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DECISION DANS L'INCERTAIN ET THEORIE DES JEUX Stefano MORETTI 1, David RIOS 2 and Alexis TSOUKIAS 1 1 LAMSADE (CNRS), Paris Dauphine 2 Statistics and Operations Research Department, Rey Juan Carlos University (URJC), Madrid Tous les mercredis de 13h45 à 17h00 du 20/01 au 24/02

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GAME THEORY NON- COOPERATIVE THEORY Games in extendive form (tree games) Games in strategic form (normal form) COOPERATIVE THEORY Games in c.f.f. (TU- games or coalitional games) Bargaining gamesNTU-games Dominant strategies Nash eq. (NE) Subgame perfect NE NE & refinements … Core Shapley value Nucleolus τ-value PMAS …. Nash sol. Kalai- Smorodinsky …. CORE NTU-value Compromise value … No binding agreements No side payments Q: Optimal behaviour in conflict situations binding agreements side payments are possible (sometimes) Q: Reasonable (cost, reward)-sharing

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Cooperative games: a simple example Alone, player 1 (singer) and 2 (pianist) can earn 100€200€ respect. Together (duo)700€ How to divide the (extra) earnings? I(v) 700 400 600 200 100 300500 700 x2x2 x1x1 x 1 +x 2 =700 “reasonable” payoff? Imputation set: I(v)={x IR 2 |x 1 100, x 2 200, x 1 +x 2 =700}

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Simple example Alone, player 1 (singer) and 2 (pianist) can earn 100€200€ respect. Together (duo)700€ How to divide the (extra) earnings? I(v) 700 400 600 200 100 300500 700 x2x2 x1x1 x 1 +x 2 =700 “reasonable” payoff Imputation set: I(v)={x IR 2 |x 1 100, x 2 200, x 1 +x 2 =700} In this case I(v) coincides with the core (300, 400) =Shapley value = -value = nucleolus

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COOPERATIVE GAME THEORY Games in coalitional form TU-game: (N,v) or v N={1, 2, …, n}set of players S Ncoalition 2 N set of coalitions DEF. v: 2 N IR with v( )=0 is a Transferable Utility (TU)-game with player set N. NB: (N,v) v NB2: if n=|N|, it is also called n-person TU-game, game in colaitional form, coalitional game, cooperative game with side payments... v(S) is the value (worth) of coalition S Example (Glove game) N=L R,L R= i L (i R) possesses 1 left (right) hand glove Value of a pair: 1€ v(S)=min{| L S|, |R S|} for each coalition S 2N\{ }.

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Example (Three cooperating communities) source 1 2 3 100 30 80 40 90 N={1,2,3} v(S)= i S c(i) – c(S) S= {1}{2}{3}{1,2}{1.3}{2,3}{1,2,3} c(S)01009080130110 140 v(S)0000607060130

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Example (flow games) source 4,1 30 10,3 80 l1l1 5,2 N={1,2,3} S= {1}{2}{3}{1,2}{1.3}{2,3}{1,2,3} v(S)00000459 sink l2l2 l3l3 capacityowner 1€: 1 unit source sink

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DEF. (N,v) is a superadditive game iff v(S T) v(S)+v(T) for all S,T with S T= Q.1: which coalitions form? Q.2: If the grand coalition N forms, how to divide v(N)? (how to allocate costs?) Many answers! (solution concepts) One-point concepts: - Shapley value (Shapley 1953) - nucleolus (Schmeidler 1969) - τ-value (Tijs, 1981) … Subset concepts:- Core (Gillies, 1954) - stable sets (von Neumann, Morgenstern, ’44) - kernel (Davis, Maschler) - bargaining set (Aumann, Maschler) …..

