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1 Power of DOE Some simple examples using 2- level factorials.

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Presentation on theme: "1 Power of DOE Some simple examples using 2- level factorials."— Presentation transcript:

1 1 Power of DOE Some simple examples using 2- level factorials

2 2 Newton’s Law of Motion Consider Newton’s Law of motion: F = m.a If nature knows this relationship but we don’t, how can we obtain the relationship without years of theoretical research? Let’s try to do it by experiment using the 2 factors mass (m) and acceleration (a) as input factors. The response is the Force (F).

3 3 Experimental Design 2-level, 2 factors or 2 2 full factorial design Inputs: M: 5, 10; A: 100, 200 RunMAAvg. Force

4 4 Analysis Using a sign table: Runmam x aForce Overall average Force = 1125 [m] = (1500)-(750) = 750, [a] = (1500) – (750) = 750 [m.a] = (1250) – (1000) = 250

5 5 Regression Equation F = m a m.a Now we need to convert the coded values into actual values M = (m + + m - )/2 + (m + - m - )/2 x m i.e. M = x m Or m = (M -7.5)/2.5 Likewise for the other terms

6 6 Substituting the actual transformed values into the regression equation, F = (M-7.5)/ (A-150)/ (M-7.5)/2.5 x (A-150)/50 Simplifying, F = M.A Imagine how quickly Newton would have closed the knowledge gap if he knew DOE!


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