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Higher Physics Unit 1 Multiple Choice Questions. Q1.

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Presentation on theme: "Higher Physics Unit 1 Multiple Choice Questions. Q1."— Presentation transcript:

1 Higher Physics Unit 1 Multiple Choice Questions

2 Q1

3 Q2 12km North 4km South 8km displacement NORTH v = s t = 8 4 = 2km/h north v = d t = 16 4 = 4 km/h

4 Q3

5 Q4 Remember redraw diagram nose to tail.

6 Q5

7 Q6

8 Q7 Displacement 50 km v = d t = 70 2 = 35 km/h v = s t = 50 2 = 25km/h

9 Q8

10 Q9

11 Q10

12 Q11 u = v = a = s = t = - 3m/s ? m/s 2 ??? 5.0s s = ut + ½ at 2 s = -3x5 + ½ (-9.8) x (5) 2 s = (-4.9 x 25) s = s = m + -

13 Q12 horizontalvertical V H = ?? d = 5.1m t = ? v = d t u = 0 m/s v = ? a = -9.8 m/s2 s = -2.0 m t = ? S = ut + ½ at 2 -2 = 0 + ½ (-9.8)t 2 -2 = -4.9 t 2 t 2 = -2 / (-4.9) t = 0.64s v = v = 7.97m/s

14 Q13

15 Q14

16 Q15 TMB = TMA pnefa m 1 u 1 = m 2 v 2 +m 3 v x 0 = 1200v x 60 0 = 1200v v 2 = v 2 = /1200 v 2 = m/s -ve answer means cannon will be travelling in the opposite direction (i.e. west)

17 Q16

18 Q17 40m/s 30m/s 40m/s 50m/s

19 Q18 Between 1 to 3 seconds a = 4m/s 2 So every second the speed increases by 4m/s so if it starts from rest is speed will be 16m/s after 4 seconds. Then between 3 to 5 seconds a = -2m/s 2 So every second the speed decreases by 2m/s so if it starts from 16m/s is speed will be 12m/s after 2 seconds.

20 Q19 Fun = ma Fun = 400 x 2 Fun = 800 N

21 Q20

22 Q21 W = mg W = 15 x 9.8 W = 147N F un = 180 –147 = 33N F un = ma a = F un / m a = 33 / 15 a = 2.2 m/s 2

23 Q22 friction F un = ma F un = 10 x 10 F un = 100N

24 Q23 Constant height = balanced forces Upthrust = weight = mg Upthrust = 1.5 x 9.8 Upthrust = 14.7 N

25 Q24 F un = ma a = F un / m a = 18 / 10 a = 1.8 m/s 2 F un = ma F un = 4 x 1.8 F un = 7.2N

26 Q25 E K at start E K = ½ mv 2 E K = ½ x 1000 x40 2 E K = 800,000 J E K at end E K = ½ mv 2 E K = ½ x 1000 x 10 2 E K = 50,000 J E K lost = 800,000 – 50,000 = 750,000 J = 750 kJ

27 Q26 FHFH opp hyp adj cos 40 o = adj / hyp cos 40 o = F H / 100 F H = 100 cos 40 o F H = 76.6 N Ew = Fd Ew = 76.6 x 10 Ew = 766 J

28 Q27 F un = ma F un = 700 x 2 F un = 1400 N

29 Q28 Force up is greater than force down So lift is either accelerating upwards OR decelerating downwards.

30 Q29 Accelerating downwards so Force down (weight) greater than force up (apparent weight)

31 Q30 TMB = TMA m 1 u 1 = m 2 v 2 + m 3 v x 0 = 2000v x 50 0 = 2000v V 2 = -250 / 2000 V 2 = m/s The answer is negative because it is travelling in opposite direction to the cannon ball.

32 Q31 Momentum = mv v = momentum / m v = 12 / 4 v = 3 m/s E K = ½ mv 2 E K = ½ x 4 x 3 2 E K = 36 J

33 Q32 F x t = mv -mu Impulse = change in momentum Since mass and speed of impact are constant change in momentum is constant. Crumple zones increase the time of contact thereby reducing the force of impact.

34 Q33

35 Q34 Ft = mv - mu F = (mv – mu) / t F = change in momentum per second.

36 Q35 Ft = mv - mu Change in momentum hasn’t changed therefore Ft is constant.

37 Q36

38 Q37

39 Q38

40 Q39

41 Q40

42 Q41

43 Q42

44 Q43

45 Q44

46 Q45

47 Q46

48 Q47

49 Q48

50 Q49

51 Q50

52 Q51

53 Q52

54 Q53

55 Q54

56 Q55

57 Q56


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