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Welcome to Interactive Chalkboard Algebra 2 Interactive Chalkboard Copyright © by The McGraw-Hill Companies, Inc. Send all inquiries to: GLENCOE DIVISION Glencoe/McGraw-Hill 8787 Orion Place Columbus, Ohio 43240

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Splash Screen

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Contents Lesson 2-1Relations and Functions Lesson 2-2Linear Equations Lesson 2-3Slope Lesson 2-4Writing Linear Equations Lesson 2-5Modeling Real-World Data: Using Scatter Plots Lesson 2-6Special Functions Lesson 2-7Graphing Inequalities

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Lesson 1 Contents Example 1Domain and Range Example 2Vertical Line Test Example 3Graph Is a Line Example 4Graph Is a Curve Example 5Evaluate a Function

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Example 1-1a State the domain and range of the relation shown in the graph. Is the relation a function? The relation is {(1, 2), (3, 3), (0, –2), (–4, 0), (–3, 1)}. Answer: The domain is {–4, –3, 0, 1, 3}. The range is {–2, 0, 1, 2, 3}. Each member of the domain is paired with exactly one member of the range, so this relation is a function.

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Example 1-1b State the domain and range of the relation shown in the graph. Is the relation a function? Answer: The domain is {–3, 0, 2, 3}. The range is {–2, –1, 0, 1}. Yes, the relation is a function.

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Example 1-2a Transportation The table shows the average fuel efficiency in miles per gallon for light trucks for several years. Graph this information and determine whether it represents a function. Year Fuel Efficiency (mi/gal) 199520.5 199620.8 199720.6 199820.9 199920.5 200020.5 200120.4

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Example 1-2b Year Fuel Efficiency (mi/gal) 199520.5 199620.8 199720.6 199820.9 199920.5 200020.5 200120.4 Use the vertical line test. Notice that no vertical line can be drawn that contains more than one of the data points.

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Example 1-2c Answer: Yes, this relation is a function.

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Example 1-2d Health The table shows the average weight of a baby for several months during the first year. Graph this information and determine whether it represents a function. Age (months) Weight (pounds) 1 12.5 216 422 624 925 1226

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Example 1-2e Answer: Yes, this relation is a function.

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2 1 0 –1 yx Example 1-3a Graph the relation represented by Make a table of values to find ordered pairs that satisfy the equation. Choose values for x and find the corresponding values for y. 5 2 –1 –4 Then graph the ordered pairs. (–1, –4)(0, –1) (1, 2) (2, 5)

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Example 1-3b Find the domain and range. Since x can be any real number, there is an infinite number of ordered pairs that can be graphed. All of them lie on the line shown. Notice that every real number is the x -coordinate of some point on the line. Also, every real number is the y -coordinate of some point on the line. Answer:The domain and range are both all real numbers. (–1, –4) (0, –1) (1, 2) (2, 5)

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Example 1-3c Determine whether the relation is a function. This graph passes the vertical line test. For each x value, there is exactly one y value. (–1, –4) (0, –1) (1, 2) (2, 5) Answer:Yes, the equation represents a function.

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Example 1-3d a.Graph b.Find the domain and range. c.Determine whether the relation is a function. Answer: Answer:The domain and range are both all real numbers. Answer:Yes, the equation is a function.

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1 2 yx 0 –1 –2 Example 1-4a Make a table. In this case, it is easier to choose y values and then find the corresponding values for x. 2 1 2 5 (1, 0) (2, –1) (5, –2) Graph the relation represented by 5 (5, 2) (2, 1) Then sketch the graph, connecting the points with a smooth curve.

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Example 1-4b Find the domain and range. Every real number is the y -coordinate of some point on the graph, so the range is all real numbers. But, only real numbers that are greater than or equal to 1 are x -coordinates of points on the graph. (1, 0) (2, –1) (5, –2) (5, 2) (2, 1) Answer: The domain is. The range is all real numbers.

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You can see from the table and the vertical line test that there are two y values for each x value except x = 1. Example 1-4c Determine whether the relation is a function. (1, 0) (2, –1) (5, –2) (5, 2) (2, 1) 1 2 yx 0 –1 –2 2 1 2 5 5

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Example 1-4d Answer:The equation does not represent a function.

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Example 1-4e a.Graph b.Find the domain and range. c.Determine whether the relation is a function. Answer:The domain is {x | x –3}. The range is all real numbers. Answer: Answer:No, the equationdoes not represent a function.

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Example 1-5a Given, find Answer: Original function Substitute. Simplify.

