpd of BPE.
66Solution – Q4b 13995 + 5762 + 1450 = 21207 Wastewater To bio =30990 – 19757= tpdFresh water = tpdBleachinterceptionW2 = 13995PULPINGW8 = 1450W6 = 1450Consumption byChemical Reactionand other losses= 9832 tpdW24 = 5762W10 = 8901W12 = 1024= 21207
67Solution Q4b The new targets are now: Pulping process fresh water: 0 tpdBleach Plant Effluent fresh water target:30990 – ( )= tpdWastewater target:30990 – = tpd
68Process Integration Strategies The overall targeting has identified that fresh water consumption can be significantly reduced from tpd to 9832 tpd.The next step, then, is to determine how this can be accomplished. What is the optimal strategy for water reduction? How are the streams to be allocated? This cannot be easily perceived simply by looking at the process flowsheet.Process integration strategies will be employed to determine the optimal ways of reaching the target
69Why Process Integration? Process Integration is a holistic approach to the design and operation of complex systems. It is a sound framework that utilizes well-developed and proven mass and energy integration techniques for optimizing the design and operation of a process.
70Process IntegrationIt is important to coordinate both process integration and process simulation. The application of process integration provides performance targets, solution strategies, and proposed changes to the process. Process simulation reassesses the process performance as a result of theses changes.
71Coordination of Process Integration and Simulation Process Objectives, Data and constraintsProcess ModificationsStructural changesProcessSimulationProcessIntegrationInput/Output relationsNew ProcessesClosing the information loop of integration andsimulation ensures that the developed insightsand solution strategies are refined and validated.
72Mass Integration Strategies Now that the rigorous targets have been developed for the minimum feasible water usage and discharge, various cost-effective mass integration strategies should be used to attain the targets. These strategies includeSegregation,Low cost/no cost modifications,Direct recycle,Interceptionhigh cost process modifications.The above strategies can be represented as a pyramid (see next slide), where it is desired to begin at the bottom of the pyramid, which represents the lowest cost and perhaps more easily implemented strategies, and work up until the target is achieved.
73Mass Integration Strategies TargetChemical ProcessHCPMInterceptionMixing & RecyclingLow Cost Process Modifications(LCPM)Segregation
74SegregationSegregation refers to avoiding the mixing of streams. In some industrial applications, dilute streams have been mixed with concentrated streams and even different phases have been mixed together unnecessarily. Segregation of streams at the sources can provide several opportunities for cost reduction such as:Generate environmentally benign streamsEnhance the opportunities for direct recycle since dilute streams are easier to recycle.The separate concentrated streams are now more thermodynamically favorable for interception
75Low-cost process modifications In some cases, a change in process conditions (such as temperature, pressure, compositions, etc) may be all this is needed to decrease or eliminate the waste produced in a unit.Provided that the cost is low, a unit can be replaced with a more environmentally benign one.
76RecycleDischarged waste can be reduced by recycling pollutant-laden streams back to the process to be utilized in process or non-process requirements. In some instances, several streams need to be mixed with each other to achieve the desired level of flowrate and composition.
77InterceptionInterception refers to the utilization of separation techniques to selectively remove targeted species from targeted streams. In most industrial applications, inteception is needed to enhance the opportunities of recycling and to generate environmentally benign streams.
78High-Cost Process Modifications After all other strategies have been exhausted, one may need to employ high cost process modifications. This may include completely new chemistry (such as new solvent or new reaction path), new technology (new plant), etc.
79Question 5What is the optimal water allocation using direct recycle?
80Solution – Q5To answer this question, a mass allocation representation of the process from the species viewpoint needs to be developed.For each species, there are sources, those streams that contain the desired species, and sinks, those streams units which can accept the species.Each sources can be segregated, intercepted to adjust species content, mixed, etc and allocated to the different units or sinks, as depicted in the following figure.