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Show that v is superadditive and c is subadditive. Example (Three cooperating communities) source 1 2 3 100 30 80 40 90 N={1,2,3} v(S)= i S c(i) – c(S) S= {1}{2}{3}{1,2}{1.3}{2,3}{1,2,3} c(S)01009080130110 140 v(S)0000607060130

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Claim 1: (N,v) is superadditive We show that v(S T) v(S)+v(T) for all S,T 2 N \{ } with S T= 60=v(1,2) v(1)+v(2)=0+0 70=v(1,3) v(1)+v(3)=0+0 60=v(2,3) v(2)+v(3)=0+0 60=v(1,2) v(1)+v(2)=0+0 130=v(1,2,3) v(1)+v(2,3)=0+60 130=v(1,2,3) v(2)+v(1,3)=0+70 130=v(1,2,3) v(3)+v(1,2)=0+60 Claim 2: (N,c) is subadditive We show that c(S T) c(S)+c(T) for all S,T 2 N \{ } with S T= 130=c(1,2) c(1)+c(2)=100+90 110=c(2,3) c(2)+v(3)=100+80 110=c(1,2) c(1)+v(2)=90+80 140=c(1,2,3) c(1)+c(2,3)=100+110 140=c(1,2,3) c(2)+c(1,3)=90+110 140=c(1,2,3) c(3)+c(1,2)=80+130

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Example (Glove game) (N,v) such that N=L R,L R= v(S)=10 min{| L S|, |R S|} for all S 2N\{ } Claim: the glove game is superadditive. Suppose S,T 2 N \{ } with S T= . Then v(S)+v(T)= min{| L S|, |R S|} + min{| L T|, |R T|} =min{| L S|+|L T|,|L S|+|R T|,|R S|+|L T|,|R S|+|R T|} min{| L S|+|L T|, |R S|+|R T|} since S T= =min{| L (S T)|, |R (S T)|} =v(S T).

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The imputation set DEF. Let (N,v) be a n-persons TU-game. A vector x=(x 1, x 2, …, x n ) IR N is called an imputation iff (1) x is individual rational i.e. x i v(i) for all i N (2) x is efficient i N x i = v(N) [interpretation x i : payoff to player i] I(v)={x IR N | i N x i = v(N), x i v(i) for all i N} Set of imputations

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Example (N,v) such that N={1,2,3}, v(1)=v(3)=0, v(2)=3, v(1,2,3)=5. x3x3 x2x2 X1X1 (5,0,0) (0,5,0) (0,0,5) x 1 +x 2 +x 3 =5 (x 1,x 2,x 3 ) (2,3,0) (0,3,2) I(v) I(v)={ x IR 3 | x 1,x 3 0, x 2 3, x 1 +x 2 +x 3 =5}

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Claim: (N,v) a n-person (n=|N|) TU-game. Then I(v) v(N) i N v(i) Proof ( ) Suppose x I(v). Then v(N)= i N x i i N v(i) EFFIR ( ) Suppose v(N) i N v(i). Then the vector (v(1), v(2), …, v(n-1), v(N)- i {1,2, …,n-1} v(i)) is an imputation. v(n)

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The core of a game DEF. Let (N,v) be a TU-game. The core C(v) of (N,v) is the set C(v)={x I(v) | i S x i v(S) for all S 2N\{ }} stability conditions no coalition S has the incentive to split off if x is proposed Note: x C(v) iff (1) i N x i = v(N) efficiency (2) i S x i v(S) for all S 2N\{ } stability Bad news: C(v) can be empty Good news: many interesting classes of games have a non- empty core.

