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Selection Process If … then … else...
Condition Process 2 Process 1 Y
Condition Process 1 Process 3 N
Condition Process 2 Process 1 Process 3 Y (then) N (else) If … then … else...
n>=0 Y Readln(n) Writeln(‘Positive’) Readln(n); If n >= 0 then Writeln(‘Positive’)
n>=0 N Readln(n) Writeln(‘Negative’) else Writeln(‘Negative’)
n>=0 Y Readln(n) Writeln(‘Positive’) N Writeln(‘Negative’) Readln(n); If n >= 0 then Writeln(‘Positive’) else Writeln(‘Negative’);
Selection Process If … then …
Condition Process 2 Process 1 Y If (Condition is T) then Process 2
Condition Process 1 N Process 2 If (Condition is T) then Process 2
EXEMPLO DE REMOÇÃO ARVORE if (T = nil) then begin writeln ('ELEMENTO NAO ENCONTRADO NA ARVORE'); end else begin if (X.ch < T^.elem.ch) then.
MULT. INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
1 ln(x) e x Approximating functions Elementary Functions.
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Weeks – 02/ 1 Introduction to flowcharts symbols for selection and looping process.
THE WELL ORDERING PROPERTY Definition: Let B be a set of integers. An integer m is called a least element of B if m is an element of B, and for every x.
Process(clk25, rst) begin if rst= '0' then div '0'); elsif rising_edge(clk25) then div<= div + 1; end if; end process; clk_in<= div(div'left); process(clk_in,
Working With Algorithm and Flowcharts Understanding their practicality.
Maximum ??? Minimum??? How can we tell? and decreasing just to the right of c, then f has a local minimum at c If f is increasing just to the left of a.
Relational and Equality Operators Table 4-1. Sample Conditions Table 4-2.
The card trick 21 cards are taken from which viewer selects one card The 21 cards are divided into 3 piles Viewer identifies pile in which selected card.
Exponents power base exponent. Warm-Up Find the value of each expression. 1.) 5 – ) (5 – 1) 3 3.) 4 (3 + 2) 4.) 10 ÷ 2 – 3 5.) 10 + (2 + 4) ÷ 4.
Question 1) If a good is a Giffen good, it must be an inferior good A) True B) False Question 2) If a good is an inferior good, it must be a Giffen good.
Selection Feature of C: Decision making statements: It allow us to take decisions as to which code is to be executed next. Since these statements control.
4.4 Rational Root Theorem. Rational Root Theorem give direction in testing possible zeros. Let a 0 x n + a 1 x n-1 + …a n-1 x + a n = 0 represent a polynomial.
Bellman-Ford algorithm Page 2 Bellman-Ford algorithm Computes single-source shortest path in a weighted digraph. The faster Dijkstras algorithm.
Grammatik, sprog og parsing Relationerne imellem sprog If While Foreach Try Catch 1Rasmus D. Lehrmann.
Copyright © 2007 Pearson Education, Inc. Slide R-2 Chapter R: Reference: Basic Algebraic Concepts R.1Review of Exponents and Polynomials R.2Review of.
K c and equilibrium. What does K c signify? If K c = 1 then the position of equilibrium is half way between products and reactants If K c > 1 then the.
Основни задачи с файлове. 1. Създаване на файл с фиксиран брой записи Program p1; Type Fl=file of real; Var F:Fl; T:real; I,N:integer; Begin Write(N=);
Chapter 12: Laws of Thermo. Law of Conservation of energy Change in U (internal energy) = Q – W. Q = amount of heat added so this is positive when heat.
We use: There is……… when just one. There are……..for more than one.
Increasing and Decreasing Functions AP Calculus – Section 3.3.
Introduction to Radicals Radical Expressions Finding a root of a number is the inverse operation of raising a number to a power. This symbol is the radical.
Our company received the delegation of 17 libraries from North America.
Starter 1 (1-D) A car travels 100 km from city A to city B. If the first half of the distance is driven at 50 km/h and the second half is driven at 100.
Slope of a Line Slope basically describes the steepness of a line Free powerpoints at
Warm up – Solve by Taking Roots. Skills Check – Solve by Taking Roots.
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