Presentation on theme: "Definition I. Beams 1. Definition"— Presentation transcript:
1DefinitionI. Beams1. DefinitionA beam is a long, slender structural member generally subjected to transverse loading that produces significant bending effects (transverse displacement rotation).< Next > < Return >
22. Simple beam theory.Assumptions: (A)member cross section is constant.(B)cross section dimension < overall length. (L/ t>10)(C) linear variation of stress and strain.(Small deformation theory)Simple beam theory 1Beam under distributed loadEquilibrium equation of a differential element of the beam.Differential beam element
3Curvature of the beam for small slope is given by Simple beam theory 2Curvature of the beam for small slope is given byr: radius of deflected curve.E: modulus of elasticity.I: principal moment of inertia about Z-axisFor constant EI and only nodal forces and moments, equation becomesSolution of displacement v(x) is of cubic polynomial function of x
4Beam element stiffness formulation 1 3. Beam element stiffness formulation. (Direct equilibrium approach)(1) Beam element (No axial effects are considered.)Sign convection of the beam element:Simple beam theory sign convection for positive shear forces and moments.
5Beam element stiffness formulation 2 (2) Assume displacement function (Without distributing loading, w(x)=0)Express n(x) as a function of nodal displacements as follows.
6Beam element stiffness formulation 3 In matrix form, we have
7Beam element stiffness formulation 4 (3)Element stiffness Matrix and EquationsBeam element stiffness formulation 4Relationships between moment, force and displacement from elementary beam theory areUsing the nodal and beam theory sign convections for shear forces and bending moments, we obtainBeam elementBeam theory
8Beam element stiffness formulation 5 Use the following equations into above equation.Hence, the beam element equation relating nodal forces and nodal displacements is given asWhere [k] is the element stiffness matrix for a beam element with neglected axial effects.
94. Example:Example 1PConstantBy direct stiffness method,the system eqn. For the beam is obtained as
10The final set of equations is Example 1The final set of equations isThe transverse displacement at node 1 and rotations at node1 and 2 arewhere the minus sign indicates that displacement at node 1 and the positive signs indicate counterclockwise rotations at node1 and 2.By substituting the known global nodal displacements and rotations into the system equation, we can determine the global nodal forces. The resulting equations areThe global nodal forces and moments are
11Free body diagrams for element 1 and 2 are shown as follows. Example 2Local nodal force for each element (used for stress analysis of the entire structure)Free body diagrams for element 1 and 2 are shown as follows.According the results of the global nodal forces and moments, the free body diagram for the whole beam is given as shown.
12Shear force diagram for the beam Example 3By using the beam theory sign conventions, the shear force V and bending moment M diagrams are shown in the following figures.Shear force diagram for the beamBending moment diagram for the beam
135. Distributed loading Equivalent force system: Replace the distributed load by concentrated nodal forces and moments tending to have the same effect on the beam as the actual distributing load based on the concept of fixed-end reactions from structural analysis theory.Fixed-end reactions are those reactions at the ends of an element if the ends of the element are assumed to be fixed.Beam subjected to a distributed loadFixed-end reactions for the beamEx.Distributed load.equivalent force system
14The system equation for the beam is Dis EX 1Example:Consider the cantilever beam subjected to the uniform load w. Find the right-end vertical displacement and rotation, and nodal forces.cantilever beam subjected to the uniform load wequivalent nodal force system for uniform load wSolution:One element is used to represent the whole beam. Based on the fixed-end reactions concept, the equivalent nodal force system is given as the following figure.The system equation for the beam is
15Applying the nodal forces and the boundary conditions , we obtain Dis EX 1Applying the nodal forces and the boundary conditions , we obtainSolving the above equation for the displacements, we haveTherefore, the reaction forces F1e and M1e for the equivalent nodal force system are
16Hence, the effective global nodal forces are Dis EX 2Hence, the effective global nodal forces areBy comparing the two equivalent system given in the previous page, we have relationships among the correct nodal forces, the effective nodal forces and the equivalent nodal forces.The equivalent nodal forces areThus, the correct global nodal forces
17Used to model general beam/frame structures. Shape Bar ElementBar Element 1DescriptionUniaxial element with tension, compression, torsion, and bending capabilities. The more general Beam element is often used instead of this element. The figure, at the end of this section, defines both element types. For some analysis programs, MSC/N4W translates both types to the same element type.ApplicationUsed to model general beam/frame structures.ShapeLine, connecting two nodes. A third node can be specified to orient the element Y axis.Element Coordinate SystemThe element X axis goes from the first node to the second.The element Y axis is perpendicular to the element X axis. It points from the first node toward the orientation (or third) node. If you use an orientation vector, the Y axis points from the first node in the direction of the orientation vector. The element Z axis is determined from the cross product of the element X and Y axes.PropertiesArea, Moments of Inertia (I1, I2, I12), Torsional Constant, Shear Areas (Y, Z), Nonstructural Mass/Length, StressRecovery Locations.Additional NotesRefer to the Beam element for further descriptions regarding Releases, Offsets and Stress Recovery Locations.