81Spriggs and El-Halwagi, 1998, SOURCE-INTERCEPTION-SINK REPRESENTATIONMass & Energy Separating Agents InSinksSegregatedSourcesSource i = 1j = 1SpeciesInterceptionNetwork(SPIN)j = 2Source i = NsourcesFresh Sourcej = Nsinks(e.g., El-Halwagi et al., 1996,Spriggs and El-Halwagi, 1998,Dunn and El-Halwagi, 2003)Mass & Energy Separating Agents Out
82Process SinksThere are a number of process units, or Nsinks,that employ fresh water and are designated by the index j (j ranges from 1 to Nsinks).Each jth sink has two sets of contraints on flowrates and composition:Flowrate to each sinkWjmin Wj Wjmax j = 1, 2,….,NsinksWj is the water flowrate entering the jth sinkIon content to each sinkYion,jmin Yion,j, Yion,jmax j = 1, 2,….,NsinksYion,j is the compostion of a certain NPE entering the jth sink
83Process SinksEach source, represented by I, is split into Nsink fractions that can be assigned to various sinks. The flowrate of each split is denoted by li,j (see figure)Each split fraction then has the opportunity to be mixed (or not) and assigned to sinks (see figure)
84SPLITTING OF SOURCES TO SINKS Yion,ili,jSplitting of the ith source:where i = 1,2, …, Nsources
85MIXING OF SOURCES BEFORE SINKS WjYion,jli,jyion,jjMixing for the jth sink:where j = 1,2, …, Nsinks
86Direct Recycle Strategy For this case study, four sources have been identified: Bleach Plant effluent, Screen effluent, Multiple Effect Evaporator effluent and Concentrator effluent. Fresh Water is included since it is the objective function of the optimization problem (where the objective function is to minimize the flowrate of fresh water via direct recycle).Four sinks have been identified: Screening, Brown Stock Washer, Washer/Filters, and the Bleach Plant. Waste Treatment is also be included since it is possible that the best allocation for a source may be biotreatment.The following figure shows the assignment representation for the Direct Recycle/Reuse problem
88Min. flowrate of fresh water = Direct Recycle Optimization Formulation for Source/Sink Analysis w/Path ConnectionThe problem can now be formulated as an optimization problem, where the objective function is the minimization of the flowrate of fresh water. This objective funtion can be represented as:Min. flowrate of fresh water =Subject to the following constraints
89Direct Recycle Optimization Formulation for Source/Sink Analysis w/Path Connection Flowrate to each sink:j = 1, 2, …, NsinksNPE content in feed to each sink:j = 1, 2, …, Nsinks and k = 1, 2, …, NkSplitting for the ith source:i = 1, 2, …, NsourcesMixing for the jth sink:j = 1, 2, …, NsinksComponent material balances for the pollutants:j = 1, 2, …, Nsinks and k = 1, 2, …, NkNon-negativity of each fraction of split sources:i = 1, 2, …, Nsources and j = 1, 2, …, Nsinks
90Direct Recyce/Reuse Optimization formulation It should be remember that no self-recycle is permitted and that the bleach plant c,an only accept dimineralized water.Furthermore, there is an additional issue with respect to the build-up of NPE’s in the recovery furnace which is affected by “sticky temperature”. It is related to Cl, K, and Na through the following constraints where Ci, Ni, and Ki, are the ionic loads of Cl, Na and K, respectively, in the ith source:
91Optimization Solution for Direct Recycle/Reuse LINGO programming was used to develop and solve the mathematical formulation. The optimal water allocation is depicted in the following slide.The fresh water to screening has been replaced with 751 tpd of concentrator effluent and 699 tpd of bleach plant effluentThe fresh water to the washers/filters has been replaced with 273 tpd of concentrator effluent and 5489 tpd of MEE effluent.A portion of the fresh water to the Brown Stock Washers has been replaced with 3412 tpd of MEE effluent and 1450 tpd of screening effluent.
