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Graphical Analysis of Linear Motion. A car travels along a road at a constant velocity of 10. m/s time (s) position (m) 0 0 1 10 2 20 3 30.

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Presentation on theme: "Graphical Analysis of Linear Motion. A car travels along a road at a constant velocity of 10. m/s time (s) position (m) 0 0 1 10 2 20 3 30."— Presentation transcript:

1 Graphical Analysis of Linear Motion

2 A car travels along a road at a constant velocity of 10. m/s time (s) position (m)

3 slope = Δx/Δt ΔtΔt ΔxΔx = 20 m/2 s = 10 m/s velocity

4 position vs. time graph to find displacement: to find velocity: subtract values from graph find slope if straight line acceleration = 0

5 Displacement for 1 st 3 seconds: 30 m area under graph slope:0acceleration

6 v vs. t graph to find displacement: to find velocity: to find acceleration: find area read graph find slope

7 Object dropped from a tall building (use g = 10 m/s 2 ) time (s) position (m) x = x 0 + v 0 t + ½ at 2 x 0 = 0; v 0 = 0

8 2 s: slope of tangent line slope = 20/1 = 20 m/s

9 time (s) velocity (m/s) v = v 0 + at

10 2 s:slope 10 m/s 2 displacement for 1 st 3 s:area Δx = 45 m

11 area:30 m/s= Δv

12 Graphs (vs. time) position velocityacceleration slope area

13 If acceleration is positive (constant); x 0 = 0; v 0 = 0 x = ½ at 2

14 To produce a straight-line graph: slope = ½ a also: t 2 vs. x, x vs. t, t vs. x

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20 Graphs of x, v, a


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