18Plane 2 (XY) Offset B Plane 1 (XY) Third Node, or Orientation Vector Bar Element 2Third Node, orOrientation VectorPlane 1 (XY)Offset AOffset BPlane 2 (XY)
19Used to model beam/frame structures. Shape Beam ElementBeam Element 1DescriptionUniaxial element with tension, compression, torsion, and bending capabilities. This element can be tapered. You can specify different properties at each end of the beam.ApplicationUsed to model beam/frame structures.ShapeLine, connecting two nodes. A third node can be specified to orient the element Y axis.Element Coordinate SystemThe element X axis goes from the first node to the second. The element Y axis is perpendicular to the element X axis. It points from the first node toward the orientation (or third) node. If you use an orientation vector, the Y axis points from the first node in the direction of the orientation vector. The element Z axis is determined from the cross product of the element X and Y axes.PropertiesArea, Moments of Inertia (I1, I2, I12), Torsional Constant, Shear Areas (Y, Z), Nonstructural Mass/Length, Stress Recovery Locations, Neutral Axis Offsets (Nay, Naz, Nby and Nbz). If the beam is tapered, you can specify different properties at each end of the element.Additional NotesYou can specify Releases which remove the connection between selected element degrees of freedom and the nodes.Offset vectors defined on the Element move the neutral axis and shear center from the nodes. Neutral Axis Offsets (Y,Z) defined on the Property card move the neutral axis away from the shear center. If there are no Neutral Axis Offsets, the neutral axis and shear center are coincident.
20MSC/pal & CDA/Sprint Iww Ivv NASTRAN Izz Iyy ANSYS IZ1 IY1 Beam Element 2If there are no offsets,both the neutral axis and shear center lie directly between the nodes.Stress Recovery Locations define positions in the elemental YZ plane (element cross-section) where you want the analysis program to calculate stresses.Specifying moments of inertia for Beam (and Bar) elements can sometimes be confusing. In MSC/N4W, I1 is the moment of inertia about the elemental Z axis. It resists bending in the outer Y fibers of the beam. It is the moment of inertia in plane 1. Similarly, I2 is the moment of inertia about the elemental Y axis. If you are familiar with one of the analysis program conventions, the following table may help you convert to MSC/N4W's convention.MSC/N4W I I2MSC/pal & CDA/Sprint Iww IvvNASTRAN Izz IyyANSYS IZ IY1STARDYNE I I2ALGOR, mTAB & SAP I I2ABAQUS I I11WECAN Izz IyyCOSMOS Izz IyySTAAD IZ IYThird Node, orOrientation VectorPlane 1 (XY)Offset AOffset BPlane 2 (XY)
21Element coordinate sys. Element coordinate system. ( orientation of a beam element)Interpretation of Element Output.．Bar element internal forces and moments.(1) plant 1(2) plant 2
22Element coordinate sys. II. Frames and Grids1. Rigid plane frame :(1) DefinitionA frame consists of a series of beam elements rigidly connected to each other.(i) joint angles between elements remain unchanged after deformation(ii) moment continuity exists at the rigid joint
23Element coordinate sys. (iii) element centroids and applied loads lie in the pane of the structure(2) Two Dimensional Beam element
24Element coordinate sys. Vectors transform law in 2DFor the beam element, we have (use the 2nd eq. of above relation)
25Element coordinate sys. Global stiffness matrix for 2D Beam elementwhereHere, the global stiffness matrix for a beam element including shear and bending effect is given as.
26Element coordinate sys. (3) 2D Beam element including axial force effectAxial force effectCombined with shear force and bending moment effects
27Element coordinate sys. and relate the local to the global displacement byor
28Element coordinate sys. The global stiffness matrix for beam element including axial, shear and bending effectswhereThe analysis of a rigid plane frame can be performed by using above stiffness matrix.
29(2) Grid Element (Shear + bending + torsion) (1) DefinitionA Grid is a structure on which loads are applied perpendicular to the plane of the structure.(2) Grid Element (Shear + bending + torsion)
30Torsional bar element stiffness matrix. Grid-2Torsional bar element stiffness matrix.Fig. Nodal and element torque sign conventionsThe relationship between torque and twist iswhere G = shear modulus ; J =centroidal polar moment of inertia
31Hence, the stiffness matrix for the torsional bar is Grid-3Hence, the stiffness matrix for the torsional bar isWe assume the shear loading to go through the shear center of these open cross sections to prevent twisting of the cross section.By Combining the torsional effect with the shear and bending effects, the local stiffness matrix equation for a grid element is written as:
32The transformation matrix relating local to global D.O.F for a grid is Hence, the global stiffness matrix for a grid element is< Prev > < Return >