Download presentation

Presentation is loading. Please wait.

1
**Recall Evaluate an Expression**

Section 10-2 Exploring Quadratic Graphs SPI 23E: find the solution to a quadratic equation given in standard form SPI 23F: select the solution to a quadratic equation given a graphical representation Objectives: Graph quadratic functions Recall Evaluate an Expression –b 2a Evaluate the expression for a = –6 and b = 4. –b 2a –4 2(-6) –4 -12 1 3 = = = Recall Role of 'a' and 'c' Form of a Quadratic Equation: ax2 + bx + c Coefficient (a) affects the width of the parabola Constant (c) affects the movement up or down

2
**Role of ‘b’ in a Quadratic Function**

Coefficient (b) affects the position of axis of symmetry vertex moves right or left axis of symmetry changes equation of axis of symmetry is x =

3
**Explore the Role of ‘b’ when Graphing a Quadratic**

Graph the quadratic function y = 2x2 + 4x – 3. Find the equation of the axis of symmetry. Substitute values into x = Find the coordinates of the vertex using the x value. Substitute x = -1 into the equation to find corresponding y value y = 2x2 + 4x – 3. = 2(-1)2 + 4(-1) – 3 = 2 – 4 – 3 = -5 Coordinates of the vertex is (-1, -5)

4
**Explore the Role of ‘b’ when Graphing a Quadratic**

Graph the quadratic function y = 2x2 + 4x – 3 Vertex is (-1, -5); axis of symmetry is x = -1 3. Find two other points on the graph. x y = 2x2 + 4x - 3 (x, y) -1 VERTEX from step 2 (-1, -5) y = 2 (0)2 +4(0) - 3 = -3 (0, -3) y = 2 (1)2 +4(1) - 3 = 3 1 (1, 3) 3. Reflect points over axis of symmetry 4. Connect with a curved line.

5
**Will the curve open down or up? (look at the coefficient of the t2) **

Aerial fireworks carry “stars,” which when ignited are projected into the air. Suppose a particular star is projected from an aerial firework at a starting height of 610 ft with an initial upward velocity of 88 ft/s. How long will it take for the star to reach its maximum height? How far above the ground will it be? The equation h = –16t2 + 88t gives the height of the star h in feet at time t in seconds. Will the curve open down or up? (look at the coefficient of the t2) Will the vertex be a max or min point? Since the coefficient of t 2 is negative, the curve opens downward, and the vertex is the maximum point. Step 1. Find the x-coordinate of the vertex. b 2a – = –88 2(–16) 2.75 After 2.75 seconds, the star will be at its greatest height. Step 2: Find the h-coordinate of the vertex. h = –16(2.75)2 + 88(2.75) Substitute 2.75 for t. h = Simplify using a calculator. The maximum height of the star will be about 731 ft.

Similar presentations

OK

5 – 1 Graphing Quadratic Functions Day 2 Objective: Use quadratic functions to solve real – life problems.

5 – 1 Graphing Quadratic Functions Day 2 Objective: Use quadratic functions to solve real – life problems.

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on stepping stone to success Free ppt on albert einstein Ppt on philosophy of education Ppt on unity in diversity slogans Ppt on chapter #3 drainage stone Ppt on exterior angle theorem Download ppt on ghosts and spirits Ppt on law against child marriage laws Ppt on collective nouns for grade 3 Ppt on power sharing in india