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Newton’s law of universal gravitation: where: F is the force of gravitation. m 1 and m 2 are the masses. r is the distance between the masses.  is the.

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Presentation on theme: "Newton’s law of universal gravitation: where: F is the force of gravitation. m 1 and m 2 are the masses. r is the distance between the masses.  is the."— Presentation transcript:

1 Newton’s law of universal gravitation: where: F is the force of gravitation. m 1 and m 2 are the masses. r is the distance between the masses.  is the gravitational constant that is equal to 6.67x Nm 2 kg -2. Units of F are N=kg m s -2. The basics Newton’s second law of motion: where: m is the mass. a is acceleration. By combining the universal law of gravitation with Newton’s second law of motion, one finds that the acceleration of m 2 due to its attraction by m 1 is:

2 Gravitational acceleration is thus: where: M E is the mass of the Earth. R E is the Earth’s radius. Units of acceleration are m s -2, or gal=0.01 m s -2. The basics The Earth is an oblate spheroid that is fatter at the equator and is thinner at the poles. There is an excess mass under the equator. Centrifugal acceleration reduces gravitational attraction. Thus, the further you are from the rotation axis, the greater the centrifugal acceleration is.

3 The basics From:

4 The basics g is a vector field: where r is a unit vector pointing towards the earth’s center. The gravitational potential, U, is a scalar field: Note that Earth’s gravitational potential is negative. Potentials are additive, and this property makes them easier (than vectors) to work with. To verify that U is the potential field of g take its derivative with respect to R. The gradient of a scalar field is a vector field.

5 Surface gravity anomalies due to some buried bodies The general equation is: where:  is the gravitational constant  is the density contrast r is the distance to the observation point  is the angle from vertical V is the volume Question: Why a cosine term? Solution for a sphere: z a x/z

6 An infinitely long horizontal cylinder cylindersphere The expression for a horizontal cylinder of a radius a and density  : It is interesting to compare the solution for cylinder with that of a sphere. This highlights the importance of a 2-D gravity survey. Surface gravity anomalies due to some buried bodies

7 What should be the spatial extent of the surveyed region? To answer this question it is useful to compute the anomaly half-distance, X 1/2, i.e. the distance from the anomaly maximum to it’s medium. For a sphere, we get: Surface gravity anomalies due to some buried bodies The signal due to a sphere buried at a depth Z can only be well resolved at distances out to 2-3 Z. Thus, to resolve details of density structures of the lower crust (say km), gravity measurements must be made over an extensive area.

8 The ambiguity of surface gravity anomalies In the preceding slide we have looked at the result of a forward modeling also referred to as the direct problem: In practice, however, the inverse modeling is of greater importance: Question: Can the data be inverted to obtain the density, size and shape of a buried body? Inspection of the solution for a buried sphere reveals a non-uniqueness of that problem. The term  a 3 introduces an ambiguity to the problem, and different combinations of densities and radii can produce identical anomalies.

9 1.Near surface very elongated body 2.Shallow elongated body 3.Deep sphere The same gravity anomaly may be explained by different anomalous bodies, having different shapes and located at different depths: measured gravity anomaly In summary, we want to know: But actually, gravity anomaly alone cannot provide this information. The ambiguity of surface gravity anomalies

10 The observed anomaly may be explained equally well with deep models with small density contrast or shallow models with greater density contrast. Question: is the MAR in isostatic equilibrium? Here’s an example from a Mid-Atlantic Ridge (MAR). The ambiguity of surface gravity anomalies

11 Geoid the observed equipotential surface that defines the sea level. the shape a fluid Earth would have if it had exactly the gravity field of the Earth roughly the sea-level surface - dynamic effects such as waves, and tides, must be excluded geoid on continents lies below continents - corresponds to level of nearly massless fluid if narrow channels were cut through continents geoid highs are gravity highs The geoid The vector gravity (g) is perpendicular to the geoid.

