# Carpentry & Joinery Phase 4 Module 1 Unit 12 Transformation of Formula m³ √ ? Sample Questions & Solutions.

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Carpentry & Joinery Phase 4 Module 1 Unit 12 Transformation of Formula m³ √ ? Sample Questions & Solutions

Carpentry & Joinery Phase 4 Module 1 Unit 12 Question In the diagram below, Transform the relevant formula to determine the width(W) showing clearly how the formula is changed in order to determine the unknown quantity L = 6m WA (area) = 18m²

Carpentry & Joinery Phase 4 Module 1 Unit 12 Answer A = L x W A ÷ L = W W = A ÷ L W = 18 ÷ 6 3m W = 3m L = 6m WA (area) = 18m²

Carpentry & Joinery Phase 4 Module 1 Unit 12 Question Given the circumference of a circle as 22m, find its area, clearly showing the application of the formula. Keep answers to two decimal points in each step of the formula

Carpentry & Joinery Phase 4 Module 1 Unit 12 Answer C = π x D 22 = 3.142 x D D = 22 ÷ 3.142 D = 7 r = 7 ÷ 2 r = 3.5 A = πr² A = 3.142 x 3.5² A = 3.142 x 12.25 38.48m² A = 38.48m²

Carpentry & Joinery Phase 4 Module 1 Unit 12 Question For the triangle given below, Transform the formula to find H. The answer must include the necessary changes to the formula needed to reach a conclusion B = 10m A (area) = 25m² H

Carpentry & Joinery Phase 4 Module 1 Unit 12 Answer A = B x H 2 25 = 10 x H 2 25 x 2 = 10 x H 10 x H = 50 H = 50 ÷ 10 H = 5 B = 10m A (area) = 25m² H

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