Presentation on theme: "Athlete or Machine? A STEM Resource"— Presentation transcript:
1Athlete or Machine? A STEM Resource www.raeng.org.uk/athleteormachine
2Bob Skeleton 1500m track 150 m vertical drop 80 mph + 33 – 43 kg sled Amy Williams - Olympic gold 2010Great contextA STEM activity
3Investigate the ‘big question’: athlete or machine? Practical activities and testingMathematics activitiesScience activitiesEngineer/athlete videoStudent ledIndependent investigationHigher level thinkingScheme of work for STEM day or STEM club
4Make a 1:5 bob skeleton sled 90 minute makeCheap materialsBasic tools and equipment
6Make some timing gates (if you have the time) Investigate launch pressure consistency
7Factors Weight The athlete’s shape The athlete’s position Aerodynamic liftSteeringClothing and equipmentStartingCornersErgonomics (how the body fits a product)Track incline (the slope down the length of the track)Friction on the iceAerodynamic drag (air resistance)Tuning the characteristics of the skeletonMaterial choiceSled runners
8Potential Energy (PE) = m x g x h Kinetic Energy (KE) = ½ x m x v2 Energy transferPotential Energy (PE) = m x g x hChange in PE for our athlete and sled =Joules (J)Kinetic Energy (KE) = ½ x m x v20.5 x 97 kg x (40.23 x 40.23) = JWhy isn’t the all of the athlete and sled’s potential energy transferred into kinetic energy?Mass (m) of athlete and sled = 97kgVertical drop of track (h) = 152m1450m(diagram not to scale)Gravity (g) = 9.81 m/s2Amy Williams max speedMax speed if all PE transferred into KEThe line graph above shows that if all the potential energy (PE) were to be transformed into kinetic energy (KE) then the athlete and sled would need to travel at 55 m/s (122 miles per hour) to reach a KE figure of J.However, the 2010 bob skeleton Olympic champion, Amy Williams, is known to travel at a maximum speed of 90 mph (40.23 m/s).Our simple analysis of the energy transfer over estimates the maximum speed of the athlete and sled by 15 m/s or 37% because it neglects the affects of aerodynamic drag and friction.
9aerodynamic drag (air resistance) Which two forces resist the forward movement of the athlete and sled down the track?frictionaerodynamic drag (air resistance)
10Friction force A little friction A lot of friction rubber / concrete Friction is a force that resists the movement of two surfaces against each other.Which combinations provide a lot or a little friction?rubber / concretefelt / woodrubber / rubbersteel / icesteel / woodA little frictionA lot of frictionrubber / rubber (1.16)steel / ice (0.03)rubber / concrete (1.02)steel / wood ( )felt / wood (0.22)
11Calculating friction force Friction is a force that resists the movement of two surfaces against each other.We can investigate the affect friction has on the model bob skeleton sled using the following equation. Force is measured in Newtons (N).Ff = x m x g= Mu, the coefficient of friction.m = Mass (kg).g = The acceleration due to the gravity, which is 9.81 m/s2.
12Calculating friction force Ff = x m x gWhat is the friction force acting on the runners of a bob skeleton sled and athlete with the combined mass of 110 kg (athlete = 75 kg, sled = 35 kg)?Ff = 0.03 x 110 x 9.81 = N= Mu, the coefficient of friction (steel on ice = 0.03).m = Mass (kg).g = The acceleration due to the gravity, which is 9.81 m/s2.
13Calculating friction force Ff = x m x gAmy Williams Kristan BromleyAthlete mass 63 kg 72 kg (+15%)Sled mass 29 kg 29 kgTotal mass 92 kg kg (+10%)What effect does a 15% increase in athlete mass have on friction?= Mu, the coefficient of friction (steel on ice = 0.03). m = Mass (kg).g = The acceleration due to the gravity, which is 9.81 m/s2.Friction forceAmy Williams0.03 x 92 x = 27 NKristan Bromley0.03 x 101 x 9.81 = 29 NIncrease in friction = new amount - original amount x 100original amountDifference in friction force between Amy Williams and Kristan Bromley is 7%
14What effect does a 15% increase in athlete mass have on friction? Friction force (Ff) x m x gAmy Williams x 92 x = 27 NKristan Bromley x 101 x 9.81 = 29 N (+7%)A 15% increase in athlete mass doesn’t result in a 15%increase in friction. This might be significant for the engineer.= Mu, the coefficient of friction (steel on ice = 0.03). m = Mass (kg).g = The acceleration due to the gravity, which is 9.81 m/s2.Friction forceAmy Williams0.03 x 92 x = 27 NKristan Bromley0.03 x 101 x 9.81 = 29 NIncrease in friction = new amount - original amount x 100original amountDifference in friction force between Amy Williams and Kristan Bromley is 7%
15Aerodynamic drag force The resistance provided by the air passing over a shape is a force called aerodynamic drag.Which shapes have a higher or lower coefficient of drag?Lower CDHigher CDCD = 0.42CD = 1.05CD = 0.47CD = 0.5
16Calculating drag force The resistance provided by air passing over the sled is a force called aerodynamic drag.FDRAG = ½ x x CD x Af x V2= DensityCD = Drag coefficientAf = Frontal areaV2 = Velocity= 1000 kg/m3= kg/m3CD = 0.47Af = m2CD = 1.05
17Calculating drag force What is the drag force acting on the athlete and sled as they travel down the track at 5 m/s?FDRAG = ½ x x CD x Af x V2FDRAG = 0.5 x 1.2 x 0.45 x x 25 = 0.94 N= 1.2 kg/m3 (density of air)CD = (drag coefficient of athlete and sled)Af = m2 (frontal area of athlete and sled)V2 = 5 m/s (velocity - 5 m/s = mph)
18Calculating drag force FDRAG = ½ x x CD x Af x V2FDRAG = 0.5 x 1.2 x 0.45 x x 25 (1) = 0.94 NWhat happens to drag force if you increase frontal area by 15 %?FDRAG = 0.5 x 1.2 x 0.45 x x 25 =What happens to drag force when the velocity increases by 15 %?FDRAG = 0.5 x 1.2 x 0.45 x x 33 (2) =What happens when frontal area and velocity increase?FDRAG = 0.5 x 1.2 x 0.45 x x 33 (2) = = density of air CD = drag coefficient of athlete and sled Af = frontal area of athlete and sledV2 = velocity - 5 m/s = mph(1) 5 m/s (2) 5.75 m/s1.08 N (+15%)1.24 N (+31 %)An increase in frontal area has a bigger impact on the forces acting against the athlete and sled than friction.1.43 N (+52 %)
19TASKS1. In your groups complete the activities, tasks and questions in the booklets (10 min)2. In your groups discuss the questions:Athlete or Machine? Which is more important in the bob skeleton event?What could be done to reduce friction and drag?(Make sure you can justify your answers)3. Choose a spokesperson who will communicate your group’s answer to the rest of the class.4. Check your answers against Kristan Bromley’s (2008 World Skeleton Champion and engineer).Kristan Bromley video clips:THE PARTS THAT MAKE A BOB SKELETON 22:34