12 Reference geoid is a mathematical formula describing a theoretical equipotential surface of a rotating (i.e., centrifugal effect is accounted for) symmetric spheroidal earth model having realistic radial density distribution. The geoid The international gravity formula gives the theoretical gravitational acceleration on a reference geoid: observed geoid reference geoid

13 The geoid height anomaly is the difference in elevation between the measured geoid and the reference geoid. Note that the geoid height anomaly is measured in meters. The geoid

14 Geoid anomaly Map of geoid height anomaly: Note that: The differences between observed geoid and reference geoid are as large as 100 meters In continental regions, they do not correlate with topography because of isostatic compensation Figure from: Question: what gives rise to geoid anomaly?

15 Geoid anomaly Differences between geoid and reference geoid are due to: Topography Density anomalies at depth Figure from Fowler

16 Geoid anomaly Figure from McKenzie et al., 1980 Two competing effects: 1.Upwelling brings hotter and less dense material, the effect of which is to reduce gravity. 2.Upwelling causes topographic bulge, the effect of which is to increase gravity. What is the effect of mantle convection on the geoid anomaly? Flow Temp. upwellingdownwelling

17 Geoid anomaly SEASAT provides water topography Note that the most prominent features on most geoid maps (depending on filtering used) are subduction zones.

18 Geoid anomaly Free-air gravity anomaly from satellite altimetry for the Tonga-Kermadec region Comparison of topography along east west profiles across the subduction zone at 20, 25 and 30°S (thick/blue) to observed topography (thin/black) Cross-sections across subduction-zone geoid anomalies show an asymmetric anomaly low (trench) and an anomaly high (presence of cold, dense slab in lighter asthenospere): (From: Billen and Gurnis, EPSL, 2001)

19 Geoid anomaly GEOID99: a refined model of the geoid in the United States Heights range from a low of meters (magenta) in the Atlantic Ocean to a high of 3.23 meters (red) in the Labrador Strait

20 Geoid anomaly A model for mass change due to post-glacial rebound and the reloading of the ocean basins with seawater. Blue and purple areas indicate rising due to the removal of the ice sheets. Yellow and red areas indicate falling as mantle material moved away from these areas in order to supply the rising areas, and because of the collapse of the forebulges around the ice sheets.

21 Geoid anomaly and corrections Geoid anomaly contains information regarding the 3-D mass distribution. But first, a few corrections should be applied: Free-air (required) Bouguer (required) Terrain (optional)

22 Geoid anomaly and corrections Free-air correction,  g FA : This correction accounts for the fact that the point of measurement is at elevation H, rather than at the sea level on the reference spheroid.

23 Geoid anomaly and corrections Since: where: is the latitude h is the topographic height g( ) is gravity at sea level R( ) is the radius of the reference spheroid at The free-air correction is thus: This correction amounts to 3.1x10 -6 ms -2 per meter elevation. Question: should this correction be added or subtracted? The free-air anomaly is the geoid anomaly, with the free-air correction applied:

24 Geoid anomaly and corrections

25 Bouguer correction,  g B : This correction accounts for the gravitational attraction of the rocks between the point of measurement and the sea level. Geoid anomaly and corrections

26 An infinite horizontal slab of finite thickness: Note that the gravity anomaly caused by an infinite horizontal slab of thickness h and density  c is independent of its distance b from the observer. Geoid anomaly and corrections Setting  (y)=  c and integration with respect to r from zero to infinity and with respect to y between 0 and h leads to:

27 Geoid anomaly and corrections The Bouguer correction is: where:  is the universal gravitational constant  is the rock density h is the topographic height For rock density of 2.7x10 3 kgm -3, this correction amounts to 1.1x10 -6 ms -2 per meter elevation. Question: should this correction be added or subtracted? The Bouguer anomaly is the geoid anomaly, with the free-air and Bouguer corrections applied:

28 Geoid anomaly and corrections Terrain correction,  g T : This correction accounts for the deviation of the surface from an infinite horizontal plane. The terrain correction is small, and except for area of mountainous terrain, can often be ignored.

