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Mixture Applications Example 1: Susan would like to mix a 10% acid solution with a 40% acid solution to make 20 ounces of a 30% acid solution. How much of each should she mix.

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1) Variable declaration: Let x represent the amount of the 10% solution The desired amount of 30% solution is 20 ounces. The amount of 40% solution is (20 – x) ounces.

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2) Write the equation

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3) Solve the equation:

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x = amount of the 10% solution 4) Write an answer in words, explaining the meaning in light of the application Susan needs approximately 6.7 oz. of the 10% solution.

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20 - x = amount of the 40% solution Susan needs approximately 13.3 oz. of the 40% solution.

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Mixture Applications Example: 2 Al would like an 8% iodine solution, but only has a 5% and a 20% solution on hand. How much of the 5% solution should he mix with 6 ml of the 20% solution to get the 8% solution. Make a drawing of the situation:

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1) Variable declaration: Let x represent the amount of the 5% solution The given amount of 20% solution is 6 ml. The amount of 8% solution is (x+6) ml.

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2) Write the equation

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3) Solve the equation:

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x = amount of the 5% solution 4) Write an answer in words, explaining the meaning in light of the application Al needs 24 ml of the 5% iodine solution to mix with the 6 ml of 20% iodine solution to get an 8% solution.

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Solving Mixture Problems One variable equations. The Problem A chemist has 20 ml of a solution that is 60% acid. How much 15% acid solution must she add.

Solving Mixture Problems One variable equations. The Problem A chemist has 20 ml of a solution that is 60% acid. How much 15% acid solution must she add.

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