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Published byChase Ashwill Modified over 2 years ago

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Mrs. Rivas

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Then substitute to answer the question. Mrs. Rivas

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4x – 1 2x x + 8 X = 3 m ∠ AOB = 4x – 1 = 4(3) – 1= 11 m ∠ BOC = 2x + 15 = 2(3) + 15 = 21 m ∠ AOC = 8x + 8 = 8(3) + 8 = 32 Mrs. Rivas

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8x x – 10 Then substitute to answer the question. Mrs. Rivas

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8x x – 6 3x – 10 X = 9 m ∠ BOC = 3x – 10 = 3(9) – 10= 17 m ∠ COD = 8x + 13 = 8(9) + 13= 85 m ∠ BOD = 12x – 6 = 12(3) – 6 = 102 Mrs. Rivas

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Always read the question and draw a picture. A B C E F 2x x + 8 3x + 8 = 2x + 48 – 8 3x = 2x + 40 – 2x x = 40 3(40) + 8 = 1282(40) + 48 = 128 Mrs. Rivas

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Always read the question and draw a picture. J K L 2x – 3 N P M 5x + 2 2x – 3 + 5x + 2 = 90º 7x – 1 = 90º + 1 7x = 91º 77 x = 13º 2(13) – 3 = 23 5(13) + 2 = 67 Mrs. Rivas

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Always read the question and draw a picture. J K M L 86 If ∠ JKM = 86 then ∠ MKL = 86, so ∠ JKL has to be equal to = 172. Mrs. Rivas

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Always read the question and draw a picture. R S V T 62 Since bisect means cut in half. Then, m ∠ RSV = 62 ÷ 2 = 31 Mrs. Rivas

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P Q S R 3x3x 5x – 20 Always read the question and draw a picture. 3x = 5x – 20 – 5x 3(10) = 30 – 2x = – x = 10 5(10) – 20 = 30 So, m ∠ PQR = = 60 Mrs. Rivas

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Always read the question and draw a picture. P Q S R 2x + 1 4x – 15 2x + 1 = 4x – 15 – 4x – 2x = – x = 8 – 1 2x = 4x – 16 2(8) + 1 = 174(8) – 15 = 17 So, m ∠ PQR = = 34 Mrs. Rivas

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Always read the question and draw a picture. P Q S R 3x – = 3x – = 3x 33 x = = 3x – 12 3(24) – 12 = 60 Mrs. Rivas

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Always read the question and draw a picture. P Q S R 2x x – 17 2x + 10 = 5x – 17 – 5x – 3x = – x = 9 – 10 2x = 5x – 27 2(9) + 10 = 285(9) – 17 = 28 So, m ∠ PQR = = 56 Mrs. Rivas

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Always read the question and draw a picture. 7x – 1 + 4x + 3 = 90º 11x + 2 = 90º – 2 11x = 88º 11 x = 8 m ∠ MLN = 7(8) – 1 = 55 m ∠ JKL = 4(8) + 3 = 35 a ). b). c). I can check the answer by adding 55 and 35, and it should be 90º = 90º Mrs. Rivas

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