How much heat is needed to convert 250 grams of ice at -30 o C to vapor at 150 o C? 1. Change temp of ice 2. Melt ice 3. Change temp of liquid water 4. Vaporize water 5. Change temp of vapor 6. Add total heat used
Step 1 raise temp of ice q = m T C p q = (250g) (30 C o ) (2.06 J/g. C o ) q = 15,450 Joules
Step 2 melt ice q = m H fus q = (250g) (334 J/g) q = 83,500 Joules
Step 3 raise temp of liquid water q = m T C p q = (250g) (100 C o ) (4.18 J/g. C o ) q = 104,500 Joules
Step 4 vaporize liquid water q = m H vap q = (250g) (2260 J/g) q = 565,000 Joules
Step 5 raise temp of water vapor q = m T C p q = (250g) (50 C o ) (2.02 J/g. C o ) q = 25,250 Joules
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