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Published byPayton Edrington Modified over 2 years ago

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4 Theorem:Proof: What shall we do for an undirected graph?

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7 p 0 (s)=1 p 1 (a)=0.5

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Note that if the right answer is ‘NO’, we clearly answer ‘NO’. Hence, this random walk algorithm has one-sided error. Such algorithms are called “Monte-Carlo” algorithms. Complexi ty 13

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14 st... The probability we head in the right direction is 1/d s But every time we get here, we get a second chance!

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Since expectedly we return to each vertex within|E|/d i steps The walk expectedly heads in the right direction within 2|E| steps By linearity of the expectation, it is expected to reach t within d(s,t) 2|E| 2|V| |E| steps. 15 Complexity

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1. Run the random walk from s for 2|V| |E| steps. 2. If node t is ever visited, answer “there is a path from s to t”. 3. Otherwise, reply “there is probably no path from s to t”. 16 Complexity

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Theorem: The above algorithm - uses logarithmic space - always right for ‘NO’ instances. - errs with probability at most ½ for ‘YES’ instances. 17 Complexity To maintain the current position we only need log|V| space Markov: Pr(X>2E[X])<½ PAP

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We explored the undirected connectivity problem. We saw a log-space randomized algorithm for this problem. We used an important technique called random walks. 18 Complexity

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