92Optimum Solution for Direct Recycle/Ruse 913330990BSWScreeningBleach1450WoodChips751699302913412Digester5489273ESPStripperStripperWhiteLiq. Clarif.MEEConcent.RecoveryFurnaceLimeKilnDissolvTankCausticizerWashers/FiltersGreenLiq. Clarif.Slaker
93Results of Direct Material Exchange The fresh water consumption has been reduced to 40,123 tons per day, a 23% reduction from the nominal fresh water usage of 52,197 tons per day.This solution is a direct recycle/reuse which requires piping and pumping but involves no capital investment for new processing units.It should be noted that the mathematical solution can generate alternate solutions that yield the same fresh water consumption but require different piping and allocation alternatives.
94Question 6Through direct recycle, fresh water usage went down from to However, from water targeting, we know that interception can get the fresh water usage down to tpd.Consider the interception of the bleach plant effluent. How much Cl must be removed in order to meet meet the fresh water target of tpd?
95Solution – Q6In this problem, the objective function has changed from one of minimizing the fresh water consumption to one of minimizing the load of the Cl to be removed from the bleach plant effluent subject to:Desired water targetPath equations for tracking water and ClRecycle ModelInterception equationsUnit constraints
96Solution – Q6Basically, this problem is just like the recycle problem except that the objective function has changed. We know that the fresh water target is now tpd and that approximately tpd of intercepted bleach plant effluent is being recycle back to the process. Thus, in order to minimize the load to be intercepted from the BPE, a target has to be set for the maximum recyclable flowrate of the bleach plant effluent (the tpd).
97Solution – Q6Again, LINGO programming was used to solve the mathematical formulationA total of 8.99 tpd of Cl must be removed from the bleach plant effluent.The fresh water consumption has been reduced to tons per day, a 60% reduction from the nominal fresh water usage of 52,197 tons per day.
98Exploring other interception opportunities So far, only terminal streams (those streams going directly to waste treatment) have been considered. However, it is possible that other inter-process streams may be intercepted, perhaps providing greater economical and environmental benefits.A literature search reveals that salt removal technologies exist for other kraft units, among those:White Liquor InterceptionGreen Liquor InterceptionOf course, this leads to the next question:
99Question 7 How much chloride needs to be removed from Case 1: Green LiquorCase 2: White Liquorin order to meet the fresh water target?
100Interception Alternatives This is quick and easy to determine. The objective function will remain the same (minimize chloride removal) as in Q6 but rather than minimizing the Cl removal from the bleach plant effluent, it will be minimized from the white liquor or green liquor streams. Thus, the optimization program only needs to be slightly altered to reflect the stream in question.Interestingly enough, though it should come as no surprise, the load removal for Green Liquor and White Liquor interception is the same as the case for Bleach Plant interception (approx. 9 tpd of Cl). However, the three solutions are not identical. Each one has a different configuration of optimal water allocation (see figures)
101Optimum Solution for Bleach Plant Interception 913330990BSWScreeningBleach1450WoodChips751699302913412Digester5489273ESPStripperStripperWhiteLiq. Clarif.MEEConcent.RecoveryFurnaceLimeKilnDissolvTankCausticizerWashers/FiltersGreenLiq. Clarif.Slaker
102Optimum Solution for Green Liquor Interception 913330990BSWScreeningBleach1450WoodChips751699302913412Digester5489273ESPStripperStripperWhiteLiq. Clarif.MEEConcent.RecoveryFurnaceLimeKilnDissolvTankCausticizerWashers/FiltersGreenLiq. Clarif.Slaker
103Optimum Solution for White Liquor Interception 913330990BSWScreeningBleach1450WoodChips751699302913412Digester5489273ESPStripperStripperWhiteLiq. Clarif.MEEConcent.RecoveryFurnaceLimeKilnDissolvTankCausticizerWashers/FiltersGreenLiq. Clarif.Slaker
104Life Cycle AnalysisBut which of the three technologies is the better solution?