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Example (N,v) such that N={1,2,3}, v(1)=v(3)=0, v(2)=3, v(1,2)=3, v(1,3)=1 v(2,3)=4 v(1,2,3)=5. Core elements satisfy the following conditions: x 1,x 3 0, x 2 3, x 1 +x 2 +x 3 =5 x 1 +x 2 3, x 1 +x 3 1, x 2 +x 3 4 We have that 5-x 3 3 x 3 2 5-x 2 1 x 3 4 5-x 1 4 x 1 1 C(v)={ x IR 3 | 1 x 1 0,2 x 3 0, 4 x 2 3, x 1 +x 2 +x 3 =5}

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Example (N,v) such that N={1,2,3}, v(1)=v(3)=0, v(2)=3, v(1,2)=3, v(1,3)=1 v(2,3)=4 v(1,2,3)=5. x3x3 x2x2 X1X1 (5,0,0) (0,5,0) (0,0,5) x 1 +x 2 +x 3 =5 (2,3,0) (0,3,2) C(v) (0,4,1) (1,3,1) (1,4,0) C(v)={ x IR 3 | 1 x 1 0,2 x 3 0, 4 x 2 3, x 1 +x 2 +x 3 =5}

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Example (Game of pirates) Three pirates 1,2, and 3. On the other side of the river there is a treasure (10€). At least two pirates are needed to wade the river… (N,v), N={1,2,3}, v(1)=v(2)=v(3)=0, v(1,2)=v(1,3)=v(2,3)=v(1,2,3)=10 Suppose ( x 1, x 2, x 3 ) C(v). Then efficiency x 1 + x 2 + x 3 =10 x 1 + x 2 10 stability x 1 + x 3 10 x 2 + x 3 10 20=2(x 1 + x 2 + x 3 ) 30Impossible. So C(v)= . Note that (N,v) is superadditive.

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Example (Glove game with L={1,2}, R={3}) v(1,3)=v(2,3)=v(1,2,3)=1, v(S)=0 otherwise Suppose ( x 1, x 2, x 3 ) C(v). Then x 1 + x 2 + x 3 =1 x 2 =0 x 1 +x 3 1 x 1 +x 3 =1 x 2 0 x 2 + x 3 1 x 1 =0andx 3 =1 So C(v)={(0,0,1)}. (1,0,0) (0,0,1) (0,1,0) I(v)

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Example (flow games) source 4,1 30 10,3 80 l1l1 5,2 N={1,2,3} S= {1}{2}{3}{1,2}{1.3}{2,3}{1,2,3} v(S)00000459 sink l2l2 l3l3 capacityowner 1€: 1 unit source sink Min cut Min cut {l 1, l 2 }. Corresponding core element (4,5,0)

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Non-emptiness of the core Notation: Let S 2 N \{ }. 1 if i S e S is a vector with (e S ) i = 0 if i S DEF. A collection B 2 N \{ } is a balanced collection if there exist (S)>0 for S B such that: e N = S B (S) e S Example: N={1,2,3}, B={{1,2},{1,3},{2,3}}, (S)= for S B e N =(1,1,1)=1/2 (1,1,0)+1/2 (1,0,1) +1/2 (0,1,1)

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Balanced games DEF. (N,v) is a balanced game if for all balanced collections B 2 N \{ } S B (S) v(S) v(N) Example: N={1,2,3}, v(1,2,3)=10, v(1,2)=v(1,3)=v(2,3)=8 (N,v) is not balanced 1/2v (1,2)+1/2 v(1,3) +1/2 v(2,3)>10=v(N)

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Variants of duality theorem Duality theorem. min{x T c|x T A b} | max{b T y|Ay=c, y 0} (if both programs feasible) A yTyT bTbT xc

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Bondareva (1963) | Shapley (1967) Characterization of games with non-empty core C(v) v(N)=min{x T e N | x T e S v(S) S 2 N \{ }} duality v(N)=max{v T | S 2 N \{ } (S)e S =e N, 0 } 0, S 2 N \{ } (S)e S =e N v T = S 2 N \{ } (S)v(S) v(N) (N,v) is a balanced game 1 0 1. e S.. 0 1 ({1})……. (S)…….… (N) V(1)………v(S)……..…v(N) X1X2...x2X1X2...x2 11...111...1 Theorem (N,v) is a balanced game C(v) Proof First note that x T e S = i S x i

