Presentation is loading. Please wait.

Presentation is loading. Please wait.

Slide 1 of 30 Chemistry 12.1. © Copyright Pearson Prentice Hall Slide 2 of 30 The Arithmetic of Equations More than 3000 cocoons are needed to produce.

Similar presentations


Presentation on theme: "Slide 1 of 30 Chemistry 12.1. © Copyright Pearson Prentice Hall Slide 2 of 30 The Arithmetic of Equations More than 3000 cocoons are needed to produce."— Presentation transcript:

1 Slide 1 of 30 Chemistry 12.1

2 © Copyright Pearson Prentice Hall Slide 2 of 30 The Arithmetic of Equations More than 3000 cocoons are needed to produce enough silk to make just one elegant Japanese kimono. Like silk manufacturers, chemists must know how much reactant they need to make a certain amount of product. Determining the quantities of reactants and products in a reaction requires a balanced chemical equation. 12.1

3 © Copyright Pearson Prentice Hall Slide 3 of 30 > The Arithmetic of Equations > Using Everyday Equations How is a balanced equation like a recipe? 12.1

4 Slide 4 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Using Everyday Equations A balanced chemical equation provides the same kind of quantitative information that a recipe does. 12.1

5 Slide 5 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Using Everyday Equations An equation can represent the manufacturing of a single tricycle. 12.1

6 © Copyright Pearson Prentice Hall Slide 6 of 30 > The Arithmetic of Equations > Using Balanced Chemical Equations How do chemists use balanced chemical equations? 12.1

7 Slide 7 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Using Balanced Chemical Equations Chemists use balanced chemical equations as a basis to calculate how much reactant is needed or product is formed in a reaction. The calculation of quantities in chemical reactions is a subject of chemistry called stoichiometry. 12.1

8 © Copyright Pearson Prentice Hall SAMPLE PROBLEM Slide 8 of

9 © Copyright Pearson Prentice Hall SAMPLE PROBLEM Slide 9 of

10 © Copyright Pearson Prentice Hall SAMPLE PROBLEM Slide 10 of

11 © Copyright Pearson Prentice Hall SAMPLE PROBLEM Slide 11 of

12 © Copyright Pearson Prentice Hall Practice Problems Slide 12 of 30 for Sample Problem 12.1 Problem Solving 12.1 Solve Problem 1 with the help of an interactive guided tutorial.

13 © Copyright Pearson Prentice Hall Slide 13 of 30 > The Arithmetic of Equations > Interpreting Chemical Equations In terms of what quantities can you interpret a balanced chemical equation? 12.1

14 Slide 14 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations A balanced chemical equation can be interpreted in terms of different quantities, including numbers of atoms, molecules, or moles; mass; and volume. 12.1

15 Slide 15 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations Number of Atoms 12.1

16 Slide 16 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations Number of Molecules 12.1

17 Slide 17 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations Moles 12.1

18 Slide 18 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations Mass 12.1

19 Slide 19 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations Volume 12.1

20 Slide 20 of 30 © Copyright Pearson Prentice Hall > The Arithmetic of Equations Interpreting Chemical Equations 12.1

21 © Copyright Pearson Prentice Hall Slide 21 of 30 > The Arithmetic of Equations > Mass Conservation in Chemical Reactions What quantities are conserved in every chemical reaction? 12.1

22 © Copyright Pearson Prentice Hall Slide 22 of 30 > The Arithmetic of Equations > 12.1 Mass Conservation in Chemical Reactions Mass and atoms are conserved in every chemical reaction.

23 © Copyright Pearson Prentice Hall Slide 23 of 30 Conceptual Problem 12.1

24 © Copyright Pearson Prentice Hall Slide 24 of 30 Conceptual Problem 12.1

25 © Copyright Pearson Prentice Hall Slide 25 of 30 Conceptual Problem 12.1

26 © Copyright Pearson Prentice Hall Practice Problems Slide 26 of 30 for Conceptual Problem 12.1 Problem Solving 12.4 Solve Problem 4 with the help of an interactive guided tutorial.

27 © Copyright Pearson Prentice Hall Section Quiz -or- Continue to: Launch: Assess students’ understanding of the concepts in Section Slide 27 of Section Quiz

28 © Copyright Pearson Prentice Hall Slide 28 of Section Quiz. 1.A manufacturer of bicycles has 5350 wheels, 3023 frames, and 2655 handlebars. How many bicycles can be manufactured using these parts? a.2675 bicycles b.2655 bicycles c.3023 bicycles d.5350 bicycles

29 © Copyright Pearson Prentice Hall Slide 29 of 30 2.A reaction that produces iron metal from iron ore is shown below. Fe 2 O 3 H 2 O(s) + 3CO(g)  2Fe(s) + 3CO 2 (g) + H 2 O(g) In this equation, the volume of gas at STP that reacts and the volume of gas at STP produced will be a.3 L and 4 L. b.67.2 L and 89.6 L. c.67.2 L and 67.2 L d.3 L and 3 L 12.1 Section Quiz.

30 © Copyright Pearson Prentice Hall Slide 30 of 30 3.What is conserved in the reaction shown below? H 2 (g) + Cl 2 (g)  2HCl(g) a.only mass b.only mass and number of moles c.only mass, number of moles, and number of molecules d.mass, number of moles, number of molecules, and volume 12.1 Section Quiz.

31 END OF SHOW


Download ppt "Slide 1 of 30 Chemistry 12.1. © Copyright Pearson Prentice Hall Slide 2 of 30 The Arithmetic of Equations More than 3000 cocoons are needed to produce."

Similar presentations


Ads by Google