106Return to the flowsheet Path Diagram EquationTypically, the Path Diagram Equation defines outlet flows and compositions from key units as functions of inlet flows, inlet compositions and process design and operating conditionsThis mass integration tool tracks the targeted species as they propagate through the system and provide the right level of details that will be incorporated into the mass integration analysisReturn to the flowsheet
107(Fresh inputs or outlets from other units) Degrees of FreedomAssumptions:All inlets to a unit are known and it is desired to determine the outputs of the unit.F must provided as additional modeling equations, assumptions, measurements, or data in order to have an appropriately specified (determined) set of equations that is solvable.NV = NS x NCF= NV - NE = NC (NS - 1)F: degrees of freedomNV: number of variablesNE: number of equationsNC: number of targeted speciesNS: number of outlet streamsUnit UInlet stream(Fresh inputs or outlets from other units)Outlet streamsNstreams outReturn to the flowsheet
108Return to the flowsheet Mixer-Splitter ModelThe mixer-splitter model is a modeling technique which relies on nominal data .The nominal data are those for the plant prior to any changes and can be obtained via simulation, fundamental modeling, direct measurements, or literature data.There are various of the mixer splitter model:Fixed split model;Flow ratio model ;Species ratio model.Based on the knowledge of the process, choices can be made for the selected model and streams/species.Path equations can be developed for water and targeted NPEs throughout the process.Return to the flowsheet
109Return to the flowsheet Fixed Split Flow ModelFixed SplitModelα * FF(1 – α) * FThe Fixed Split model takes a certain split, α, for the flows of streams leaving the unitReturn to the flowsheet
110Gnew = Gold * ( Fnew / Fold ) Return to the flowsheet Flow Ratio ModelFlow RatioModelGFGnew = Gold * ( Fnew / Fold )The Flow Ratio model assumes that streams or components maintain a certain fixed ratio. Thus, if the flow rate of a certain stream increases or decreases, all other related streams adjust according to the same ratio.Return to the flowsheet
111IInew = Inew (IIold/ Iold ) Return to the flowsheet Species Ratio ModelSpecies RatioModelGFI = species 1II = species 2IInew = Inew (IIold/ Iold )Similar to the Flow Ratio Model, the Species Ratio Model maintains a fixed relationship between species in related streams. Thus, if one species changes, the other one adjusts by the fixed ratio. This model is especially useful if one species can be accurately tracked whereas the other one cannot.Return to the flowsheet
112Initial Data - Digester Assumption: all inlet streams are known.Flowrate of wood chips, Chips = 6000 tpdMoisture content of wood chips = 50%Pulp Yield = 50%Pulp = Dry Chips * YieldMass fraction ions with incoming wood chips:C1 = 1 * Chips/6000K1 = 2.50 * Chips/6000N1 = * Chips/6000Return to the flowsheet
113Initial Data – Brown Stock Washer Composition of ions in incoming wash water:Cl = 3.7 ppmK = 1.1 ppmNa = 3.6 ppmConsistency of pulp leaving Brown Stock Washer, CY = 0.12Dilution Factor, DF = 2.0Ratio of ions in slurry leaving the BSW to the chloride in the pulp stream leaving the digesterCl = 0.050K = 0.020Na = 0.009Return to the flowsheet