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Convex games (1) DEF. An n-persons TU-game (N,v) is convex iff v(S)+v(T) v(S T)+v(S T) for each S,T 2 N. This condition is also known as submodularity. It can be rewritten as v(T)-v(S T) v(S T)-v(S) for each S,T 2 N For each S,T 2 N, let C=(S T)\S. Then we have: v ( C (S T) ) -v(S T) v(C S)-v(S) Interpretation: the marginal contribution of a coalition C to a disjoint coalition S does not decrease if S becomes larger

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Convex games (2) It is easy to show that submodularity is equivalent to v(S {i})-v(S) v(T {i})-v(T) for all i N and all S,T 2 N such that S T N\{i} interpretation: player's marginal contribution to a large coalition is not smaller than her/his marginal contribution to a smaller coalition (which is stronger than superadditivity) Clearly all convex games are superadditive (S T= …) A superadditive game can be not convex (try to find one) An important property of convex games is that they are (totally) balanced, and it is “easy” to determine the core (coincides with the Weber set, i.e. the convex hull of all marginal vectors…)

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Example (N,v) such that N={1,2,3}, v(1)=v(3)=0, v(2)=3, v(1,2)=3, v(1,3)=1 v(2,3)=4 v(1,2,3)=5. Check it is convex x3x3 x2x2 X1X1 (5,0,0) (0,5,0) (0,0,5) x 1 +x 2 +x 3 =5 (2,3,0) (0,3,2) C(v) Marginal vectors 123 (0,3,2) 132 (0,4,1) 213 (0,3,2) 231 (1,3,1) 321 (1,4,0) 312 (1,4,0) (0,4,1) (1,3,1) (1,4,0) C(v)={ x IR 3 | 1 x 1 0,2 x 3 0, 4 x 2 3, x 1 +x 2 +x 3 =5}

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How to share v(N)… The Core of a game can be used to exclude those allocations which are not stable. But the core of a game can be a bit “extreme” (see for instance the glove game) Sometimes the core is empty (pirates) And if it is not empty, there can be many allocations in the core (which is the best?)

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An axiomatic approach (Shapley (1953) Similar to the approach of Nash in bargaining: which properties an allocation method should satisfy in order to divide v(N) in a reasonable way? Given a subset C of G N (class of all TU-games with N as the set of players) a (point map) solution on C is a map Φ:C →IR N. For a solution Φ we shall be interested in various properties…

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Symmetry PROPERTY 1(SYM) For all games v G N, If v(S {i}) = v(S {j}) for all S 2 N s.t. i,j N\S, then Φ i (v) = Φ j (v). EXAMPLE We have a TU-game ({1,2,3},v) s.t. v(1) = v(2) = v(3) = 0, v(1, 2) = v(1, 3) = 4, v(2, 3) = 6, v(1, 2, 3) = 20. Players 2 and 3 are symmetric. In fact: v( {2})= v( {3})=0 and v({1} {2})=v({1} {3})=4 If Φ satisfies SYM, then Φ 2 (v) = Φ 3 (v)

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Efficiency PROPERTY 2 (EFF) For all games v G N, i N Φ i (v) = v(N), i.e., Φ(v) is a pre-imputation. Null Player Property DEF. Given a game v G N, a player i N s.t. v(S i) = v(S) for all S 2 N will be said to be a null player. PROPERTY 3 (NPP) For all games v G N, Φ i (v) = 0 if i is a null player. EXAMPLE We have a TU-game ({1,2,3},v) such that v(1) =0, v(2) = v(3) = 2, v(1, 2) = v(1, 3) = 2, v(2, 3) = 6, v(1, 2, 3) = 6. Player 1 is null. Then Φ 1 (v) = 0

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EXAMPLE We have a TU-game ({1,2,3},v) such that v(1) =0, v(2) = v(3) = 2, v(1, 2) = v(1, 3) = 2, v(2, 3) = 6, v(1, 2, 3) = 6. On this particular example, if Φ satisfies NPP, SYM and EFF we have that Φ 1 (v) = 0 by NPP Φ 2 (v)= Φ 3 (v) by SYM Φ 1 (v)+Φ 2 (v)+Φ 3 (v)=6 by EFF So Φ=(0,3,3) But our goal is to characterize Φ on G N. One more property is needed.

