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Published byDante Harmison Modified about 1 year ago

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x012 P(x) A probability distribution is as shown. If it is repeated and the 2 distributions combined then the following would be the table of potential results Value x Prob’ x0.60.2x x x x x0.2

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Prob’ y01234 P(y) yP(y) y 2 P(y) E(y)= y P(y)] = = 2.00 2 = y 2 P(y) – = 2 = 4.8 – 4 = 0.8

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y01234 y - (y- ) P(y) (y- ) 2 P(y) E(y)= y P(y) = = 2.00 2 = (y – P(y) = 2 = 0.8 Alternatively using the other formula for Variance

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