114Digester S2 Brown Stock Washer S4 S1 Digester S5 S3 W2 (from consistency)S2C2 (from comp of Cl in wash water)K2 (from comp of K in wash water)N2 (from comp of N in wash water)BrownStockWasherS4W4 (from dilution factorC4 (from ratio to C5) = 0.05*C5K4 (from ratio to K5) = 0.02*K5S1N4 (from ratio to N5) = 0.009*N5DigesterW1 (from moisture contentC1 (from comp of Cl in chips)S5K1 (from comp of K in chipsN1 (from comp of N in chipsW5C5S3K5N5All species data will be calculated as anoutput stream from white liquor clarifier
115Digester W1 = Moisture*Chips=0.5*6000=3000 W4 = [(1-CY)/CY]*Pulp=[(1-.82)/(0.82)]*3000DF = (W2 - W4 )*Pulp; DF is given as 2W2 can be determined from after W4 has been calculated.Ion Content in streams 2 and 4:C2 = (3.7*10-6) *W2; C4 = 0.05*C5K2 = (1.1*10-6) *W2; K4 = 0.02*K5N2 = (3.6*10-6) *W2; N4 = 0.009*N5Recalling the assumption that all inlet streams are known, thenstream 5 will need to be determined. The number of unknowns isour (flowrate of water and the three ions in S5); these can be obtainedVia the four material balances for the 4 speciesW5 = W1 + W2 + W3 – W4C5 = C1 + C2 + C3 – C4K5 = K1 + C2 + K3 – K4N5 = N1 + C2 + N3 – N4
116Multiple Effect Evaporator 80% of the water in the weak black liquor is evaporated (water recovery ratio is 0.8).It is assumed that no ions are in the condensate of the multiple effect evaporatorsThe material balances can be used to calculated the concentrated stream leaving the multiple effect evaporatorsW10 = Water recovery in evaporator * W5W9 = W5 - W10C9 = C5 - C10K9 = K5 - K10N9 = N5 - N10
118Multiple Effect Evaporator 46% of the water in the black liquor entering the concentrators is evaporated (water recovery ratio is 0.46).Again, it is assumed that no ions are in the condensate of the multiple effect evaporatorsThe material balances can be used to calculated the concentrated stream leaving the multiple effect evaporatorsW12 = Water recovery in concentrator * W9W11 = W9 - W12C11 = C9 - C12K11 = K9 - K12N11 = N9 - N12
119Concentrator Condensate Evaporator Concentrate W12 = Water Recovery * W9C12 = 0Concentrator CondensateK12 = 0N12 = 0S9S11Evaporator ConcentrateConcentratorStrong Black LiquorW9C9K9N9W11C11K11N11
120Recovery Furnace and Electrostatic Precipitator (ESP) It is assumed that all the water in the strong black liquor leaves with the ESP off-gas so W15= W11.The ions in the solids return, ESP dust and off-gass are related to the ions in the strong black liquor stream:C13 = 0.278*C11; C14 = 0.048*C11; C15 = 0.02*C11K13 = 0.498*K2; K14 = 0.028*K11; K15 = 0.008*K11N13 = 0.154*N2; N14 = 0.002*N11; N15 = *N11
121Recovery Furnace and ESP The component material balance around the ESP is:W13 - W14 - W15 - W16 = 0.0C13 - C14 - C15 - C16 = 0.0K13 - K14 - K15 - K16 = 0.0N13 - N14 - N15 - N16 = 0.0It is assumed that the saltcake has a makeup flow of * Pulp. Knowing this and the molecular formula for saltcake,N18 = 2*23/142 * SaltcakeThe content of Cl and K in the saltcake is obtained by assuming ratios to Na in the saltcake. In addition, there is virtually no water in saltcake.W17 = 0.0W18 = 0.0C18 = 0.01*N18K18 = *N18
122Recovery Furnace and ESP The ion content in the smelt is determined via component material balance around the Recovery Furnace and ESPC11 + C18 - C15 - C14 - C17 = 0.0K11 + K18 - K15 - K14 - K17 = 0.0N11 + N18 - N15 - N14 - N17 = 0.0