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Additivity PROPERTY 2 (ADD) Given v,w G N, Φ(v)+Φ(w)=Φ(v +w)..EXAMPLE Two TU-games v and w on N={1,2,3} v(1) =3 v(2) =4 v(3) = 1 v(1, 2) =8 v(1, 3) = 4 v(2, 3) = 6 v(1, 2, 3) = 10 w(1) =1 w(2) =0 w(3) = 1 w(1, 2) =2 w(1, 3) = 2 w(2, 3) = 3 w(1, 2, 3) = 4 + v+w(1) =4 v+w(2) =4 v+w(3) = 2 v+w(1, 2) =10 v+w(1, 3) = 6 v+w(2, 3) = 9 v+w(1, 2, 3) = 14 = ΦΦ Φ

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Theorem 1 (Shapley 1953) There is a unique map defined on G N that satisfies EFF, SYM, NPP, ADD. Moreover, for any i N we have that Here is the set of all permutations σ:N →N of N, while m σ i (v) is the marginal contribution of player i according to the permutation σ, which is defined as: v({σ(1), σ(2),..., σ (j)})− v({σ(1), σ(2),..., σ (j −1)}), where j is the unique element of N s.t. i = σ(j).

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Unanimity games (1) DEF Let T 2 N \{ }. The unanimity game on T is defined as the TU-game (N,u T ) such that 1 is T S u T (S)= 0 otherwise Note that the class G N of all n-person TU-games is a vector space (obvious what we mean for v+w and v for v,w G N and IR). the dimension of the vector space G N is 2 n -1 {u T |T 2 N \{ }} is an interesting basis for the vector space G N.

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Unanimity games (2) Every coalitional game (N, v) can be written as a linear combination of unanimity games in a unique way, i.e., v = S 2 N λ S (v)u S. The coefficients λ S (v), for each S 2 N, are called unanimity coefficients of the game (N, v) and are given by the formula: λ S (v) = T 2 S (−1) s−t v(T ).

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.EXAMPLE Two TU-games v and w on N={1,2,3} v(1) =3 v(2) =4 v(3) = 1 v(1, 2) =8 v(1, 3) = 4 v(2, 3) = 6 v(1, 2, 3) = 10 1 (v) =3 2 (v) =4 3 (v) = 1 {1,2} (v) =-3-4+8=1 {1,3} (v) = -3-1+4=0 {2,3} (v) = -4-1+6=1 {1,2,3} (v) = -3-4-1+8+4+6-10=0 v=3u {1} (v)+4u {2} (v)+u {3} (v)+u {1,2} (v)+u {2,3} (v)

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Sketch of the Proof of Theorem1 Shapley value satisfies the four properties (easy). Properties EFF, SYM, NPP determine on the class of all games αv, with v a unanimity game and α IR. Let S 2 N. The Shapley value of the unanimity game (N,u S ) is given by /|S| if i S i (αu S )= 0 otherwise Since the class of unanimity games is a basis for the vector space, ADD allows to extend in a unique way to G N.

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Example (N,v) such that N={1,2,3}, v(1)=v(3)=0, v(2)=3, v(1,2)=3, v(1,3)=1, v(2,3)=4, v(1,2,3)=5. Permutation123 1,2,3032 1,3,2041 2,1,3032 2,3,1131 3,2,1140 3,1,2140 Sum340 (v) 3/621/66/6 Probabilistic interpretation: (the “room parable”) Players gather one by one in a room to create the “grand coalition”, and each one who enters gets his marginal contribution. Assuming that all the different orders in which they enter are equiprobable, the Shapley value gives to each player her/his expected payoff.