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Example 1-5b Givenfind Original function Substitute. Multiply. Answer: Simplify.

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Example 1-5c Given, find Original function Substitute. Answer:

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Example 1-5d Givenand find each value. a. b. c. Answer: 6 Answer: 0.625 Answer:

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End of Lesson 1

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Lesson 2 Contents Example 1Identify Linear Functions Example 2Evaluate a Linear Function Example 3Standard Form Example 4Use Intercepts to Graph a Line

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Example 2-1a State whether is a linear function. Explain. Answer: This is a linear function because it is in the form

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Example 2-1b Answer:This is not a linear function because x has an exponent other than 1. State whether is a linear function. Explain.

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Example 2-1c State whether is a linear function. Explain. Answer:This is a linear function because it can be written as

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Example 2-1d State whether each function is a linear function. Explain. a. b. c. Answer: yes; Answer:No; x has an exponent other than 1. Answer:No; two variables are multiplied together.

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Example 2-2a Meteorology The linear function can be used to find the number of degrees Fahrenheit, f (C), that are equivalent to a given number of degrees Celsius, C. On the Celsius scale, normal body temperature is 37 C. What is normal body temperature in degrees Fahrenheit? Original function Substitute. Simplify. Answer:Normal body temperature, in degrees Fahrenheit, is 98.6 F.

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Example 2-2b There are 100 Celsius degrees between the freezing and boiling points of water and 180 Fahrenheit degrees between these two points. How many Fahrenheit degrees equal 1 Celsius degree? Answer: 1.8 F = 1 C Divide 180 Fahrenheit degrees by 100 Celsius degrees.

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Example 2-2c Meteorology The linear functioncan be used to find the distance d (s) in miles from a storm, based on the number of seconds s that it takes to hear thunder after seeing lightning. a.If you hear thunder 10 seconds after seeing lightning, how far away is the storm? b.If the storm is 3 miles away, how long will it take to hear thunder after seeing lightning? Answer: 2 miles Answer: 15 seconds

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Example 2-3a Writein standard form. Identify A, B, and C. Original equation Subtract 3x from each side. Multiply each side by –1 so that A 0. Answer: and

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Example 2-3b Writein standard form. Identify A, B, and C. Original equation Subtract 2y from each side. Multiply each side by –3 so that the coefficients are all integers. Answer: and

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Example 2-3c Writein standard form. Identify A, B, and C. Original equation Subtract 4 from each side. Divide each side by 2 so that the coefficients have a GCF of 1. Answer: and

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Example 2-3d Write each equation in standard form. Identify A, B, and C. a. b. c. Answer: and Answer:and Answer: and

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Example 2-4a Find the x -intercept and the y -intercept of the graph of Then graph the equation. The x -intercept is the value of x when The x -intercept is –2. The graph crosses the x -axis at (–2, 0). Original equation Substitute 0 for y. Add 4 to each side. Divide each side by –2.

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Example 2-4b The y -intercept is 4. The graph crosses the y -axis at (0, 4). Likewise, the y -intercept is the value of y when Original equation Substitute 0 for x. Add 4 to each side.

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Example 2-4c Use the ordered pairs to graph this equation. Answer:The x -intercept is –2, and the y -intercept is 4. (0, 4) (–2, 0)

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Example 2-4d Find the x -intercept and the y -intercept of the graph of Then graph the equation. Answer:The x -intercept is –2, and the y -intercept is 6.

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End of Lesson 2

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Lesson 3 Contents Example 1Find Slope Example 2Use Slope to Graph a Line Example 3Rate of Change Example 4Parallel Lines Example 5Perpendicular Line

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Example 3-1a Find the slope of the line that passes through (1, 3) and (–2, –3). Then graph the line. Slope formula and Simplify.

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Example 3-1b Graph the two ordered pairs and draw the line. (1, 3) Use the slope to check your graph by selecting any point on the line. Then go up 2 units and right 1 unit or go down 2 units and left 1 unit. This point should also be on the line. Answer:The slope of the line is 2. (–2, –3)

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Example 3-1c Find the slope of the line that passes through (2, 3) and (–1, 5). Then graph the line. Answer:The slope of the line is

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Example 3-2a Graph the line passing through (1, –3) with a slope of Graph the ordered pair (1, –3). Then, according to the slope, go down 3 units and right 4 units. Plot the new point at (5, –6). (1, –3) (5, –6) Draw the line containing the points.

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Example 3-2b Graph the line passing through (2, 5) with a slope of –3. Answer:

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Example 3-3a Communication Refer to the graph. Find the rate of change of the number of radio stations on the air in the United States from 1990 to 1998. Slope formula Substitute.