123SmeltThe smelt flowrate consists of the saltcake + solids in strong black liquor (SBL) – solids lost with the purge streams (S14 and S15) – solids volatilized in the furnace. Assuming that 5% of the solids in the SBL leave the ESP in the flue gas and that 47% of the SBL solids are volatized in the furnace:Smelt = Saltcake + SBL – 0.05*SBL – 0.47*SBLOrSmelt = Saltcake *SBL
124Recovery Furnace and Electrostatic Precipitator (ESP W15 = W11S15C15 (from ratio to C11)K15 (from ratio to K11)Off-gasS14N15 (from ratio to N11)Dust PurgeW14 = 0S11ESPC14 (from ratio to C11)K14 (from ratio to K11)Strong Black LiquorN14 (from ratio to N11)W11C11K11N11RecoveryFurnaceS17SmeltS18Salt Cake = *PulpW17C17W18 = 0K17C18 (from ratio to N18)K18 (from ratio to N18)N17N18 = * Salt Cake
125Dissolving TankThe dissolving water-to-smelt ratio used in the dissolving tank is typically 85/15W19 = (85/15)*SmeltThe ionic content of S19 is determined by assuming ratios of Cl and K to those in the smelt and Na to the white liquorC19=0.136*C17K19=0.136*K17N19=0.196*N3Component material balances around the dissolving tank are used to evaluate the ionic content of the feed to the green liquor clarifierW20 - W17 - W19 = 0.0C20 - C17 - C19 = 0.0K20 - K17 - K19 = 0.0N20 - N17 - N19 = 0.0
126Dissolving Water = (85/15)*Smelt Feed to green liquor clarifier Dissolving TankS17SmeltW17C17K17N17S19DissolvingTankDissolving Water = (85/15)*SmeltW19 = 5.67 * SmeltC19 (from ratio to C17)K19 (from ratio to K17)S20N19 (from ratio to N17)Feed to green liquor clarifierW20C20K20N20
127Green Liquor Clarifier Typical overflow ratios were used to obtain the flows and ion concentrations in the overflow and underflow stream.W21=0.992*W20C21=0.863*C20K21=0.880*K20N21=0.968*N20Component material balance can then be written around the green liquor clarifier:W22 - W21 - W20 = 0.0C22 - C21 - C20 = 0.0K22 – K21 - K20 = 0.0N20 - N21 - N20 = 0.0
128Green Liquor Clarifier S20Feed to green liquor clarifierW20C20K20N20S21Green LiquorClarifierDust OverflowW21 (from ratio to W20)C21 (from ratio to C20)K21 (from ratio to K20)S22N21 (from ratio to N20)UnderflowW22C22K22N22
129Washer/Filter SystemThe dregs leaving the washer/filter system contains very little water and is determined by relating it to the water content in the underflow from the GLC. The ion content in the dregs is determined by assuming ratios of the ions to the water in the dregsW23 = 0.075*W22C23 = 0.010*C22K23 = 0.001*K22N23 = 0.250*N22The overflow from the white liquor clarifier is determined by assuming a ration to Green Liquor overflowW32 = 0.160*W21C32 = 0.237*C21K32 = 0.016*K21N32 = 0.156*N21
130Washer/Filter System W24 = 0.9*W19 The wash water is assumed to be 90% of the smelt dissolution water and the ionic content for C, K and N is based on the typical values of 3.7, 1.1, and 3.6 ppm, respectivelyW24 = 0.9*W19C24 = (3.7*10-6) *W24K24 = (1.1*10-6) *W24N24 = (3.6*10-6) *W24Component material balances can then be written for the washer/filter systemW22 + W24 + W32 - W19 - W23 - W25 = 0.0C22 + C24 + C32 - C19 - C23 - C25 = 0.0K22 + K24 + K32 - K19 - K23 - K25 = 0.0N22 + N24 + N32 - N19 - N23 - N25 = 0.0
131Washer/Filter S25 S32 Feed to lime kiln Overflow from WLC S19 W32 (from ratio to W21)W25C25C32 (from ratio to C21)K25K32 (from ratio to K21)N25N32 (from ratio to N21)S19Washer/FilterTo dissolving tankS23S24DregsWash WaterS22Ion content of Cl, Kand Na is assumed tobe 3.7, 1.1 and 3.6 ppmUnderflowW22C22K22N22