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Example (N,v) such that N={1,2,3}, v(1)=v(3)=0, v(2)=3, v(1,2)=3, v(1,3)=1 v(2,3)=4 v(1,2,3)=5. x3x3 x2x2 X1X1 (5,0,0) (0,5,0) (0,0,5) x 1 +x 2 +x 3 =5 (2,3,0) (0,3,2) C(v) Marginal vectors 123 (0,3,2) 132 (0,4,1) 213 (0,3,2) 231 (1,3,1) 321 (1,4,0) 312 (1,4,0) (0,4,1) (1,3,1) (1,4,0) (v)=(0.5, 3.5,1)

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Example (N,v) such that N={1,2,3}, v(1) =3 v(2) =4 v(3) = 1 v(1, 2) =8 v(1, 3) = 4 v(2, 3) = 6 v(1, 2, 3) = 10 Permutation123 1,2,3 1,3,2 2,1,3 2,3,1 3,2,1 3,1,2 Sum (v)

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Example (Glove game with L={1,2}, R={3}) v(1,3)=v(2,3)=v(1,2,3)=1, v(S)=0 otherwise (1,0,0) (0,0,1) I(v) Permutation123 1,2,3001 1,3,2001 2,1,3001 2,3,1001 3,2,1010 3,1,2100 Sum114 (v) 1/6 4/6 C(v) (0,1,0) (v) (1/6,1/6,2/3)

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Let m σ’ i (v)=v({σ’(1),σ’(2),…,σ’(j)})− v({σ’(1),σ’(2),…, σ’(j −1)}), where j is the unique element of N s.t. i = σ’(j). Let S={σ’(1), σ’(2),..., σ’(j)}. Q: How many other orderings do we have in which {σ(1), σ(2),..., σ (j)}=S and i = σ’(j)? A: they are precisely (|S|-1)! (|N|-|S|)! Where (|S|-1)! Is the number of orderings of S\{i} and (|N|- |S|)! Is the number of orderings of N\S We can rewrite the formula of the Shapley value as the following: An alternative formulation

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Alternative properties PROPERTY 5 (Anonymity, ANON) Let (N, v) G N σ : N →N be a permutation. Then, Φ σ(i) (σ v) = Φ i (v) for all i N. Here σv is the game defined by: σv(S) = v(σ(S)), for all S 2 N. Interpretation: The meaning of ANON is that whatever a player gets via Φ should depend only on the structure of the game v, not on his “name”, i.e., the way in which he is labelled. DEF (Dummy Player) Given a game (N, v), a player i N s.t. v(S {i}) =v(S)+v(i) for all S 2 N will be said to be a dummy player. PROPERTY 6 (Dummy Player Property, DPP) If i is a dummy player, then Φ i (v) =v(i). NB: often NPP and SYM are replaced by DPP and ANON, respectively.

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Characterization on a subclass Shapley and Shubik (1954) proposed to use the Shapley value as a power index, ADD property does not impose any restriction on a solution map defined on the class of simple games S N, which is the class of games such that v(S) {0,1} (often is added the requirement that v(N) = 1). Therefore, the classical conditions are not enough to characterize the Shapley–Shubik value on S N. A condition that resembles ADD and can substitute it to get a characterization of the Shapley–Shubik (Dubey (1975) index on S N : PROPERTY 7 (Transfer, TRNSF) For any v,w S(N), it holds: Φ(v w)+Φ(v w) = Φ(v)+Φ(w). Here v w is defined as (v w)(S) = (v(S) w(S)) = max{v(S),w(S)}, and v w is defined as (v w)(S) = (v(S) w(S)) = min{v(S),w(S)},

