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Sinusoidal Nature of SHM
SHM and Uniform Circular Motion
θ x = A cos θ A ω = θ/t x = A cos(ωt) ω = 2П/T = 2Пf
At what time is there: max. positive acceleration max. negative acceleration max. positive velocity max. negative velocity Equation: y t y = A sin (ωt) ω =2π/T 3T/4 T/4 0 & T T/2
Period of Mass on Spring Compare to circular motion with same T v = Δx/t v 0 = 2ПA/T T = 2ПA/v 0 ½ mv 0 2 = ½ kA 2 v 0 = A (k/m)T = 2П (m/k)
To double the period: change in m: 4 times change in k: ¼ as large
1.To arrive at the relationship between displacement, velocity and acceleration for a system in SHM 2.To be able calculate the magnitude & direction of.
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