2Electrical Forces vs Gravity Strong – Some can produce accelerations more than gravityRepulsive or attractive where as gravity is always attractiveHenry Cavendish showed that electrical forces obey an inverse square lawDid not publish work and was found a century later
3Forces on Charged BodyCharged objects do not necessarily need to be touching (long range force)The electrical forces is summarized…1) Two kinds of charges: Positive and Negative2) Charges exert force over a distance3) Force is stronger when charges are close together4) Like charges repel, Opposite Charges attract
4Electroscope Metal knob with metal stem and two thin metal leaves Enclosed to be away from outside influence
5Charging by conduction For conduction, objects have to be _____________When touching the ball on the electroscope, the charges are spread all through the metal causing the leaves to _____________
6Charging by conduction How can you determine whether electroscope is positively charged or negatively charged?Bring a known charge to the endLeaves spread further apart if same charge is appliedLeaves fall slightly if opposite charge is applied
7Charging by Induction Charging an object without touching it When charged object is brought close, the neutral charged item brings the opposite charge close and alike charges move away
9Coulomb’s Law Charges will push or pull on another Force depends on size of charge and distance of separationExperiment was designed by French physicist Charles Coulomb
10Coulomb’s Law Symbol for charge is q Force is varied inversely with the square distanceF = 1 / d2Force is varied directly with the charge of the bodiesF = qAqB
11The Coulomb SI unit of charge is the coulomb (C) Coulombs Law Symbol to represent charge is (q)Coulombs LawF = K (qAqB / d2)K = 9.0 x 109 Nm2/C2One Coulomb is the charge of 6.24 x 1018 electrons – about the charge going thru a 100 watt light bulb in about 1 second.
12Newton’s Third LawThe equation gives the magnitude of the force that charges exert on each other.Forces are equal in magnitude but opposite in direction
13Problem Solving Strategy for Electrical Force Problems 1) Sketch the System showing all distances and angles to scale (diagram the vectors of the system)2) Use Coulomb’s Law to find the magnitude of the force3) Use your diagram along with trig relations to find the direction of the force4) Perform all algebraic operations on units as well as numbers
14ProblemTwo Charges are separated by 3.0 cm. Object A has a charge of +6.0 µC, while object B has a charge of +3.0 µC. What is the force on object A?qA = +6.0 µCqB = +3.0 µCdAB = m
15F B on A = K (qAqB / dAB2)= (9.0 e9 Nm2/C2) x (6.0 µC)(3.0 µC) / (0.30 m)2F B on A = 1.8 x 102 N in +x direction
16ProblemTwo charges are separated by an unknown distance. Object A has a +4.5 µC and Object B has a -7.5 µC. If the attractive force of A on B is 250 N, what is the distance that the two Objects are spaced?