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Example 3-3b Simplify. Answer: Between 1990 and 1998, the number of radio stations on the air in the United States increased at an average rate of 0.225(1000) or 225 stations per year.

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Example 3-3c Computers Refer to the graph. Find the rate of change of the number of households with computers in the United States from 1984 to 1998. Answer: The rate of change is 2.9 million households per year.

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Example 3-4a Graph the line through (1, –2) that is parallel to the line with the equation The x -intercept is –2 and the y -intercept is 2. Use the intercepts to graph The line rises 1 unit for every 1 unit it moves to the right, so the slope is 1. Now, use the slope and the point at (1, –2) to graph the line parallel to (1, –2)(2, –1)

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Example 3-4b Graph the line through (2, 3) that is parallel to the line with the equation Answer:

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Example 3-5a Graph the line through (2, 1) that is perpendicular to the line with the equation The x -intercept is or 1.5 and the y -intercept is –1. Use the intercepts to graph 2x – 3y = 3 The line rises 1 unit for every 1.5 units it moves to the right, so the slope is or

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2x – 3y = 3 Example 3-5b Graph the line through (2, 1) that is perpendicular to the line with the equation The slope of the line perpendicular is the opposite reciprocal of or Start at (2, 1) and go down 3 units and right 2 units. (2, 1) (4, –2) Use this point and (2, 1) to graph the line.

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Example 3-5c Graph the line through (–3, 1) that is perpendicular to the line with the equation Answer:

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End of Lesson 3

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Lesson 4 Contents Example 1Write an Equation Given Slope and a Point Example 2Write an Equation Given Two Points Example 3Write an Equation for a Real-World Situation Example 4Write an Equation of a Perpendicular Line

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Example 4-1a Write an equation in slope-intercept form for the line that has a slope ofand passes through (5, –2). Slope-intercept form Simplify.

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Example 4-1b Add 3 to each side. Answer:The y -intercept is 1. So, the equation in slope-intercept form is

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Example 4-1c Write an equation in slope-intercept form for the line that has a slope ofand passes through (–3, –1). Answer:

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Example 4-2a Multiple-Choice Test Item What is an equation of the line through (2, –3) and (–3, 7) ? ABCDABCD Read the Test Item You are given the coordinates of two points on the line. Notice that the answer choices are in slope-intercept form.

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Example 4-2b Solve the Test Item First, find the slope of the line. Slope formula Simplify. The slope is –2. That eliminates choices B and C.

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Example 4-2c Then use the point-slope formula to find an equation. Point-slope form you can use either point for. Distributive Property Answer: D Subtract 3 from each side.

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Example 4-2d Answer:C Multiple-Choice Test Item What is an equation of the line through (2, 5) and (–1, 3) ? ACBDACBD

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Example 4-3a Sales As a part-time salesperson, Jean Stock is paid a daily salary plus commission. When her sales are $100, she makes $58. When her sales are $300, she makes $78. Write a linear equation to model this situation. Let x be her sales and let y be the amount of money she makes. Use the points (100, 58) and (300, 78) to make a graph to represent the situation.

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Example 4-3b Slope formula Simplify.

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Example 4-3c Now use the slope and either of the given points with the point-slope form to write the equation. Point-slope form Distributive Property Add 58 to each side. Answer:The slope-intercept form of the equation is

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The y -intercept of the line is 48. The y -intercept represents the money Jean would make if she had no sales. Thus, $48 is her daily salary. Example 4-3d Answer:Ms. Stocks daily salary is $48, and she makes a 10% commission. What are Ms. Stocks daily salary and commission rate? The slope of the line is 0.1. Since the slope is the coefficient of x, which is her sales, she makes 10% commission.

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Example 4-3f How much would Jean make in a day if her sales were $500? Find the value of y when Use the equation you found in Example 3a. Replace x with 500. Simplify. Answer:She would make $98 if her sales were $500.

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Example 4-3h Sales The student council is selling coupon books to raise money for the Humane Society. If the group sells 200 books, they will receive $150 dollars. If they sell 500 books, they will make $375. a.Write a linear equation to model this situation. b.Find the percentage of the proceeds that the student council receives. c.If they sold 1000 books, how much money would they receive to donate to the Humane Society? Answer: Answer: 75% Answer: $750

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Example 4-4a Write an equation for the line that passes through (3, –2) and is perpendicular to the line whose equation is The slope of the given line is –5. Since the slopes of perpendicular lines are opposite reciprocals, the slope of the perpendicular line is Use the point-slope form and the ordered pair (3, –2) to write the equation.

