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Published byCorinne Bates Modified over 2 years ago

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Latent Heat Materials can also go through a change in state called a phase change. Changes between solid, liquid, gaseous and plasma states. Energy Is required for these changes, but during this process the temperature of the material will not change. These changes typically occur at specific temperatures. The amount of heat required for a phase transition is given by: Q – Heat [J] L – Latent Heat [J/kg] M – mass [kg]

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Latent Heat values for selected substances.

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Example: 10 kg of ice at 0 o C is dropped into a steam chamber at 100 o C. How much steam is converted to water at 100 o C? The negative sign on the mass is acceptable here since it represents the mass of steam that was lost (converted to water).

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You have two containers of water. The first container has 200 g of water at 80 o C and the second container has 200 g of water at 20 o C. If the water in the two containers is mixed, what would the equilibrium temperature be for this mixture? 1.T > 80 °C 2.T 80 °C 3.50 °C ≤ T ≤ 80 °C 4.T 50 °C 5.20 °C ≤ T ≤ 50 °C 6.T 20 °C 7.T < 20 °C

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You have two containers of water. The first container has 200 g of water at 80 o C and the second container has 100 g of water at 20 o C. If the water in the two containers is mixed, what would the equilibrium temperature be for this mixture? 1.T > 80 °C 2.T 80 °C 3.50 °C ≤ T ≤ 80 °C 4.T 50 °C 5.20 °C ≤ T ≤ 50 °C 6.T 20 °C 7.T < 20 °C T = 60 o C

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You have one container of water. The container has 200 g of water at 20 o C. If a 200 g lead slug at 80 o C is dropped into the water, what would the equilibrium temperature be for this mixture? 1.T > 80 °C 2.T 80 °C 3.50 °C ≤ T ≤ 80 °C 4.T 50 °C 5.20 °C ≤ T ≤ 50 °C 6.T 20 °C 7.T < 20 °C T 22 o C

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Heat Examples Heat up Water from 21C to 95C m = 1 kg c = 4180 Q = mc T Q = (1)(4180)(95 – 21) Q = 309,320 Joules.

Heat Examples Heat up Water from 21C to 95C m = 1 kg c = 4180 Q = mc T Q = (1)(4180)(95 – 21) Q = 309,320 Joules.

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