29 Geoid anomaly and corrections The Bouguer anomaly including terrain correction is: Bouguer anomaly for offshore gravity survey: Replace water with rock Apply terrain correction for seabed topography After correcting for these effects, the ''corrected'' signal contains information regarding the 3-D distribution of mass in the earth interior.

30 Isostasy The deflection of plumb-bob near mountain chains is less than expected. Calculations show that the actual deflection may be explained if the excess mass is canceled by an equal mass deficiency at greater depth. A plumb-bob Picture from wikipedia

31 Isostasy: the Airy hypothesis (application of Archimedes’ principal) Two densities, that of the rigid upper layer,  u, and that of the substratum,  s. Mountains therefore have deep roots. A mountain height h 1 is underlain by a root of thickness: Ocean basin depth, h 2, is underlain by an anti-root of thickness: r1r1 uu ss h1h1 r3r3 d

32 Ocean basin whose depth is h 2 is underlain by a high density material,  2, that is given by: Isostasy: the Pratt’s hypothesis The depth to the base of the upper layer is constant. The density of rocks beneath mountains is less than that beneath valleys. A mountain whose height is h 1 is underlain by a root whose density  1 is:

33 Isostasy Questions: Which is the correct hypothesis? Does isostatic equilibrium apply everywhere? Is the person resting on top of a spring-mattress in a state of isostatic equilibrium?

34 Isostasy: elastic flexure Like the springs inside the mattress, the elastic lithosphere can also support excess mass. Thick plates can support more excess mass than thin plates.

35 Isostasy: elastic flexure The response of the lithosphere to a vertical load depends on the lithosphere elastic properties as follows: where D is the flexural rigidity, that is given by: with: E being Young Modulus h being the plate thickness being Poisson’s ratio

36 Isostasy: elastic flexure The figure below shows the solution for the case of a line load: Note the flexural bulge on either side of the depression. Of course in reality the boundary conditions are more complex… Figure from Fowler

37 Isostasy: example from the Hawaii chain bathymetry free-air Two effects: Elastic flexure due to island load. A swell due to mantle upwelling. Figure from Fowler

38 Isostasy: example from the Mariana subduction zone deflection [km] distance [km] The accretionary wedge loads the plate edge causing it to bend. A flexural bulge is often observed adjacent to the trench. Topography of Mariana bulge implies a 28 km thick plate. Fluxural bulge Figure from Fowler

39 Isostasy example from the Tonga subduction zone deflection [km] distance [km] The Tonga slab bends more steeply than can be explained by an elastic model. It turned out that an elastic-plastic model for the lithosphere can explain the bathymetry data. Figure from Fowler

40 Isostasy: local versus regional isostatic equilibrium According to Pratt and Airy hypotheses, excess mass is perfectly compensated everywhere. This situation is referred to as local isostasy. The situation where some of the load is supported by the strength of the lithosphere is referred to as regional isostasy. In this case, isostatic equilibrium occurs on a larger scale, but not at any point.

41 Isostasy Questions: 1.Isostatic equilibrium means no excess mass. Does this mean no gravitational anomaly. 2.Can we distinguish compensated from uncompensated topographies?

42 Isostasy: gravity 100% compensated A rule of thumb: A region is in isostatic equilibrium if the Bouguer anomaly is a mirror image of the topography. Figure from Fowler

43 Isostasy: gravity Uncompensated A rule of thumb: A region is NOT in isostatic equilibrium if the Bouguer anomaly remains flat under topographic highs and lows. Figure from Fowler

44 Isostasy: isostatic rebound Figure from Fowler The rate of isostatic rebound depends on the elastic properties of the lithosphere (including its thickness) as well as the mantle viscosity. Isostatic rebound can be observed if a large enough load has been added or removed fast enough.