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Example 4-4b Point-slope form Distributive Property Subtract 2 from each side. Answer: An equation of the line is

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Example 4-4c Write an equation for the line that passes through (3, 5) and is perpendicular to the line whose equation is Answer:

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End of Lesson 4

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Lesson 5 Contents Example 1Draw a Scatter Plot Example 2Find and Use a Prediction Equation

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Example 5-1a Education The table below shows the approximate percent of students who sent applications to two colleges in various years since 1985. Make a scatter plot of the data. 131415 1820 Percent 15129630 Years Since 1985 Source: U.S. News & World Report Graph the data as ordered pairs, with the number of years since 1985 on the horizontal axis and the percentage on the vertical axis.

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Example 5-1b Safety The table below shows the approximate percent of drivers who wear seat belts in various years since 1994. Make a scatter plot of the data. 7371686964615857 Percent 76543210 Years Since 1994 Source: National Highway Traffic Safety Administration

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Example 5-2a Education The table and scatter plot below show the approximate percent of students who sent applications to two colleges in various years since 1985. Draw a line of fit for the data. How well does the line fit the data? 131415 1820 Percent 15129630 Years Since 1985 Source: U.S. News & World Report The points (3, 18) and (15, 13) appear to represent the data well. Draw a line through these two points.

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Example 5-2b Education The table and scatter plot below show the approximate percent of students who sent applications to two colleges in various years since 1985. Draw a line of fit for the data. How well does the line fit the data? 131415 1820 Percent 15129630 Years Since 1985 Source: U.S. News & World Report Answer:Except for (6, 15), this line fits the data fairly well.

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Example 5-2c Find a prediction equation. What do the slope and y -intercept indicate? Find an equation of the line through (3, 18) and (15, 13). Begin by finding the slope. Slope formula Substitute. Simplify.

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Example 5-2d Point-slope form Distributive Property Add 18 to each side. Answer:One prediction equation is The slope indicates that the percent of students sending applications to two colleges is falling at about 0.4% each year. The y -intercept indicates that the percent in 1985 should have been about 19%.

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Example 5-2e Predict the percent in 2010. The year 2010 is 25 years after 1985, so use the prediction equation to find the value of y when Prediction equation Simplify. Answer:The model predicts that the percent in 2010 should be about 9%.

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Example 5-2f How accurate is this prediction? Answer:The fit is only approximate, so the prediction may not be very accurate.

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Example 5-2g Safety The table and scatter plot show the approximate percent of drivers who wear seat belts in various years since 1994. a.Draw a line of fit for the data. How well does the line fit the data? 7371686964615857 Percent 76543210 Years Since 1994 Source: National Highway Traffic Safety Administration Answer:Except for (4, 69), this line fits the data very well.

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Example 5-2h b.Find a prediction equation. What do the slope and y -intercept indicate? Answer:Using (1, 58) and (7, 73), an equation is y = 2.5x + 55.5. The slope indicates that the percent of drivers wearing seatbelts is increasing at a rate of 2.5% each year. The y -intercept indicates that, according to the trend of the rest of the data, the percent of drivers who wore seatbelts in 1994 was about 56%.

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Example 5-2i c.Predict the percent of drivers who will be wearing seat belts in 2005. d.How accurate is the prediction? Answer: 83% Answer:Except for the outlier, the line fits the data very well, so the predicted value should be fairly accurate.

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End of Lesson 5

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Lesson 6 Contents Example 1Step Function Example 2Constant Function Example 3Absolute Value Functions Example 4Piecewise Function Example 5Identify Functions

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Example 6-1a Psychology One psychologist charges for counseling sessions at the rate of $85 per hour or any fraction thereof. Draw a graph that represents this solution. Explore The total charge must be a multiple of $85, so the graph will be the graph of a step function. Plan If the session is greater than 0 hours, but less than or equal to 1 hour, the cost is $85. If the time is greater than 1 hour, but less than or equal to 2 hours, then the cost is $170, and so on.

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Example 6-1b Solve Use the pattern of times and costs to make a table, where x is the number of hours of the session and C(x) is the total cost. Then draw the graph. 425 340 255 170 85 C(x)x

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Example 6-1c Answer: Examine Since the psychologist rounds any fraction of an hour up to the next whole number, each segment on the graph has a circle at the left endpoint and a dot at the right endpoint.

