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Published byKody Petitt Modified over 2 years ago

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**Unit 1 Day 16: Electric Potential due to any Charge Distribution**

Electric Field due to a single point charge Electric Potential of a ring of charge Electric Potential due to a charged disk

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**Electric Potential of a Single Point Charge**

The electric potential due to a single point charge is: In a region where there is a distribution of electric charge, we can sum over all the individual point charges, relative to some point a: If the charge distribution is continuous, then:

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**Electric Potential of a Ring of Charge**

A thin circular ring which has a uniformly distributed charge Q, the electric potential at point P on the axis of the ring is: For x>>R, this result reduces to:

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**Electric Potential due to a Charged Disk**

A thin, flat disk of radius R0, having A uniformly distributed charge Divide the disk into thin rings of Radius R, and thickness dR, so we Can use the previous result. The disk is uniformly charged (Q), So that the charge contained in each Ring is proportional to its area. For x>>R0:

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The approximation becomes exact if we let the number of chunks go to infinity and the volume of each chunk go to zero – the sum then becomes an integral:

The approximation becomes exact if we let the number of chunks go to infinity and the volume of each chunk go to zero – the sum then becomes an integral:

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