45 Small loads, a few km in diameter, can tell us about the elastic properties of the crust. Isostasy: isostatic rebound The Dead Sea, Israel: During the past few decades, the Dead Sea water-level is dropping at a rate of 1 m/yr.

46 Isostasy: isostatic rebound Data Model Residual Ground displacement due to water-level changes can be reproduced using a homogeneous elastic half-space model.

47 Medium size loads, say ~100 km diameter, can tell us about the viscosity of the asthenosphere. Isostasy: isostatic rebound Lake Bonneville, Utha: A lake 300 m deep dried up 10,000 years ago. Lake center has risen by 65 m. shoreline Images from:

48 Fennoscandia: Removal of 2.5 km thick ice at the end of the last ice age 10,000 years ago. Current peak uplift rate is 9 mm/yr. Large loads, say ~1000 km diameter tell us about the upper and lower mantle viscosity. Isostasy: isostatic rebound Great Britain: Glaciation affected Scotland, but not Southern England. Uplift rate of up to 10cm per century.

49 Dipole moment of density anomaly: dipole moment of density distribution We have seen that the gravity anomaly due to a horizontal layer of thickness y is: thus the gravity potential of this layer is: The dipole moment of density distribution is just: We shall see that it is the dipole moment of density distribution, which contains information regarding the mass distribution, and may help to discriminate between the two isostatic models.

50 Dipole moment of density anomaly: gravity potential Combining this with the expression for the gravity potential of a Bouguer slab (see previous slide) leads to: U=U obs U=U ref

51 Dipole moment of density anomaly: Airy versus Pratt Airy (positive topography): Pratt (positive topography): In areas of isostatic equilibrium, we would wish to know whether mass is distributed according to Airy or Pratt models.

52 Dipole moment of density anomaly: Airy versus Pratt Pratt (positive topography): Replacing with leads to: Note the linear relation between  N and h. +y

53 Dipole moment of density anomaly: Airy versus Pratt Airy (positive topography): +y Replacing with leads to: Note the NON-LINEAR relation between  N and h.

54 Dipole moment of density anomaly: Airy versus Pratt Pratt Airy  N versus h for Airy and Pratt models. Airy model implies a nearly factor of 3 difference between  N/h on-land and off- shore. Figure from Turcotte and Schubert

55 At what direction does the Pacific plate moves? Dipole moment of density anomaly: Airy versus Pratt

56 Figure from Turcotte and Schubert Dependence of the observed geoid anomaly on bathymetry across the Hawaiian swell and across the Bermuda swell compared with the predicted anomaly according to Airy and Pratt models. Fair (or good?) agreement is obtained for Pratt model with a compensation depth of 100 km. If we accept the Pratt model to be applicable, the conclusion is that the mantle rocks beneath these swells have anomalously low density down to a depth of 100 km.

57 Further reading: * Turcotte, D. L. and G. Schubert, Geodynamics, Cambridge University Press. * Fowler, C. M. R., The solid Earth, Cambridge University Press.

58 Dipole moment of density anomaly: Airy versus Pratt A comparison between Airy-predicted and measured geoid anomaly across the Atlantic continental margin of N. America. It follows from this comparison that the continental margin is in a state of isostatic equilibrium according to Airy model. Figure from Turcotte and Schubert

59 Practical issues (This lecture is based largely on: The shape of the gravity anomaly depends not on the absolute density, but on the density contrast, i.e. the difference between the anomalous density and the “background density”.

60 Practical issues Here’s a list of densities associated with various earth’s materials: material1000 kg/m 3 sediments sandstone shale limestone granite basalt metamorphic Note that: Density differences are quite small. There's considerable overlap in the measured densities.

61 Practical issues Consider the variation in gravitational acceleration due to a spherical ore body with a radius of 10 meters, buried at a depth of 25 meters below the surface, and with a density contrast of 500 kg per meter cubed. The maximum anomaly for this example is mGal. (keep in mind that 9.8 m/s 2 is equal to 980,000 mGal !!!)

