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Published byMackenzie Rowe Modified over 2 years ago

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Newtons Universal Law of Gravitation

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Factors Affecting the Gravitational Force mass distance

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Mass m1m1 m2m2 force varies directly with masses F g α m 1 m 2 decrease mass forcedecreased

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Distance r increase r force decreased

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Force varies inversely with distance squared F g α 1/r 2

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m 1 m 2 F g α r 2 FgFg m 1 m 2 /r 2 slope = G F g α m 1 m 2 F g α 1/r 2

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G = 6.67 x N m 2 /kg 2

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A 1000 kg car and a 2000 kg truck are 0.50 m apart. Gravitational force:5.3 x N

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Computing mass of Earth radius of Earth: 6.37 x 10 6 m 1.00 kg mass has a weight of 9.81 N mass of Earth:5.97 x kg

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2F 4F

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¼ F 4F

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F

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g gravitational field – weight per mass wtg F g g = = mass m G M = r 2 M = planet mass

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Effect of changing variables GM g = r 2 if M doubles: if r doubles: if M & r doubles: if r becomes ½: 2g ¼ g ½ g 4g

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Mars mass: 11% mass of Earth radius: 53% radius of Earth gravitational field for Mars? 0.39 g E = 3.84 N/kg

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MM M s s s Net gravitational force on bottom mass? 3 GM 2 /s 2

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G m 1 m 2 F g = r 2 = weight What would happen to your weight if: Earth had twice mass but the same radius: Earth had twice radius but same mass: Twice weight ¼ weight

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What is g at top of Mt. Everest (8848 m elevation)? 9.77 N/kg = 9.77 m/s 2

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