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T UTORIAL 2 SOLUTIONS Lecturer: Miss Anis Atikah Ahmad Tel:

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The exothermic reaction A--->B + C was carried out adiabatically and the following data recorded: The entering molar flow rate of A was 300 mol/min. (a) What are the PFR and CSTR volumes necessary to achieve 40 % conversion? (b) Over what range of conversions would the CSTR and PFR reactor volumes be identical? (c) What is the maximum conversion that can be achieved in a 105 dm 3 CSTR? (d) What conversion can be achieved if a 72 dm 3 PFR is followed in series by a 24 dm 3 CSTR? (e) What conversion can be achieved if a 24 dm 3 CSTR is followed in a series by a 72 dm 3 PFR? (f) Plot the conversion and rate of reaction as a function of PFR reactor volume up to a volume of 100 dm 3. Q UESTIONS X r A (mol/dm 3. min

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P ART (A) Recall Simpson One- Third Rule Formula: PFR Volume: Using Simpson One-Third Rule; What are the PFR and CSTR volumes necessary to achieve 40 % conversion?

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P ART (A) X r A (mol/dm 3.min) F A0 /-r A (dm 3 ) Levelspiel Plot V PFR

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P ART ( A ) CSTR Volume: Substituting the value of F A0 / –r A at X =0.4; V CSTR Levelspiel Plot

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P ART (B) Over what range of conversions would the CSTR and PFR reactor volumes be identical? The volume of both reactors are identical at X= , From Levelspiel Plot;

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P ART (B) Over what range of conversions would the CSTR and PFR reactor volumes be identical? Using Simpson One-Third Rule Proving by calculation; Volume of PFR Volume of CSTR

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By trial and error, calculate what is X that gives a CSTR volume of 105 dm 3 Trial 1: X=0.6, P ART ( C ) What is the maximum conversion that can be achieved in a 105 dm 3 CSTR? Trial 2: X=0.8, Trial 3: X=0.7, X=0.7 The max conversion can be achieved in 105 dm 3 of CSTR is 0.7

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By trial and error, calculate what is X 2 that gives a CSTR volume of 24 dm 3 Trial 1: X=0.6, Trial 2: X=0.7, P ART ( D ) What conversion can be achieved if a 72 dm 3 PFR is followed in series by a 24 dm 3 CSTR? X 2 =? X 1 =0.4 F A0 =300 mol/dm 3 V CSTR =24 dm 3 V PFR =72 dm 3 Now, we know that the conversion must be between From part (a)

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Trial 3: X=0.64, P ART ( D ) What conversion can be achieved if a 72 dm 3 PFR is followed in series by a 24 dm 3 CSTR? X 2 =? X 1 =0.4 F A0 =300 mol/dm 3 V CSTR =24 dm 3 V PFR =72 dm 3 X=0.64 X =0.64 can be achieved if a 72 dm 3 PFR is followed in series by a 24 dm 3 CSTR.

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By trial and error, calculate what is X 2 that gives a PFR volume of 72 dm 3 Trial 1: X=0.8, P ART ( E ) What conversion can be achieved if a 24 dm 3 CSTR is followed in a series by a 72 dm 3 PFR? X 2 =? X 1 =0.4 F A0 =300 mol/dm 3 V CSTR =24 dm 3 V PFR =72 dm 3 From part (a)

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By trial and error, calculate what is X 2 that gives a PFR volume of 72 dm 3 Trial 2: X=0.9, P ART ( E ) What conversion can be achieved if a 24 dm 3 CSTR is followed in a series by a 72 dm 3 PFR? X 2 =? X 1 =0.4 F A0 =300 mol/dm 3 V CSTR =24 dm 3 V PFR =72 dm 3

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Trial 3: X=0.91, P ART ( E ) What conversion can be achieved if a 24 dm 3 CSTR is followed in a series by a 72 dm 3 PFR? X =0.91 can be achieved if a 24 dm 3 CSTR is followed in a series by a 72 dm 3 PFR

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P ART ( F ) Plot the conversion and rate of reaction as a function of PFR reactor volume up to a volume of 100 dm 3 ? X r A (mol/dm 3.min) F A0 /-r A (dm 3 ) V PFR (dm 3 )

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P ART ( F ) Plot the conversion and rate of reaction as a function of PFR reactor volume up to a volume of 100 dm 3 ?

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THANK YOU

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