Download presentation

Presentation is loading. Please wait.

Published byMegan Kent Modified over 3 years ago

1
Equations as Relations By: Cathy Miller Bartlett High School Lesson for Glencoe Algebra I Math Section 4-4 Algebra I Glencoe Mathematics 2004 The McGraw Hill Companies Inc.

2
Ways to write a relation Set of ordered pairs Table Mapping Graph Equation in two variables

3
New Vocabulary Equation in Two Variables – Equations with 2 different variables. Solution to Equation in Two Variables – any point that makes a true statement when you substitute the x and y values into the equation.

4
Solve Using a Replacement Set Replacement set = a set of possible solutions. Substitute the points to find the true solutions… these are the ones that make the equation true. Solution set = the set of true solutions.

5
Solve -3x+y=7 if the replacement set is {(-5,0),(-3,-2),(2,13),(4,19)} x y-3x+y= (-5)+(0)=7 15 = 7 -3(-3)+(-2)=7 7=7

6
Solve -3x+y=7 if the replacement set is {(-5,0),(-3,-2),(2,13),(4,19)} x y-3x+y= (2)+(13)=7 7=7 -3(4)+(19)=7 7=7

7
Solve y=7+3x if the replacement set is {(-5,0),(-3,-2),(2,13),(4,19)} Solution set = {(-3,-2),(2,13),(4,19)}

8
Solve Using a Given Domain Domain = the xs for your solution setlthat you can use Substitute the xs to find their ys. Solution set = the set (x,y)s

9
Solve 9x+3y=15 if the domain is { 0,1,2,3} First…solve the equation for y

10
Solve 9x+3y=15 if the domain is { 0,1,2,3} xy=-3x y=-3(0)+5 y y=-3(1)+5 = 5 = 2

11
Solve 9x+3y=15 if D={ 0,1,2,3} x y=-3x y=-3(0)+5 y y=-3(1)+5 = 5 = 2 2 y=-3(2)+5 = -1 3 y=-3(3)+5 = -4 Sol. Set={(0,5),(1,2),(2,-1),(3,-4)|

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google