62 Practical issues Owing to the small variation in rock density, the spatial variations in the observed gravitational acceleration caused by geologic structures are quite small A gravitational anomaly of mGal is very small compared to the 980,000 mGals gravitational acceleration produced by the earth as a whole. Actually, it represents a change in the gravitational field of only 1 part in 40 million. Clearly, a variation in gravity this small is going to be difficult to measure.

63 Practical issues How is gravity measures: Falling objects Pendulum Mass on a spring

64 Practical issues Falling objects: The distance a body falls is proportional to the time it has fallen squared. The proportionality constant is the gravitational acceleration, g: g = distance / time 2. To measure changes in the gravitational acceleration down to 1 part in 40 million using an instrument of reasonable size, we need to be able to measure changes in distance down to 1 part in 10 million and changes in time down to 1 part in 10 thousands!! As you can imagine, it is difficult to make measurements with this level of accuracy.

65 Practical issues Pendulum measurements: The period of oscillation of the pendulum, T, is proportional to one over the square root of the gravitational acceleration, g. The constant of proportionality, l, is the pendulum length: Here too, in order to measure the acceleration to 1 part in 50 million requires a very accurate estimate of the instrument constant l, but l cannot be determined accurately enough to do this.

66 Practical issues But all is not lost: We could measure the period of oscillation of a given pendulum by dividing the time of many oscillations by the total number of oscillations. By repeating this measurement at two different locations, we can estimate the variation in gravitational acceleration without having to measure l.

67 Practical issues Mass on a spring measurements: The most common type of gravimeter used in exploration surveys is based on a simple mass- spring system. According to Hook’s law: X = mg / k, with k being the spring stiffness.

68 Practical issues Like pendulum the measurements, we can not determine k accurately enough to estimate the absolute value of the gravitational acceleration to 1 part in 40 million. We can, however, estimate variations in the gravitational acceleration from place to place to within this precision. Under optimal conditions, modern gravimeters are capable of measuring changes in the Earth's gravitational acceleration down to 1 part in 1000 million.

69 Practical issues Various undesired factors affect the measurements: Temporal (time-dependent) variations: 1.Instrumental drift 2.Tidal effects Spatial variations: 1.Latitude variations 2.Altitude variations 3.Slab effects 4.Topography effect

70 Practical issues Instrumental drift: The properties of the materials used to construct the spring change with time. Consequently, gravimeters can drift as much as 0.1 mgal per day. What causes the oscillatory changes superimposed on the instrumental drift?

71 Practical issues Tidal effect: In this example, the amplitude of the tidal variation is about 0.15 mGals, and the amplitude of the drift appears to be about 0.12 mGals over two days. These effects are much larger than the example gravity anomaly described previously.

72 Practical issues Since changes caused by instrumental drift and tidal effects do not reflect the mass distribution at depth, they are treated as noise. Strategies to correct for instrumental drift and tidal effects are discussed in:

73 Practical issues Regional and local (or residual) gravity anomalies: Consider a spherical ore body embedded in a sedimentary unit on top of a (denser) Granitic basement that is dipping to the right.

74 Practical issues The strongest contribution to the gravity is caused by large-scale geologic structure that is not of interest. The gravitational acceleration produced by these large-scale features is referred to as the regional gravity anomaly.

75 Practical issues The second contribution is caused by smaller- scale structure for which the survey was designed to detect. That portion of the observed gravitational acceleration associated with these structures is referred to as the local or the residual gravity anomaly.

76 Practical issues There are several methods of removing unwanted regional gravity anomalies. Here's an example for a graphical approach: Smoothing in 1 dimension Smoothing in 2 dimensions

77 Practical issues Variations in gravity around the globe are inferred from satellite orbit. The balance between the gravitational attraction and the centrifugal force is written as: This leads to: where T is the satellite’s period, 2  r / V.

78 Practical issues Yet, the highest resolution whole earth gravity maps are derived from radar measurement of the height of the sea surface.

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