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Published byMelany Frederick Modified over 2 years ago

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Thevenin, Norton and Maximum Power Transfer Theorems

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Why Thevenin’s Theorem is useful

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Everything in the original circuit, except the load, maybe replaced by an equivalent circuit. The equivalent circuit consists of a series combination of a voltage source and a resistance.

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Write these on white board

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R TH = 5k Ω

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V TH = 10V

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Now you can place any load in the circuit you want and the calculations are EASY! =10k Ω.66mA

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Solving for V TH 10V 5V V TH = V A – V B = 5V Determine V TH

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Determine R TH

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What is the resistance from point a to b?

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Everything in the original circuit, except the load may be replaced by an equivalent circuit. The equivalent circuit consists of a parallel combination of a current source and a resistance.

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2mA Norton Current I N Norton Resistance

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There are a bunch of rules for how to calculate the Norton Current and Norton Resistance. However, a shortcut is to find the Thevenin Equivalent circuit and then convert it to a Norton

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2mA

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Besides using traditional circuit analysis using Ohm’s Law, or Superposition, Mesh Analysis, Thevenin’s Theorem, and Norton’s Theorem, there are other circuit analysis techniques. A couple include: Nodal Analysis and Millman’s Theorem Do more hw problems from back of chap 12 (9, 10, 11, or 12) if time

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In the following circuit solve for V TH, R TH, I N, R N, I L and V L

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Solve for V L using traditional Ohm’s Law technique, Mesh Analysis, and Thevenin Analysis

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See notes

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R L (Ω)0V T (V)I (A)P L (W)P i (W)P T (W)Eff (%)

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? What circuit analysis technique can we use to solve for this? Thevenin’s Theorem.R TH = 5k Ω 6kOhm I’ve checked this technique using Ohm’s law and it works. See following numbers:

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SPST SPDTDPST DPDT

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