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.EXAMPLE Two TU-games v and w on N={1,2,3} + v(1) =0 v(2) =1 v(3) = 0 v(1, 2) =1 v(1, 3) = 1 v(2, 3) = 0 v(1, 2, 3) = 1 = w(1) =1 w(2) =0 w(3) = 0 w(1, 2) =1 w(1, 3) = 0 w(2, 3) = 1 w(1, 2, 3) = 1 ΦΦ v w(1) =0 v w(2) =0 v w(3) = 0 v w(1, 2) =1 v w(1, 3) = 0 v w(2, 3) = 0 v w(1, 2, 3) = 1 Φ v w(1) =1 v w(2) =1 v w(3) = 0 v w(1, 2) =1 v w(1, 3) = 1 v w(2, 3) = 1 v w(1, 2, 3) = 1 Φ +

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Reformulations Other axiomatic approaches have been provided for the Shapley value, of which we shall briefly describe those by Young and by Hart and Mas-Colell. PROPERTY 8 (Marginalism, MARG) A map Ψ : G N →IR N satisfies MARG if, given v,w G N, for any player i N s.t. v(S {i}) −v(S) = w(S {i}) −w(S) for each S 2 N, the following is true: Ψ i (v) = Ψ i (w). Theorem 2 (Young 1988) There is a unique map Ψ defined on G(N) that satisfies EFF, SYM, and MARG. Such a Ψ coincides with the Shapley value.

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.EXAMPLE Two TU-games v and w on N={1,2,3} v(1) =3 v(2) =4 v(3) = 1 v(1, 2) =8 v(1, 3) = 4 v(2, 3) = 6 v(1, 2, 3) = 10 w(1) =2 w(2) =3 w(3) = 1 w(1, 2) =2 w(1, 3) = 3 w(2, 3) = 5 w(1, 2, 3) = 4 w( {3})- w( ) = v( {3})- v( )=1 w({1} {3})- w({1}) = v({1} {3})- v({1})=1 w({2} {3})- w( ) = v({2} {3})- v( )=1 w({1,2} {3})- w({1,2}) = v({1,2} {3})- v({1,2)=1 Ψ 3 (v) = Ψ 3 (w).

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Potential A quite different approach was pursued by Hart and Mas-Colell (1987). To each game (N, v) one can associate a real number P(N,v) (or, simply, P(v)), its potential. The “partial derivative” of P is defined as D i (P )(N, v) = P(N,v)−P(N\{i},v |N\{i} ) Theorem 3 (Hart and Mas-Colell 1987) There is a unique map P, defined on the set of all finite games, that satisfies: 1)P( ∅, v 0 ) = 0, 2)For each i N, D i P(N,v) = v(N). Moreover, D i (P )(N, v) = i (v). [ (v) is the Shapley value of v]

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there are formulas for the calculation of the potential. For example, P(N,v)= S 2 N S /|S| ( Harsanyi dividends) Example v(1) =3 v(2) =4 v(3) = 1 v(1, 2) =8 v(1, 3) = 4 v(2, 3) = 6 v(1, 2, 3) = 10 1 (v) =3 2 (v) =4 3 (v) = 1 {1,2} (v) =1 {1,3} (v) =0 {2,3} (v) =1 {1,2,3} (v)= 0 P({1,2,3},v)=3+4+1+1/2+1/2=9 P({1,2},v)=3+4+1/2=15/2 P({1,3},v)=3+1=4 P({2,3},v)=4+1+1/2=11/2 1 (v)=P({1,2,3},v)-P({2,3},v |{2,3} )=9-11/2=7/2 2 (v)=P({1,2,3},v)-P({1,3},v |{2,3} )=9-4=5 3 (v)=P({1,2,3},v)-P({1,2},v |{2,3} )=9-15/2=3/2

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Yoram Bachrach Jeffrey S. Rosenschein November 2007.

Yoram Bachrach Jeffrey S. Rosenschein November 2007.

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