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**INC 112 Basic Circuit Analysis**

Week 4 Mesh Analysis

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**Mesh Analysis (Loop Analysis)**

Mesh = A closed loop path which has no smaller loops inside

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**Mesh Analysis Procedure**

Count the number of meshes. Let the number equal N. Define mesh current on each mesh. Let the values be I1, I2, I3, … Use Kirchoff’s voltage law (KVL) on each mesh, generating N equations Solve the equations

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Example Use mesh analysis to find the power consumption in the resistor 3 Ω I1 I2 Mesh current (loop current)

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I1 I2 Loop 1 Equation 1 Loop 2 Equation 2 I1 = 6A, I2 = 4A, The current that pass through R 3Ω is 6-4 = 2A (downward) Power = 12 W

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Example Use Mesh analysis to find Vx I1 I2 I3

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I2 Equation 1 I1 I3 Equation 2 Equation 3 I1 = 3A, I2 = 2A, I3 = 3A Vx = 3(I3-I2) = 3V

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Supermesh When there is a current source in the mesh path, we cannot use KVL because we do not know the voltage across the current source. We have to use supermesh, which is a combination of 2 meshes to be a big mesh, and avoid the inclusion of the current source in the mesh path.

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Example Use Mesh analysis to find Vx I1 I2 I3

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I1 I2 I3 Equation from 2nd loop

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Supermesh I1 I2 I3 Equation 2 Equation 3

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I1 = 9A I2 = 2.5A I3 = 2A Vx = 3(I3-I2) = -1.5V

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**How to choose between Node and Mesh Analysis**

The hardest part in analyzing circuits is solving equations. Solving 3 or more equations can be time consuming. Normally, we will count the number of equations according to each method and select the method that have lesser equations.

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**Example From the previous example, if we want to use Nodal Analysis 7V**

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**Example: Dependent Source**

Find Vx I1 I2 I3

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Equation 1 I1 I2 I3 Equation 2 Equation 3 Equation 4 I1=15A, I2=11A, I3=17A Vx = 3(17-11) = 18V

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**Special Techniques Superposition Theorem Thevenin’s Theorem**

Norton’s Theorem Source Transformation

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**Superposition Theorem**

In a linear circuit, we can calculate the value of current (or voltage) that is the result from each voltage source and current source independently. Then, the real value is the sum of all current (or voltage) from the sources.

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Linearity V and I have linear relationship I V

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Implementation When calculating the effect of a source, the other sources will be set to zero. For voltage sources, when set as 0V, it will be similar to short circuit For current sources, when set as 0A, it will be similar to open circuit

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Example I1 = 1A I2 = 2A I total = 1+2 = 3A

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Example I1 = 1A I2 = 0A I total = 1+0 = 1A

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Example Find voltage Vx

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**Superposition and Dependent Source**

Dependent sources cannot be used with superposition. They have to be active all the time.

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Example Use superposition to find Ix

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**Find Ix by eliminating the current source 3A**

KVL

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**Find Ix by eliminating the voltage source 10V**

KVL outer loop

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Lecture-4. Md.Kausher ahmed Electrical department.

Lecture-4. Md.Kausher ahmed Electrical department.

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