132Lime KilnThe lime leaving the lime kiln is assumed to have no water. It is assumed that 95% of the sodium entering the lime kiln leaves in the off-gas. The ratio of C and K to water in the off-gas is assumed to be 0.001W27 = 0.0W25 = W26C26 = *W26K26 = *W26N24 = 0.05 *N25A material balance can then be written around the kilnC25 – C26 – C27 = 0K25 – K26 – K27 = 0N25 – N26 – N27 = 0
133Lime mud from washer/filter Lime KilnS26Kiln Off-gasW26C26K26S27N26To SlakerLime KilnW27C27K27N27S25Lime mud from washer/filterW25C25K25N25
134Slaker The slaking reaction is given by CaO + H2O = Ca(OH)2 The amount of water consumed by the reaction is 0.32 of the consumed limeWATERSLK = 0.32*LimeThe amount of lime fed to the slaker is 35% of the pulpLime = 0.35 * PulpThe vapor leaving the slaker makes up %5 of the water in the green liquor overflow and is ion-freeW29 = * W21C296 = 0.0K296 = 0.0N294 = 0.0
135SlakerThe ion content in the grits is related to the green liquor overflowW28 = * W21C28 = *C21K28 = *K21N28 = *N215The component material balance can then be written around the slaker:W21 + W27 - W28 - W29 - W30 - Waterslk = 0.0C21 + C27 - C28 - C29 - C30 = 0.0K21 + K27 - K28 - K29 - K30 = 0.0N21 + N27 - N28 - N29 - N30 = 0.0
136Slaker S30 S29 To Causticizer Slaker Vapor S27 From Lime Kiln Slaker W29 = *W21C29 = 0S27K29 = 0SlakerFrom Lime KilnN29 = 0S21S28Green Liquor OverflowGritsWater consumed by Rxn0.032*Lime = 0.35*PulpW21 (from ratio to W21)C21 (from ratio to C21)K21 (from ratio to K21)N21 (from ratio to N21)
137Causticer/White Liquor Clarifier(WLC) The causticing system provides an addition residence time for the causticizing reaction to take place so it can be assumed that the water and ionic content of the stream entering and exiting the system is the same (the chemical forms may change)W31 = W30C31 = C30K31 = K30N31 = N30The material balance around the WLC is thenW21 - W32 - W3 = 0.0C21 - C32 - C2 = 0.0K21 – K32 - K3 = 0.0N21 - N32 - N3 = 0.0
138Causticizer and White Liquor Clarifier to digesterWhiteLiquorClarifierS32To washer/filterS31CausticizerS30From Slaker
140Degrees of Freedom Analysis As stated earlier, a too-detailed model can hinder optimization. Consequently, a degree of freedom analysis should be conducted to determine the number of unknowns that can be specified before the remaining variables can be solved.
141Degree of Freedom Analysis Given the following generic unitINLET STREAMSOUTLET STREAMS(fresh inputs or outletsfrom other units)UnitUNSandF = Number of Degrees of FreedomNV = number of unknown variables (NS*NC)NE = number of equations in each variableNS = number of outlet streamsNC = number of targeted species
142Degree of Freedom Analysis Then the number of assumptions, additional modeling equations, measurements, data, etc that must be provided in order to have a properly specified and solvable set of equations is:F = NV – NE = NC(NS – 1)
143PINCH-BASED VISUALIZATION TOOL FOR BPX PROBLEM (El-Halwagi et al., 2003)
144Optimization of Source/Sink Analysis With Path Connections MEE Cond.G6f101ScreenF10, z10y6u = 1f102f105f103Conc. Cond.G2f121Brown StockWasherf122F12, z12f123y2u = 2f125f124fresh2Screen Condf81f82G24F8, z8f83Washer/Filterf84y24f85u = 3fresh3BPEf372f371f104G37f373F37, z37f83Bleach Plantf37bioy37u = 4fresh1Fresh H2OG2fresh4BiotreatmentFresh, z5y2u = 5