Presentation on theme: "Keq vs. Q Javell, Shantell, Akosua"— Presentation transcript:
1Keq vs. Q Javell, Shantell, Akosua EQUILIBRIUMKeq vs. QJavell, Shantell, Akosua
2Keq Facts Keq is the constant equilibrium. Keq is a part of the Law of Mass Action which expresses the relative concentrations of reactants and products at equilibrium in terms of a quantity.Keq is the constant equilibrium.
3Keq RULESTo find the Keq of a molecule put the products over the reactants.The Keq or the equilibrium expression is written with symbols of the elements that’s on the periodic table.Raised powers indicate coefficients, and square brackets are used to denote concentration.aA+bB ----> cC+dD[C]^c[D]^dKeq=[A]^a[B]^b
4Example of Keq Equation What is the equilibrium expression for this reaction ? 2CO (g) + O2(g) 2CO2 (g)The equilibrium expression is the ratio of the product concentration to the reactant concentration.Each concentration is raised to a power as indicated by its coefficients in the equation.Keq= [CO2]^2[CO]^2 [O2]
5Now YOU TRYWhat is the equilibrium expression for the reaction 2 SO2 (g) + O2 2 SO3 (g)Answer :Keq= [SO3]^2[SO2]^2 [O2]
6Q FactsThe reaction quotient (Q) is used to determine if a reaction is at equilibrium.It is different from Keq because it uses numbers at the time the concentration measurement is taken.In order for a reaction to be at equilibrium Q would have to equal Keq because the quotient is the equilibrium expression using concentrations at a given time.
7Rules for QIf Q < Keq then the reaction will proceed to the right in the direction of the products because at the time of the reaction the product was too small and the reactants was too large; therefore the reaction will consume reactants and form products to reach equilibrium.If Q > Keq then the reaction will proceed to the left in the direction of the reactants because the reactants were too small and the products were too big. For the system to reach equilibrium reactants must be formed and products must be consumed.If Q = Keq the system is at equilibrium. There is no shift.
8Example of a Q equation COCl2 (g) CO (g) + Cl2 (g) Keq= 170 If the concentrations of CO and Cl2 are each 0.15 M and the concentration of COCl2 is 1.1 x 10^-3 M, is the reaction at equilibrium? If not, in which direction will it proceed ?Q= [CO] [Cl2] = (0.15) (0.15) = 20[COCl2] x 10^-3Q < Keq which means the reaction is not at equilibrium and it proceeds to the right.
9Now YOU tryA vial contains M NO2, and M N2O4. Calculate Q for the reaction 2 NO2 (g) N2O4 (g)Answer 13.3