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Example 6-1d Sales The Daily Grind charges $1.25 per pound of meat or any fraction thereof. Draw a graph that represents this situation. Answer:

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Example 6-2a Graph For every value of The graph is a horizontal line. g(x) = –3 xg(x)g(x) –2–3 0 1 0.5–3 Answer:

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Example 6-2b Graph Answer:

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Example 6-3a Graphandon the same coordinate plane. Determine the similarities and differences in the two graphs. Find several ordered pairs for each function. x| x – 3 | 03 12 21 30 41 52 x| x + 2 | –42 –31 –20 –11 02 13

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Example 6-3b Graph the points and connect them. Answer: The domain of both graphs is all real numbers. The range of both graphs is The graphs have the same shape, but different x -intercepts. The graph of g (x) is the graph of f (x) translated left 5 units.

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Example 6-3c Graphandon the same coordinate plane. Determine the similarities and differences in the two graphs. The domain of both graphs is all real numbers. The graphs have the same shape, but different y -intercepts. The graph of g (x) is the graph of f (x) translated up 5 units. Answer: The range of isThe range of is

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Example 6-4a Step 1Graph the linear function for Since 3 satisfies this inequality, begin with a closed circle at (3, 2). GraphIdentify the domain and range.

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Example 6-4b Step 2Graph the constant function Since x does not satisfy this inequality, begin with an open circle at (3, –1) and draw a horizontal ray to the right. GraphIdentify the domain and range.

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Example 6-4c GraphIdentify the domain and range. Answer: The function is defined for all values of x, so the domain is all real numbers. The values that are y -coordinates of points on the graph are all real numbers less than or equal to –2, so the range is

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Example 6-4d GraphIdentify the domain and range. Answer:The domain is all real numbers. The range is

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Example 6-5a Determine whether the graph represents a step function, a constant function, an absolute value function, or a piecewise function. Answer:Since this graph consists of different rays and segments, it is a piecewise function.

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Example 6-5b Determine whether the graph represents a step function, a constant function, an absolute value function, or a piecewise function. Answer:Since this graph is V-shaped, it is an absolute value function.

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Example 6-5c Determine whether each graph represents a step function, a constant function, an absolute value function, or a piecewise function. a.b. Answer: constant function Answer: absolute value function

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End of Lesson 6

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Lesson 7 Contents Example 1Dashed Boundary Example 2Solid Boundary Example 3Absolute Value Inequality

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Example 7-1a Graph The boundary is the graph ofSince the inequality symbol is <, the boundary will be dashed. Use the slope-intercept form,

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Example 7-1b Graph Test (0, 0). Original inequality true Shade the region that contains (0, 0).

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Example 7-1c Graph Answer:

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Example 7-2a Education The SAT has two parts. One tutoring company advertises that it specializes in helping students who have a combined score on the SAT that is 900 or less. Write an inequality to describe the combined scores of students who are prospective tutoring clients. Let x be the first part of the SAT and let y be the second part. Since the scores must be 900 or less, use the symbol.

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Example 7-2b The2 nd partare less than 1 st partandtogether or equal to900. xy 900 Answer:

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Example 7-2c Graph the inequality. Since the inequality symbol is, the graph of the related linear equation is solid. This is the boundary of the inequality.

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Example 7-2d Graph the inequality. Test (0, 0). Original inequality true

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Example 7-2e Graph the inequality. Shade the region that contains (0, 0). Since the variables cannot be negative, shade only the part in the first quadrant.

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Example 7-2f Does a student with a verbal score of 480 and a math score of 410 fit the tutoring companys guidelines? The point (480, 410) is in the shaded region, so it satisfies the inequality. Answer:Yes, this student fits the tutoring companys guidelines.

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Example 7-2g Class Trip Two social studies classes are going on a field trip. The teachers have asked for parent volunteers to also go on the trip as chaperones. However, there is only enough seating for 60 people on the bus. a.Write an inequality to describe the number of students and chaperones that can ride on the bus. Answer:

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Example 7-2h b.Graph the inequality. c.Can 45 students and 10 chaperones go on the trip? Answer: Answer:yes

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Example 7-3a Graph Since the inequality symbol is, the graph of the related equation is solid. Graph the equation. Test (0, 0). Original inequality true Shade the region that contains (0, 0).

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Example 7-3b Graph Answer:

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End of Lesson 7

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Algebra2.com Explore online information about the information introduced in this chapter. Click on the Connect button to launch your browser and go to the Algebra 2 Web site. At this site, you will find extra examples for each lesson in the Student Edition of your textbook. When you finish exploring, exit the browser program to return to this presentation. If you experience difficulty connecting to the Web site, manually launch your Web browser and go to www.algebra2.com/extra_examples.

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