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Mr. Samaniego Lawndale High. How many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen? mol = ? (NH 3 ) 0.60 mol N 2 N 2 +

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Presentation on theme: "Mr. Samaniego Lawndale High. How many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen? mol = ? (NH 3 ) 0.60 mol N 2 N 2 +"— Presentation transcript:

1 Mr. Samaniego Lawndale High

2 How many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen? mol = ? (NH 3 ) 0.60 mol N 2 N 2 + H 2 NH mol N 2 = 1.2 mol NH 3

3  Balanced equations are necessary to find the amount of product or reactant needed in a chemical reaction. Cu + O 2 CuO

4 Calculate the number of grams of NH 3 produced by the reaction of 5.40 g of hydrogen with an excess of nitrogen. The balanced equation is mass = ? (NH 3 ) 5.40 g H 2 N 2 + H 2 NH g H 2 = 30.4 g NH 3

5 Lithium nitride reacts with water to form ammonia and aqueous lithium hydroxide. a. What mass of water is needed to react with 32.9 g of Li 3 N? Li 3 N + 3H 2 O NH 3 + 3LiOH b. When the above reaction takes place, how many molecules of NH 3 are produced? c. Calculate the number of grams of Li 3 N that must be added to an excess of water to produce 15.0 L of NH3 (at STP).

6  Pages : 6-14 (skip 11a). (12/14/11, 12/15/11)

7 A + B C grams of A to grams of C: grams A  mol A  mol C  grams C mol of A to grams of C: mol A  mol C  grams C mol of A to mol of C: mol A  mol C grams of A to mol of C: grams A  mol A  mol C

8 Calculate the number of grams of H 2 O produced by the reaction of 12.5 g of nitrogen monoxide with an excess of ammonia. The balanced equation is mass = ? (H 2 O) 12.5 g NH 3 4NH 3 + 6NO 5N 2 + 6H 2 O 12.5 g NH 3 = 19.8 g H 2 O

9 How many molecules of oxygen are produced when 29.2 g of water is decomposed by electrolysis according to this balanced equation? molecules = ? (O 2 ) 29.2 g H 2 O 2H 2 O 2H 2 + O g H 2 O = 4.88x10 23 molecules O 2 After Ch 12 Quiz

10 Nitrogen monoxide and oxygen gas combine to form the brown gas nitrogen dioxide, which contributes to photochemical smog. How many liters of nitrogen dioxide are produced when 34 L of oxygen reacts with an excess of nitrogen monoxide? STP.) vol O 2 = 34 L vol = ? (NO 2 ) 2NO + O 2 2NO 2 34 L O 2 = 68 L NO 2 Remember: 1 mol = 22.4

11 Assuming STP, how many milliliters of oxygen are needed to produce 20.4 mL SO 3 according to this balanced equation? vol SO 3 = 20.4 mL vol = ? (mL O 2 ) 2SO 2 + O 2 2SO mL SO 3 = 10.2 mL O 2 Remember: 1 mol = 22.4


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