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Passive Circuit Elements in the Frequency Domain Section 9.4-9.6.

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Presentation on theme: "Passive Circuit Elements in the Frequency Domain Section 9.4-9.6."— Presentation transcript:

1 Passive Circuit Elements in the Frequency Domain Section 9.4-9.6

2 Outline I-V relationship for a capacitor I-V relationship for an inductor


4 Current and Voltage Relationship Q=CV (at t=t 1 ) (Current is 0) If you increase voltage by ∆V, then more charges will be shoved to the capacitor. (Q+ ∆Q) Here is what we have. Q+ ∆Q=C(V+ ∆V) Charges can not be moved instantaneously. The accumulation of charges will take place between t1 and t 1 + ∆t We are interested only in the incremental change of charges. ∆Q/ ∆t=C ∆V/ ∆t=i

5 Current and Voltage Relationship i=C ∆V/ ∆t – ∆V/ ∆t represent the rate of change of voltage across a capacitor. – The faster the rate of change, the greater the current. – ∆V/ ∆t is the slope V C vs time plot.

6 The rate of change of a sine wave Determine the slope by putting a ball on the curve.

7 Time Domain Interpretation I C =C ∆V/ ∆t

8 Phasor Interpretation Z=1/(jωC)=-j/(ωC) V C =I C Z V C =I C [-j/(ωC)]

9 Capacitive Impedance as a function of frequency The faster the voltage changes, the higher the frequency, the greater the current, and hence lower the Impedance. So Z C, the Impedance, is inversely proportional to f. I C =C ∆V/ ∆t

10 Impedance as a function of Capacitor i=C ∆V/ ∆t Assume that ∆V/ ∆t is constant, the larger the C, the greater the current. In other words, ∆V/ ∆t represent changes in the voltage across the capacitor. The changes in V C can not happen without the changes in Q. A larger the capacitance will require more charges for the same ∆V/ ∆t. So it will require more current. Reactance is inversely proportional to capacitance.

11 Similarity to resistance ADD impedance of series capacitors – Z TC =Z C1 +Z C2 +Z C3 Calculate Impedance of parallel capacitors like parallel resistors. – Z TC =Z C1 Z C2 /(Z C1 +Z C2 )

12 Example

13 Ohm’s law When applying Ohm’s law in AC circuits, you must express both the current and the voltage in rms, peak,…and so on. I=V s /X C


15 Capacitive Voltage Divider Vx=(X Cx /X c,tot ) Vs This is similar to the formula for voltage divider

16 Power in a capacitor Instantaneous Power True Power Reactive Power

17 Power curve Instantaneous power fluctuates as twice the frequency of voltage and current. Ideally all the energy stored by a capacitor during the positive power cycle is returned to the source during the negative portion Note that the average power is 0.

18 Inductor

19 Time Domain Interpretation (An inductor resists change in current. At t=0, voltage is maximum, but current is 0. It takes time for the current to catch up to voltage.)

20 Phasor Interpretation Z=jωL V C =I C (jωL) I C =V C [-j/(ωL)]

21 Understanding Z L I C =V C [-j/(ωL)] An inductor has a natural tendency to resist change in current. Therefore, as the frequency of V C increases, it will not be able to keep up with changes. At sufficiently high frequencies, the current will cease to track the voltage, and begins to behave as an open circuit.

22 Inductive reactance formula In general: – X L =2ΩfL=ωL For series inductors: – X LT =X L1 +X L2 +X L3 …. For parallel inductors: – 1/X LT =1/X L1 +1/X L2 +1/X L3

23 Example 13-13

24 Ohm’s law I=V S /Z L

25 Example 13-14

26 Power in an inductor

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