Download presentation

Presentation is loading. Please wait.

Published byTyrell Leopard Modified over 3 years ago

1
Direct Current Bridges

3
A Wheatstone bridge can be used to measure resistance by comparing unknown resistor against precision resistors of known value,

4
When the voltage between A and B is equal zero. Then the voltage for R1 is equal to the voltage for R2 I1 R1 = I 2 R 2 (1) I3 R3 = I4 R4 (2)

5
I Galvanometer is equal zero then I1 = I3, I2= I4 (3) Divide (1)/(I2 2) or

6
Calculate the value of R x if the bridge is balanced

7
R1 Rx = R2 R3

9
We can calculate V th and r th by the following: * First V th : Using voltage Kirchhoff law Vth =V1 − V2 = I1 R1 − I2 R2 =

10
seconded r th

13
Calculate the current flowing through Galvanometer in the figure bellow:

Similar presentations

Presentation is loading. Please wait....

OK

Use Ohm’s Law to solve the following equations.

Use Ohm’s Law to solve the following equations.

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Download ppt on pulse code modulation ppt A ppt on nanotechnology Ppt on afforestation in india Economics for kids ppt on batteries Download ppt on motivational stories Ppt on grease lubrication system Ppt on coalition government in canada Ppt on railway track engineering Ppt on varactor diode testing Ppt on differential used in automobiles